Cell Membrane Resistance
The capacitance of biological membranes is about 1.0 μF per cm2 of membrane area, so investigators can determine the surface area of a cell membrane by using intracellular electrodes to measure the membrane’s capacitive reactance. An investigator applies a 1.0 μA peak current at 40 kHz to a cell and measures the peak out-of-phase voltage—that is, the component of the voltage due to the capacitive reactance of the cell membrane—to be 0.16 V.
If the investigator applies a 1.0 μA peak current at 40 kHz to a cell with twice the membrane area of the cell noted in the passage, what will be the peak out-of-phase voltage?
A. 0.32 V
B. 0.16 V
C. 0.080 V
D. 0.040 V
Want to see the full answer?
Check out a sample textbook solutionChapter 26 Solutions
Pearson eText for College Physics: A Strategic Approach -- Instant Access (Pearson+)
Additional Science Textbook Solutions
Chemistry: The Central Science (14th Edition)
Anatomy & Physiology (6th Edition)
Microbiology: An Introduction
Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)
Human Biology: Concepts and Current Issues (8th Edition)
Campbell Essential Biology with Physiology (5th Edition)
- 10:44 AM Fri Jan 31 O Better endurance Limb end points travel less D Question 2 Take Quiz 1 pt: Two springs are arranged in series, and the whole arrangement is pulled a vertical distance of 2 cm. If the force in Spring A is 10 N, what is the force in Spring B as a result of the displacement? 05N 5 N 0.2 N 10 N O2N Question 3 1 ptsarrow_forwardNo chatgpt pls will upvote Already got wrong chatgptarrow_forwardPlz no chatgpt pls will upvotearrow_forward
- I need correct answer not chatgptarrow_forwardWhat is the resistance (in (2) of a 27.5 m long piece of 17 gauge copper wire having a 1.150 mm diameter? 0.445 ΧΩarrow_forwardFind the ratio of the diameter of silver to iron wire, if they have the same resistance per unit length (as they might in household wiring). d. Ag dFe = 2.47 ×arrow_forward
- Find the ratio of the diameter of silver to iron wire, if they have the same resistance per unit length (as they might in household wiring). d Ag = 2.51 dFe ×arrow_forwardShow that the units 1 v2/Q = 1 W, as implied by the equation P = V²/R. Starting with the equation P = V²/R, we can get an expression for a watt in terms of voltage and resistance. The units for voltage, V, are equivalent to [? v2 v2 A, are equivalent to J/C ✓ X . Therefore, 1 = 1 = 1 A V1 J/s Ω V-A X = 1 W. . The units for resistance, Q, are equivalent to ? The units for current,arrow_forwardPlease solve and answer the question correctly please. Thank you!!arrow_forward
- Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax College
- Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning