Understanding Motor Controls
3rd Edition
ISBN: 9781305498129
Author: Stephen L. Herman
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 27, Problem 1RQ
To determine
Identify why and which voltage must be used for the dual voltage motor to be used for part winding starting.
Expert Solution & Answer
Explanation of Solution
If a dual voltage 240/480V motor is used for a part winding starting, then the low voltage setting must be used. This is because, since only one winding is connected to the power line, the high current due to high voltage supplied causes overheating of the windings.
Hence, 240V must be used for part winding starting.
Want to see more full solutions like this?
Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
۲/۱
: +0
العنوان
seoni
4) 1 Mg (dry weight) of a non-porous
solid is dried under constant drying
conditions with an air
velocity of 0.75 m/s parallel to the drying
surface. The area of drying surface is 55
m2
If initial
rate of drying is 0.3 g/m2
s, how long it will take to dry a material
from 0.15 to 0.025 kg water/kg
dry solid? The critical moisture content
is 0.125 and the equilibrium moisture is
negligible.
The falling rate of drying is linear
in moisture content. If air velocity
increases to 4 m/s, what
will be the anticipated saving in drying
time?
0
osther
14.23. A double-effect forward-feed
evaporator is required to give a product
consisting of 30 per cent crystals and a
mother liquor containing 40 per cent by
mass of dissolved solids. Heat transfer
coefficients are 2.8 and 1.7 kW/m² K in the
first and second effects respectively. Dry
saturated steam is supplied at 375 kN/m²
and the condenser operates at 13.5 kN/
m².
(a) What area of heating surface is
required in each effect assuming the
effects are identical, if the feed rate is 0.6
kg/s of liquor, containing 20 per cent by
mass of dissolved solids, and the feed
temperature is 313 K?
(b) What is the pressure above the boiling
liquid in the first effect?
The specific heat capacity may be
taken as constant at 4.18 kJ/kg K. and
the effects of boiling-point rise and of
hydrostatic head may be neglected.
O
O
5) A 100 kg batch of granular solids
containing 30% moisture is to be dried in
a tray drier to
15.5% by passing a current of air at 350
K tangentially across its surface at a
velocity of 1.8
m/s. If the constant rate of drying under
these conditions is 0.7 g/s m2
and the critical moisture
content is 15%, calculate the
approximate drying time. Assume the
drying surface to be 0.03
m2
/kg dry mass.
O
Chapter 27 Solutions
Understanding Motor Controls
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Solve for v and Iarrow_forwardG = 0.350MPa, P = 900N, a=20mm, b=50mm, c=80mmarrow_forward[20 Points] Use Method of Sections to draw the shear-force and bending-moment diagrams for the simply supported beam shown. Determine the maximum bending moment that occurs in the span. 1.5 kN/m 4 m 2 m Carrow_forward
- 14.10. A liquor containing 15 per cent solids is concentrated to 55 per cent solids in a double-effect evaporator. operating at a pressure in the second effect of 18 kN/m². No crystals are formed. The flowrate of feed is 2.5 kg/ s at 375 K with a specific heat capacity of 3.75 kJ/kg K. The boiling-point rise of the concentrated liquor is 6 deg K and the steam fed to the first effect is at 240 kN/ m². The overall heat transfer coefficients in the first and second effects are 1.8 and 0.63 kW/m²K. respectively. If the heat transfer area is to be the same in each effect, what areas should be specified? D Aarrow_forward14.9. A forward feed double-effect vertical evaporator, with equal heating areas in each effect, is fed with 5 kg/s of a liquor of specific heat capacity of 4.18 kJ/kg K. and with no boiling point rise, so that 50 per cent of the feed liquor is evaporated. The overall heat transfer coefficient in the second effect is 75 per cent of that in the first effect. Steam is fed at 395 K and the boiling point in the second effect is 373 K. The feed is heated by an external heater to the boiling point in the first effect. It is decided to bleed off 0.25 kg/s of vapour from the vapour line to the second effect for use in another process. If the feed is still heated to the boiling point of the first effect by external means, what will be the change in steam consumption of the evaporator unit? For the purpose of calculation, the latent heat of the vapours and of the steam may both be taken as 2230 kJ/kg Ад Oarrow_forwardcorrect the shaft misalignment in a cars transmission system, determine the offset distance required to correct the shaft misalignment of 4 degrees in a rotating system. shaft diameter is 4cm.arrow_forward
- 14.14. A three-stage evaporator is fed with 1.25 kg/s of a liquor which is concentrated from 10 to 40 per cent solids by mass. The heat transfer coefficients may be taken as 3.1, 2.5 and 1.7 kW/m² K, respectively, in each effect. Calculate the steam flow at 170 kN/m² and the temperature distribution in the three effects, if: (a) the feed is at 294 K, and (b) the feed is at 355 K. Forward feed is used in each case and the values of U are the same for the two systems. The boiling point in the third effect is 325 K and the liquor has no boiling point rise. Oarrow_forwardForm of the second question 3 Question 2: 500 In the figure shown, gear 2 rotates at 1000rpm. It transmits a power of 5kw to gear 4 via gear Loose 3 idler all gears spur, angle Gear pressure =200, and inclusion = 5m. Draw Analyze the forces on gear 3 and then find the reactions on Column 6, knowing the number of teeth N₂ = 12, N3 = 60, N₁ = 40arrow_forwardExample (7): Determine the heating surface area required for the production of 2.5kg/s of 50wt% NaOH solution from 15 wt% NaOH feed solution which entering at 100 oC to a single effect evaporator. The steam is available as saturated at 451.5K and the boiling point rise (boiling point evaluation) of 50wt% solution is 35K. the overall heat transfer coefficient is 2000 w/m²K. The pressure in the vapor space of the evaporator at atmospheric pressure. The solution has a specific heat of 4.18kJ/ kg.K. The enthalpy of vaporization under these condition is 2257kJ/kg Example (6): 5:48 م An evaporator is concentrating F kg/h at 311K of a 20wt% solution of NaOH to 50wt %. The saturated steam used for heating is at 399.3K. The pressure in the vapor space of the evaporator is 13.3 KPa abs. The 5:48 Oarrow_forward
- Design a speed warning system that receives on two lines, an indication of the speed limit on the highway. There are three possible values 45, 55, or 65 MPH. It receives from the automobile, on two other lines, an indication of the speed of the vehicle. There are four possible values under 45, between 46 and 55, between 56 and 65, and over 65 MPH. It produces two outputs. The first, F, indicates whether the car is going above the speed limit. The second, G, indicates that the car is driving at a "dangerous speed" _ defined as either over 65 MPH or more than 10 MPH above the speed limit. The inputs are coded as follows: Speed limit A B Speed C D 45 0 0 65 1 1 a) Complete the Truth table for the speed warning system Inputs Outputs A B C D F G b) Write the Minterm expressions for the Output Functions. c) Minimize the output functions d) Implement the logic e) Using LabView, verify the Correctness of the Speed Warning System.arrow_forwardEx. The cantilever beam shown us, made ofrem steel with = 552 MPa is , ut subjected to fully reversed load. Neglect shear stress effect, estimate wheather the beam is safe or not safe at N= lo cycles 9 The beam is machined surface and the operating temp. is 100C. A F 200 a=0 N -200 N 1 L= 10cm D time 764 Yze.25 Gm L D= 1.3 cm d = 1 cm b= 1 cm -momend diagram AA -FL at the root of the cantilever, the bending moment is max. factor Ex. Repeat Ex. in page (24), with fluctuating load as shown below. By = 46242,041 = 552 MPa. Find the safety (NF) using Modified -Goodman, Gerber, and soderberg criterias F(N). ....400 timearrow_forwardExample The bar Shown Is. subsected to combined loadings as follows: P = = 20.KN F = 0 to 2 KN T= 0-5 KN.m The bar material has Se=400 mpa and out = 1379 MPa, Yiu= 1000 mpa Find the factor of safety, neglect the transverse Shear- Sol I load analysis ар F T Par = 20 KN (axial load- Pmim = -20 KN fully reversed dynamic) Emark 2km = Fmim = 0 N (bending loading -dynamic) Repeated D=20mm d=15 mm r=5mm L= =250mmarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Understanding Motor ControlsMechanical EngineeringISBN:9781337798686Author:Stephen L. HermanPublisher:Delmar Cengage LearningElectrical Transformers and Rotating MachinesMechanical EngineeringISBN:9781305494817Author:Stephen L. HermanPublisher:Cengage LearningRefrigeration and Air Conditioning Technology (Mi...Mechanical EngineeringISBN:9781305578296Author:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill JohnsonPublisher:Cengage Learning
Understanding Motor Controls
Mechanical Engineering
ISBN:9781337798686
Author:Stephen L. Herman
Publisher:Delmar Cengage Learning
Electrical Transformers and Rotating Machines
Mechanical Engineering
ISBN:9781305494817
Author:Stephen L. Herman
Publisher:Cengage Learning
Refrigeration and Air Conditioning Technology (Mi...
Mechanical Engineering
ISBN:9781305578296
Author:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson
Publisher:Cengage Learning