ELEMENTARY+INTERMEDIATE ALGEBRA
ELEMENTARY+INTERMEDIATE ALGEBRA
6th Edition
ISBN: 9781285074672
Author: Larson
Publisher: CENGAGE L
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Chapter 2.6, Problem 35E

a.

To determine

  An expression for the distance the whales travel in x days.

a.

Expert Solution
Check Mark

Answer to Problem 35E

  The distance the whales travel in x days is 100x miles.

Explanation of Solution

Given:

The distance from the Baja Peninsula of Mexico to Alaska = 5000 miles.

The speed of the whales = 100 miles per day.

Concept Used:

Consider the formula of speed-distance-time:

  distance = speed×time

Calculation:

As per the question,

The speed of the whales = 100 miles per day.

Consider, x as the number of days travelled by the whales.

Then, the total distance travelled by the whales in x days is given by,

  distance = speed×time

  distance = 100 miles per day×x days

That is,

  distance = 100x .

Hence,

  The distance the whales travel in x days is 100x miles.

Conclusion:

  The distance the whales travel in x days is 100x miles.

b.

To determine

Complete the given table

ELEMENTARY+INTERMEDIATE ALGEBRA, Chapter 2.6, Problem 35E , additional homework tip  1

b.

Expert Solution
Check Mark

Answer to Problem 35E

ELEMENTARY+INTERMEDIATE ALGEBRA, Chapter 2.6, Problem 35E , additional homework tip  2

Explanation of Solution

Given:

Consider the equation,

  distance = 100x .

Consider the table provided in the question,

ELEMENTARY+INTERMEDIATE ALGEBRA, Chapter 2.6, Problem 35E , additional homework tip  3

Calculation:

As per the given problem

Consider the equation,

  distance = 100x

Where x is the number of days travelled.

1. Substitute the value x=0 in the equation,

  distance = 1000 = 0.

Hence,

The distance travelled in 0 days is 0 miles.

2. Substitute the value x=5 in the equation,

  distance = 1005 = 500.

Hence,

The distance travelled in 5 days is 500 miles.

3. Now, substitute the value x=10 in the equation,

  distance = 10010 = 1000.

Hence,

The distance travelled in 10 days is 1000 miles.

4. Now, substitute the value x=15 in the equation,

  distance = 10015 = 1500.

Hence,

The distance travelled in 15 days is 1500 miles.

5. Now, substitute the value x=20 in the equation,

  distance = 10020 = 2000.

Hence,

The distance travelled in 20 days is 2000 miles.

6. Now, substitute the value x=25 in the equation,

  distance = 10025 = 2500.

Hence,

The distance travelled in 25 days is 2500 miles.

Writing in tabulated form,

ELEMENTARY+INTERMEDIATE ALGEBRA, Chapter 2.6, Problem 35E , additional homework tip  4

Conclusion:

The completed table is as follows:

ELEMENTARY+INTERMEDIATE ALGEBRA, Chapter 2.6, Problem 35E , additional homework tip  5

c.

To determine

Create a scatter plot of the data in the table

c.

Expert Solution
Check Mark

Answer to Problem 35E

The scatter plot represents a straight line,

ELEMENTARY+INTERMEDIATE ALGEBRA, Chapter 2.6, Problem 35E , additional homework tip  6

Explanation of Solution

Given information:

The table is as follows:

ELEMENTARY+INTERMEDIATE ALGEBRA, Chapter 2.6, Problem 35E , additional homework tip  7

The time is to be plotted along x-axis and distance to be plotted along y-axis.

Graph :

ELEMENTARY+INTERMEDIATE ALGEBRA, Chapter 2.6, Problem 35E , additional homework tip  8

Interpretation :

The scattered plot of the data represents a straight-line graph , that is with days the distance travelled also increases.

d.

To determine

Create a scatter plot of the data in the table

d.

Expert Solution
Check Mark

Answer to Problem 35E

The scatter plot represents a straight line,

ELEMENTARY+INTERMEDIATE ALGEBRA, Chapter 2.6, Problem 35E , additional homework tip  9

Explanation of Solution

Given information:

The table is as follows:

ELEMENTARY+INTERMEDIATE ALGEBRA, Chapter 2.6, Problem 35E , additional homework tip  10

The time is to be plotted along x-axis and distance to be plotted along y-axis.

Graph :

As per the question, to extend the plot,

Consider y=5000 which is the distance in miles.

So, substitute distance = 5000 in the equation:

  distance = 100x

  5000=100x

Dividing both sides by 100,

  5000100=100100x

Therefore,

  50=x , or

  x=50 .

Taking values of x in differences of 5 as x=30,x=35,x=40,x=45,x=50 ,

For x=30 ,

  distance = y=10030 = 3000.

For x=35 ,

  distance = y=10035 = 3500.

  for x=40distance = y=10040 = 4000.

  for x=45distance = y=10045 = 4500.

  for x=50distance = y=10050 = 5000.

Tabulating the data,

ELEMENTARY+INTERMEDIATE ALGEBRA, Chapter 2.6, Problem 35E , additional homework tip  11

Plotting the graph,

ELEMENTARY+INTERMEDIATE ALGEBRA, Chapter 2.6, Problem 35E , additional homework tip  12

Interpretation :

The whales take 50 days to migrate from the Baja Peninsula of Mexico to Alaska.

e.

To determine

To solve the equation 100x=5000

e.

Expert Solution
Check Mark

Answer to Problem 35E

  The value of x is 50.

Explanation of Solution

Given:

Consider the equation provided in the question:

  100x=5000

Concept Used:

Multiplicative property of equality.

Calculation:

As per the question,

  100x=5000

Dividing both sides by 100 ,

  100x100=5000100

Therefore,

  x=50 , that is same as the value from the graph in part d.

Conclusion:

  The value of x is 50.

Chapter 2 Solutions

ELEMENTARY+INTERMEDIATE ALGEBRA

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ALGEBRAIC EXPRESSIONS & EQUATIONS | GRADE 6; Author: SheenaDoria;https://www.youtube.com/watch?v=fUOdon3y1hU;License: Standard YouTube License, CC-BY
Algebraic Expression And Manipulation For O Level; Author: Maths Solution;https://www.youtube.com/watch?v=MhTyodgnzNM;License: Standard YouTube License, CC-BY
Algebra for Beginners | Basics of Algebra; Author: Geek's Lesson;https://www.youtube.com/watch?v=PVoTRu3p6ug;License: Standard YouTube License, CC-BY
Introduction to Algebra | Algebra for Beginners | Math | LetsTute; Author: Let'stute;https://www.youtube.com/watch?v=VqfeXMinM0U;License: Standard YouTube License, CC-BY