PRINCIPLES OF INSTRUMENTAL ANALYSIS
PRINCIPLES OF INSTRUMENTAL ANALYSIS
7th Edition
ISBN: 9789353506193
Author: Skoog
Publisher: CENGAGE L
Question
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Chapter 27, Problem 27.26QAP
Interpretation Introduction

Interpretation:

Percentages of each component should be calculated.

Concept introduction:

Area normalization method is used in quantitative analysis of compounds in chromatography. In this method of quantification, complete elution of all analytes in the sample is required. Following formulas are required for the calculation.

Correctedarea=Relativearea×RelativedetectorresponsePercentageofthecompound=CorrectedareaofinterestedcompoundTotalcorrectedarea×100%

Expert Solution & Answer
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Answer to Problem 27.26QAP

PercentageofthecompoundA=19.1%PercentageofthecompoundB=12.5%PercentageofthecompoundC=37.8%PercentageofthecompoundD=18.5%PercentageofthecompoundE=11.9%

Explanation of Solution

Given information:

Compound Relative peak area Relative detector response
A 32.5 0.70
B 20.7 0.72
C 60.1 0.75
D 30.2 0.73
E 18.3 0.78

Corrected areas of compound can be calculated as follows.

CorrectedareaA=Relativearea×Relativedetectorresponse=32.5×0.70=22.75CorrectedareaB=Relativearea×Relativedetectorresponse=20.7×0.72=14.90CorrectedareaC=Relativearea×Relativedetectorresponse=60.1×0.75=45.08CorrectedareaD=Relativearea×Relativedetectorresponse=30.2×0.73=22.05CorrectedareaE=Relativearea×Relativedetectorresponse=18.3×0.78=14.27Totalcorrectedarea=22.75+14.9+45.08+22.05+14.27=119.05

Now, the percentage of compound can be calculated as follows:

PercentageofthecompoundA=CorrectedareaofinterestedcompoundTotalcorrectedarea×100%=22.75119.05×100%=19.1%PercentageofthecompoundB=CorrectedareaofinterestedcompoundTotalcorrectedarea×100% =14.9119.05×100% =12.5%

Or,

PercentageofthecompoundC=CorrectedareaofinterestedcompoundTotalcorrectedarea×100% =45.08119.05×100% =37.8%PercentageofthecompoundD=CorrectedareaofinterestedcompoundTotalcorrectedarea×100% =22.05119.05×100% =18.5%

Also,

PercentageofthecompoundE=CorrectedareaofinterestedcompoundTotalcorrectedarea×100% =14.27119.05×100% =11.9%

Conclusion

Thus,

PercentageofthecompoundA=19.1%PercentageofthecompoundB=12.5%PercentageofthecompoundC=37.8%PercentageofthecompoundD=18.5%PercentageofthecompoundE=11.9%

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