Explanation Given info: The object distance is 24 cm , the refractive index of red light is 1.572 , the refractive index of violet light is 1.605 and image distance of red light is 55.00 cm The focal length is inversely proportional to the term ( n − 1 ) f ∝ 1 n − 1 Here, n is the refractive index. The formula to calculate the focal length of red light is, f r = 1 n r − 1 Here, n r is the refractive index of red light. The formula to calculate the focal length of red light is, 1 f r = 1 v r − 1 u Here, u is the object distance. v r is the image distance of red light. Substitute 1 n r − 1 for f r in the above formula. 1 f r = 1 v r − 1 u 1 n r − 1 = 1 v r − 1 u (1) The formula to calculate the focal length of violet light is, f v = 1 n v − 1 Here, n v is the refractive index of violet light. The formula to calculate the focal length of violet light is, 1 f v = 1 v v − 1 u Here, u is the object distance. v v is the image distance of violet light. Substitute 1 n v − 1 for f v in the above formula. 1 f v = 1 v v − 1 u 1 n v − 1 = 1 v v − 1 u (2) Divide equation (1) and (2)

5th Edition

ISBN: 9780321976444

Author: James S. Walker

Publisher: PEARSON

See similar textbooks

Concept explainers

Refraction of Light

Refraction is a change in the direction of light rays when they travel from one medium to another. It is the bending of light when it goes through different media.

Angle of Refraction

Light is considered by many scientists to have dual nature, both particle nature and wave nature. First, Particle nature is one in which we consider a stream of packets of energy called photons. Second, Wave nature is considering light as electromagnetic…

Index of Refraction of Diamond

Diamond, the world’s hardest naturally occurring material and mineral known, is a solid form of the element carbon. The atoms are arranged in a crystal structure called diamond cubic. They exist in a huge variety of colours. Also, they are one of the bes…

Videos

Question

Chapter 26, Problem 86PCE

To determine

The image distance of violet light.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 26, Problem 85PCE

Chapter 26, Problem 87GP

Students have asked these similar questions

A uniform ladder of length L and weight w is leaning against a vertical wall. The coefficient of static friction between the ladder and the floor is the same as that between the ladder and the wall. If this coefficient of static friction is μs : 0.535, determine the smallest angle the ladder can make with the floor without slipping. ° = A 14.0 m uniform ladder weighing 480 N rests against a frictionless wall. The ladder makes a 55.0°-angle with the horizontal. (a) Find the horizontal and vertical forces (in N) the ground exerts on the base of the ladder when an 850-N firefighter has climbed 4.10 m along the ladder from the bottom. horizontal force magnitude 342. N direction towards the wall ✓ vertical force 1330 N up magnitude direction (b) If the ladder is just on the verge of slipping when the firefighter is 9.10 m from the bottom, what is the coefficient of static friction between ladder and ground? 0.26 × You appear to be using 4.10 m from part (a) for the position of the…

Your neighbor designs automobiles for a living. You are fascinated with her work. She is designing a new automobile and needs to determine how strong the front suspension should be. She knows of your fascination with her work and your expertise in physics, so she asks you to determine how large the normal force on the front wheels of her design automobile could become under a hard stop, ma when the wheels are locked and the automobile is skidding on the road. She gives you the following information. The mass of the automobile is m₂ = 1.10 × 103 kg and it can carry five passengers of average mass m = 80.0 kg. The front and rear wheels are separated by d = 4.45 m. The center of mass of the car carrying five passengers is dCM = 2.25 m behind the front wheels and hcm = 0.630 m above the roadway. A typical coefficient of kinetic friction between tires and roadway is μk 0.840. (Caution: The braking automobile is not in an inertial reference frame. Enter the magnitude of the force in N.)…

John is pushing his daughter Rachel in a wheelbarrow when it is stopped by a brick 8.00 cm high (see the figure below). The handles make an angle of 0 = 17.5° with the ground. Due to the weight of Rachel and the wheelbarrow, a downward force of 403 N is exerted at the center of the wheel, which has a radius of 16.0 cm. Assume the brick remains fixed and does not slide along the ground. Also assume the force applied by John is directed exactly toward the center of the wheel. (Choose the positive x-axis to be pointing to the right.) (a) What force (in N) must John apply along the handles to just start the wheel over the brick? (No Response) N (b) What is the force (magnitude in kN and direction in degrees clockwise from the -x-axis) that the brick exerts on the wheel just as the wheel begins to lift over the brick? magnitude (No Response) KN direction (No Response) ° clockwise from the -x-axis

Chapter 26 Solutions

Physics (5th Edition)

Ch. 26.1 - A ray of light reflects from a horizontal flat...Ch. 26.2 - A meterstick is placed 40 cm in front of a plane...Ch. 26.3 - Rank the following spherical mirrors in order of...Ch. 26.4 - A spherical mirror with an object at the distance...Ch. 26.5 - (a) As a beam of light passes from flint glass to...Ch. 26.6 - The lenses shown in Figure 26-49 have objects that...Ch. 26.7 - An object at the distance do = 15 cm from a lens...Ch. 26.8 - Referring to Figure 26-53, do you expect the index...Ch. 26 - Two plane mirrors meet at right angles at the...Ch. 26 - Two plane mirrors meet at right angles at the...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

The image distance of violet light.

Solution Summary: The author explains that the image distance of violet light is 47.3cm. The focal length is inversely proportional to the term (n-1).

Concept explainers

Videos

The image distance of violet light.

Want to see the full answer?

Chapter 26 Solutions