a. Answer The change in the Vasa’s position with respect to sea level is 55 feet Explanation Given information: In 1628 , the ship Vasa sank in Stockholm harbor in depth of 105 feet water In 1959 , move the Vasa to a shallower depth of 50 feet In 1961 the Vasa was lifted to the surface Calculation: To calculate the change in the position of Vasa’s positon subtract the depth upto which Vasa moved from the depath of Vasa in 1628 Therefore, the obtained equation is as: Change in the Vasa’s position with respect to sea level = depth at which Vasa sank in 1628 - shallower depth upto which Vasa moved in 1959 ⇒ Change in the Vasa’s position with respect to sea level = 105 feet − 50 feet ⇒ Change in the Vasa’s position with respect to sea level = 55 feet Conclusion: The change in the Vasa’s position with respect to sea level is 55 feet b. To determine To calculate: the number of years the Vasa remained underwater Answer Total year up to which Vasa remained in the water are 333 years Explanation Given information: In 1628 , the ship Vasa sank in Stockholm harbor in depth of 105 feet water In 1959 , move the Vasa to a shallower depth of 50 feet In 1961 the Vasa was lifted to the surface Calculation: To evaluate the total year when the Vasa remained in the water it is needed to subtract the year in which Vasa sank from it is moved to surface Therefore, ⇒ Total number of years the Vasa remaind underwater = year in which Vasa moved to surface - year in which the ship Vasa sank ⇒ Total number of years the Vasa remaind underwater = 1961 − 1628 = 333 years Conclusion: Total year up to which Vasa remained in the water are 333 years

6th Edition

ISBN: 9781285074672

Author: Larson

Publisher: CENGAGE L

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Question

Chapter 2.5, Problem 42E

To determine

To calculate: the change in the Vasa’s position with respect to sea level

Expert Solution

Answer to Problem 42E

The change in the Vasa’s position with respect to sea level is 55 feet

Explanation of Solution

Given information:

In 1628 , the ship Vasa sank in Stockholm harbor in depth of 105 feet water

In 1959 , move the Vasa to a shallower depth of 50 feet

In 1961 the Vasa was lifted to the surface

Calculation:

To calculate the change in the position of Vasa’s positon subtract the depth upto which Vasa moved from the depath of Vasa in 1628

Therefore, the obtained equation is as:

Change in the Vasa’s position with respect to sea level = depth at which Vasa sank in 1628 - shallower depth upto which Vasa moved in 1959

⇒Change in the Vasa’s position with respect to sea level = 105 feet −50 feet⇒Change in the Vasa’s position with respect to sea level=55 feet

Conclusion:

The change in the Vasa’s position with respect to sea level is 55 feet

To determine

To calculate:the number of years the Vasa remained underwater

Expert Solution

Answer to Problem 42E

Total year up to which Vasa remained in the water are 333 years

Explanation of Solution

Given information:

In 1628 , the ship Vasa sank in Stockholm harbor in depth of 105 feet water

In 1959 , move the Vasa to a shallower depth of 50 feet

In 1961 the Vasa was lifted to the surface

Calculation:

To evaluate the total year when the Vasa remained in the water it is needed to subtract the year in which Vasa sank from it is moved to surface

Therefore,

⇒Total number of years the Vasa remaind underwater=year in which Vasa moved to surface - year in which the ship Vasa sank ⇒Total number of years the Vasa remaind underwater=1961−1628=333 years

Conclusion:

Total year up to which Vasa remained in the water are 333 years

Chapter 2.5, Problem 41E

Chapter 2.5, Problem 43E

Chapter 2 Solutions

ELEMENTARY+INTERMEDIATE ALGEBRA

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