Stats: Modeling the World Nasta Edition Grades 9-12
Stats: Modeling the World Nasta Edition Grades 9-12
3rd Edition
ISBN: 9780131359581
Author: David E. Bock, Paul F. Velleman, Richard D. De Veaux
Publisher: PEARSON
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Chapter 26, Problem 3E

a)

To determine

To find expected value.

a)

Expert Solution
Check Mark

Answer to Problem 3E

Expected value is 10.

Explanation of Solution

Given:

    FaceCount
    111
    27
    39
    415
    512
    66

Formula:

  E=np

Calculation:

The die roll 60 times. Therefore, sample size would be n = 60.

There is equal chance to get a face value when die is rolled. Therefore,

  p=16

So, expected value is,

  E=60×16=10

b)

To determine

To explain which test would be appropriate.

b)

Expert Solution
Check Mark

Answer to Problem 3E

Chi-square goodness of fit.

Explanation of Solution

Given:

    FaceCount
    111
    27
    39
    415
    512
    66

The researcher wants to test whether the distribution is uniform. The test involves only one variable so, Chi-square goodness of fit would be appropriate to use.

c)

To determine

To state null and alternative hypotheses.

c)

Expert Solution
Check Mark

Answer to Problem 3E

  H0:p1=p2=...p6=16Ha:At least one of the pis different

Explanation of Solution

Given:

    FaceCount
    111
    27
    39
    415
    512
    66

The null and alternative hypotheses:

  H0:p1=p2=...p6=16Ha:At least one of the pis different

d)

To determine

To check the conditions.

d)

Expert Solution
Check Mark

Answer to Problem 3E

All the conditions satisfied.

Explanation of Solution

Given:

    FaceCount
    111
    27
    39
    415
    512
    66

There are three main conditions of Chi-square test:

Counts, Independent and expected frequencies are at least 5.

The data has given counts so the condition of counts satisfied.

The rolls are random so condition of independent is satisfied.

The expected frequency is 10 which is greater than 5 so all the conditions satisfied.

e)

To determine

To find the degrees of freedom.

e)

Expert Solution
Check Mark

Answer to Problem 3E

The degrees of freedom are 5

Explanation of Solution

Given:

    FaceCount
    111
    27
    39
    415
    512
    66

The degrees of freedom are:

  df=c1=61=5

f)

To determine

To find the χ2 and P-value.

f)

Expert Solution
Check Mark

Answer to Problem 3E

  χ2 = 5.60 and P-value = 0.3471.

Explanation of Solution

Given:

    FaceCount
    111
    27
    39
    415
    512
    66

Using excel,

  Stats: Modeling the World Nasta Edition Grades 9-12, Chapter 26, Problem 3E

So,

  χ2 = 5.60

P-value = 0.3471

g)

To determine

To state the conclusion.

g)

Expert Solution
Check Mark

Answer to Problem 3E

There is not sufficient evidence to reject the claim that the die is fair.

Explanation of Solution

Given:

    FaceCount
    111
    27
    39
    415
    512
    66

Decision: The p-value> 0.05, fail to reject H0.

Conclusion: There is not sufficient evidence to reject the claim that the die is fair.

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