Concept explainers
(a)
Interpretation: The glycosidic linkages of the stachyose are to be labeled.
Concept introduction: Monosaccharides are the small units of simple sugars. Polysaccharides are made up of small units of monosaccharides. These small units are joined together by glycoside linkage.
(b)
Interpretation: Each glycosidic linkages of the stachyose are to be classified as
Concept introduction: Monosaccharides are the small units of simple sugars. Polysaccharides are made up of small units of monosaccharides. These small units are joined together by glycoside linkage.
(c)
Interpretation: The products formed on hydrolysis of stachyose are to be predicted.
Concept introduction: Glycosidic linkages are hydrolyzed in presence of acid to form cyclic hemiacetal and corresponding alcohol. Acetals in the presence of acid undergo hydrolysis to form cyclic hemiacetals.
(d)
Interpretation: The validation to the corresponding fact that whether stachyose is reducing sugar or not is to be stated.
Concept introduction: The reducing sugars contain hemiacetal and they undergo mutarotation. These sugars are in equilibrium with cyclic monosaccharide forms.
(e)
Interpretation: The product formed on treatment of stachyose with excess
Concept introduction: The hydroxyl groups of monosaccharides are converted into the ether groups in presence of base and
(f)
Interpretation: The product formed on treatment of product in (e) with
Concept introduction: Glycosidic linkages are hydrolyzed in presence of acid to form cyclic hemiacetal and corresponding alcohol. Acetals in the presence of acid undergo hydrolysis to form cyclic hemiacetals.
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Chapter 26 Solutions
ORGANIC CHEMISTRY W/CONNECT & ALEKS
- 9. OA. Rank the expected boiling points of the compounds shown below from highest to lowest. Place your answer appropriately in the box. Only the answer in the box will be graded. (3) points) OH OH بر بد بدید 2 3arrow_forwardThere is an instrument in Johnson 334 that measures total-reflectance x-ray fluorescence (TXRF) to do elemental analysis (i.e., determine what elements are present in a sample). A researcher is preparing a to measure calcium content in a series of well water samples by TXRF with an internal standard of vanadium (atomic symbol: V). She has prepared a series of standard solutions to ensure a linear instrument response over the expected Ca concentration range of 40-80 ppm. The concentrations of Ca and V (ppm) and the instrument response (peak area, arbitrary units) are shown below. Also included is a sample spectrum. Equation 1 describes the response factor, K, relating the analyte signal (SA) and the standard signal (SIS) to their respective concentrations (CA and CIS). Ca, ppm V, ppm SCa, arb. units SV, arb. units 20.0 10.0 14375.11 14261.02 40.0 10.0 36182.15 17997.10 60.0 10.0 39275.74 12988.01 80.0 10.0 57530.75 14268.54 100.0…arrow_forwardA mixture of 0.568 M H₂O, 0.438 M Cl₂O, and 0.710 M HClO are enclosed in a vessel at 25 °C. H₂O(g) + C₁₂O(g) = 2 HOCl(g) K = 0.0900 at 25°C с Calculate the equilibrium concentrations of each gas at 25 °C. [H₂O]= [C₁₂O]= [HOCI]= M Σ Marrow_forward
- What units (if any) does the response factor (K) have? Does the response factor (K) depend upon how the concentration is expressed (e.g. molarity, ppm, ppb, etc.)?arrow_forwardProvide the structure, circle or draw, of the monomeric unit found in the biological polymeric materials given below. HO OH amylose OH OH 행 3 HO cellulose OH OH OH Ho HOarrow_forwardWhat units (if any) does K have? Does K depend upon how the concentration is expressed (e.g. molarity, ppm, ppb, etc.)? in calculating the response factorarrow_forward
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