The new potential difference across 5.00 μ F and 10.0 μ F when the switch is closed.

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Chapter 26, Problem 63AP

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The new potential difference across 5.00 μF and 10.0 μF when the switch is closed.

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A 10.0-µF capacitor is charged to 15.0 V. It is next connected in 5.00раF 10.0 µF series with an uncharged 5.00-µF capacitor. The series combina- tion is finally connected across a 50.0-V battery as diagrammed in Figure P26.63. Find the new potential differences across the 5.00-рF and 10.0-иF сараcitors after the switch is thrown closed. AV; = 15.0 V + 50.0 V

Three capacitors are connected to a battery as shown in Figure P26.22. Their capacitances are C, = 3C, C, = C, and C3 = 5C. Co Figure P26.22 (a) What is the equivalent capacitance of this set of capacitors (in terms of C)? Ceg = (b) State the ranking of the capacitors according to the charge they store, from largest to smallest. > Q (c) Rank the capacitors according to the potential differences across them, from largest to smallest. AV1 = AV2 AV2 > AV3 O AV1 > AV2 = AV3 O AV2 > AV3 > AV1 (d) If C3 is increased, what happens to the charge stored by each of the capacitors? Q3 and Q2 increases; Q, decreases. O Q3 and Q1 increases; Q2 decreases. O Q3, Q1, and Q2 increases. O All charges stay the same.

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