EBK PHYSICS FOR SCIENTISTS AND ENGINEER
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
6th Edition
ISBN: 9781319321710
Author: Mosca
Publisher: VST
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Chapter 27, Problem 14P

(a)

To determine

The magnetic field at x=1.0m,y=3.0m .

(a)

Expert Solution
Check Mark

Answer to Problem 14P

The magnetic field is (12.72pT)k^ .

Explanation of Solution

Given:

The charge is q=12μC .

The velocity is v=30m/si^ .

Formula used:

The expression for magnetic field is given by,

  B=μ04πqv×r^r2

Calculation:

The magnetic field is calculated as,

  B=μ04πqv×r^r2=( 4π× 10 7 Tm/A 4π)( ( ( 12μC )( 10 6 C 1μC ) )( ( 30m/s i ^ )× r ^ ) ( ( 1.0m0m ) i ^ +( 3.0m2.0m ) j ^ ) 2 )=(( 36× 10 12 T m 2 )( 10 12 pT 1T ))( ( i ^ ×( 1 ( 1m ) 2 + ( 1m ) 2 i ^ + 1 ( 1m ) 2 + ( 1m ) 2 j ^ ) ) ( ( 1m ) 2 + ( 1m ) 2 ) 2 )=(12.72pT)k^

Conclusion:

Therefore, the magnetic field at origin is (12.72pT)k^ .

(b)

To determine

The magnetic field at x=2.0,y=2.0m .

(b)

Expert Solution
Check Mark

Answer to Problem 14P

The magnetic field is 0 .

Explanation of Solution

Calculation:

The magnetic field is calculated as,

  B=μ04πqv×r^r2=( 4π× 10 7 Tm/A 4π)( ( ( 12μC )( 10 6 C 1μC ) )( ( 30m/s i ^ )× r ^ ) ( ( 2.0m0m ) i ^ +( 2.0m2.0m ) j ^ ) 2 )=(( 36× 10 12 T m 2 )( 10 12 pT 1T ))( ( i ^ ×( i ^ ) ) ( 2m ) 2 )=0(i^×i^=0)

Conclusion:

Therefore, the magnetic field is 0 .

(c)

To determine

The magnetic field at x=2.0,y=3.0m .

(c)

Expert Solution
Check Mark

Answer to Problem 14P

The magnetic field is (3.22pT)k^ .

Explanation of Solution

Calculation:

The magnetic field is calculated as,

  B=μ04πqv×r^r2=( 4π× 10 7 Tm/A 4π)( ( ( 12μC )( 10 6 C 1μC ) )( ( 30m/s i ^ )× r ^ ) ( ( 2.0m0m ) i ^ +( 3.0m2.0m ) j ^ ) 2 )=(( 36× 10 12 T m 2 )( 10 12 pT 1T ))( ( i ^ ×( i ^ ) ) ( ( ( 2.0m ) 2 + ( 1.0m ) 2 ) ) 2 )=(3.22pT)k^

Conclusion:

Therefore, the magnetic field is (3.22pT)k^ .

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Chapter 27 Solutions

EBK PHYSICS FOR SCIENTISTS AND ENGINEER

Ch. 27 - Prob. 11PCh. 27 - Prob. 12PCh. 27 - Prob. 13PCh. 27 - Prob. 14PCh. 27 - Prob. 15PCh. 27 - Prob. 16PCh. 27 - Prob. 17PCh. 27 - Prob. 18PCh. 27 - Prob. 19PCh. 27 - Prob. 20PCh. 27 - Prob. 21PCh. 27 - Prob. 22PCh. 27 - Prob. 23PCh. 27 - Prob. 24PCh. 27 - Prob. 25PCh. 27 - Prob. 26PCh. 27 - Prob. 27PCh. 27 - Prob. 28PCh. 27 - Prob. 29PCh. 27 - Prob. 30PCh. 27 - Prob. 31PCh. 27 - Prob. 32PCh. 27 - Prob. 33PCh. 27 - Prob. 34PCh. 27 - Prob. 35PCh. 27 - Prob. 36PCh. 27 - Prob. 37PCh. 27 - Prob. 38PCh. 27 - Prob. 39PCh. 27 - Prob. 40PCh. 27 - Prob. 41PCh. 27 - Prob. 42PCh. 27 - Prob. 43PCh. 27 - Prob. 44PCh. 27 - Prob. 45PCh. 27 - Prob. 46PCh. 27 - Prob. 47PCh. 27 - Prob. 48PCh. 27 - Prob. 49PCh. 27 - Prob. 50PCh. 27 - Prob. 51PCh. 27 - Prob. 52PCh. 27 - Prob. 53PCh. 27 - Prob. 54PCh. 27 - Prob. 55PCh. 27 - Prob. 56PCh. 27 - Prob. 57PCh. 27 - Prob. 58PCh. 27 - Prob. 59PCh. 27 - Prob. 60PCh. 27 - Prob. 61PCh. 27 - Prob. 62PCh. 27 - Prob. 63PCh. 27 - Prob. 64PCh. 27 - Prob. 65PCh. 27 - Prob. 66PCh. 27 - Prob. 67PCh. 27 - Prob. 68PCh. 27 - Prob. 69PCh. 27 - Prob. 70PCh. 27 - Prob. 71PCh. 27 - Prob. 72PCh. 27 - Prob. 73PCh. 27 - Prob. 74PCh. 27 - Prob. 75PCh. 27 - Prob. 76PCh. 27 - Prob. 77PCh. 27 - Prob. 78PCh. 27 - Prob. 79PCh. 27 - Prob. 80PCh. 27 - Prob. 81PCh. 27 - Prob. 82PCh. 27 - Prob. 83PCh. 27 - Prob. 84PCh. 27 - Prob. 85PCh. 27 - Prob. 86PCh. 27 - Prob. 87PCh. 27 - Prob. 88PCh. 27 - Prob. 89PCh. 27 - Prob. 90PCh. 27 - Prob. 91PCh. 27 - Prob. 92PCh. 27 - Prob. 93PCh. 27 - Prob. 94PCh. 27 - Prob. 95PCh. 27 - Prob. 96PCh. 27 - Prob. 97PCh. 27 - Prob. 98P
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Magnets and Magnetic Fields; Author: Professor Dave explains;https://www.youtube.com/watch?v=IgtIdttfGVw;License: Standard YouTube License, CC-BY