ORGANIC CHEMISTRY W/BIOLOGICAL TOPICS
ORGANIC CHEMISTRY W/BIOLOGICAL TOPICS
6th Edition
ISBN: 9781260325294
Author: SMITH
Publisher: RENT MCG
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Chapter 26, Problem 40P
Interpretation Introduction

(a)

Interpretation: The enantiomer of D-arabinose is to be drawn.

Concept introduction: An arabinose is a monosaccharide which contains five carbon atoms and an aldehyde group. The molecular formula of arabinose is C5H10O5.

Interpretation Introduction

(b)

Interpretation: An epimer of D-arabinose at C3 is to be drawn.

Concept introduction: An arabinose is a monosaccharide which contains five carbon atoms and an aldehyde group. The molecular formula of arabinose is C5H10O5.

Interpretation Introduction

(c)

Interpretation: The diastereomer that is not an epimer of D-arabinose is to be drawn.

Concept introduction: An arabinose is a monosaccharide which contains five carbon atoms and an aldehyde group. The molecular formula of arabinose is C5H10O5.

Interpretation Introduction

(d)

Interpretation: The constitutional isomer of D-arabinose contains a carbonyl group is to be drawn.

Concept introduction: An arabinose is a monosaccharide which contains five carbon atoms and an aldehyde group. The molecular formula of arabinose is C5H10O5.

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Q2: Ranking Acidity a) Rank the labeled protons in the following molecule in order of increasing pKa. Briefly explain the ranking. Use Table 2.2 as reference. Ha Нь HC H-N Ha OHe b) Atenolol is a drug used to treat high blood pressure. Which of the indicated N-H bonds is more acidic? Explain. (Hint: use resonance structures to help) Name the functional groups on atenolol. H H-N atenolol Ν H-N OH Н
Answer d, e, and f
If the rotational constant of a molecule is B = 120 cm-1, it can be stated that the transition from 2←1:a) gives rise to a line at 120 cm-1b) is a forbidden transitionc) gives rise to a line at 240 cm-1d) gives rise to a line at 480 cm-1

Chapter 26 Solutions

ORGANIC CHEMISTRY W/BIOLOGICAL TOPICS

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