Concept explainers
The quantity designated by Ampere-hours.
Answer to Problem 1OQ
Option (d) Ampere-hour designates the amount of charge.
Explanation of Solution
Write the expression for Ampere.
Here,
Write the expression for Ampere-hour.
Conclusion:
Substitute
The
The unit for current is Ampere. Thus, option (a) is incorrect.
The unit for power is Watt. Thus, option (b) is incorrect.
The unit for energy is Joule. Thus, option (c) is incorrect.
The unit for potential is Volts. Thus, option (e) is incorrect.
Want to see more full solutions like this?
Chapter 27 Solutions
Bundle: Physics for Scientists and Engineers with Modern Physics, Loose-leaf Version, 9th + WebAssign Printed Access Card, Multi-Term
- The immediate cause of many deaths is ventricular fibrillation, an uncoordinated quivering of the heart, as opposed to proper beating. An electric shock to the chest can cause momentary paralysis of the heart muscle, after which the heart will sometimes start organized beating again. A defibrillator is a device that applies a strong electric shock to the chest over a time of a few milliseconds. The device contains a capacitor of a few microfarads, charged to several thousand volts. Electrodes called paddles, about 8 cm across and coated with conducting paste, are held against the chest on both sides of the heart. Their handles are insulated to prevent injury to the operator, who calls Clear! and pushes a button on one paddle to discharge the capacitor through the patient's chest Assume an energy of 3.00 102 W s is to be delivered from a 30.0-F capacitor. To what potential difference must it be charged?arrow_forwardConsider the circuit shown in Figure P20.52, where C1 = 6.00 F, C2 = 3.00 F, and V = 20.0 V. Capacitor C1 is first charged by closing switch S1. Switch S1 is then opened, and the charged capacitor is connected to the uncharged capacitor by closing S2. Calculate (a) the initial charge acquired by C1 and (b) the final charge on each capacitor. Figure P20.52arrow_forwardA battery is used to charge a capacitor through a resistor as shown in Figure P27.44. Show that half the energy supplied by the battery appears as internal energy in the resistor and half is stored in the capacitor. Figure P27.44arrow_forward
- According to UE=12C(V)2 (Eq. 27.3), a greater capacitance means more energy is stored by the capacitor, but according to UE = Q2/2C (Eq. 27.2), a greater capacitance means less energy is stored. How can both of these equations be correct?arrow_forwardThe battery capacity of a lithium ion battery in a digital music player is 750 mA-h. The manufacturer claims that the player can operate for eight hours if the battery is initially fully charged. Given this information, determine the number of electrons that flow through the player as you listen to your favorite songs for three hours.arrow_forward(a) In electron-volts, how much work does an ideal battery with a 39.0 V emf do on an electron that passes through the battery from the positive to the negative terminal? (b) If 4.68 × 1018 electrons pass through each second, what is the power of the battery? (a) Number (b) Number P Units Unitsarrow_forward
- Two circular metal plates with 15 cm radius are connected to either side of a 75 V battery. The plates are separated by 5 mm. The battery is then disconnected and replaced with a wire that has a resistance 500 kiloohms. (a) Calculate the charge that the battery sends to each plate.(b) Calculate how long it will take the capacitor to discharge to 2 nC.arrow_forwardCardiac defibrillators must be able to supply a high voltage very quickly, and so use capacitors. If a certain defibrillator has a 154 µF capacitor charges to 2,697 V. If this electrical charge is released into the patient in a time of 4.85 milliseconds, what is the (average) power, in watts?arrow_forwardThree capacitors of 8µF, 9µF and 12µF are connected in parallel across a battery of 80 V. Find a) the equivalent capacitance, b) the total charge on the equivalent capacitor, c) th voltage drop across each capacitor, d) the charge on each capacitor, e) the energy stored in each capacitor, f) the total energy stored in the circuit.arrow_forward
- In the figure & = 2.63 V, 82 = 0.933 V, R1 = 5.96 N, R2 = 2.98 0, R3 = 3.85 N, and both batteries are ideal. What is the rate at which energy is dissipated in (a) R1, (b) R2, and (c) R3? What is the power of (d) battery 1 and (e) battery 2? ww R +18, (a) Number i Units (b) Number i Units (c) Number Units (d) Number i Units (e) Number Units > > > > >arrow_forward2. Q (C) capacitor P 0.63Q.. 0.37Q. 2 μF 3 μF t (us) 37 80 5 µF (а) (b) FIGURE 2 (a) The graph in FIGURE 2(a) shows how the charge, Q on a capacitor P changes with time, t when is charged through a 20 Q resistor. Determine the capacitance of capacitor P? (b) Capacitor P is then arranged as shown in FIGURE 2(b). Determine the effective capacitance.arrow_forwardThe flash unit in a camera uses a special circuit to “step up” the 3.0 V from the batteries to 300 V, which charges a capacitor. The capacitor is then discharged through a flashlamp. The discharge takes 10 μs, and the average power dissipated in the flashlamp is 105 W. What is the capacitance of the capacitor?arrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning