Organic Chemistry (9th Edition)
Organic Chemistry (9th Edition)
9th Edition
ISBN: 9780321971371
Author: Leroy G. Wade, Jan W. Simek
Publisher: PEARSON
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Chapter 26, Problem 26.32SP

(a)

Interpretation Introduction

To determine: The structure of cellulose acetate.

Interpretation: The structure of cellulose acetate is to be drawn.

Concept Introduction: Cellulose is the polymer of glucose. A larger number of glucose molecules combine together to form cellulose polymer.

(b)

Interpretation Introduction

To determine: The reason for cellulose acetate being soluble in organic solvents.

Interpretation: The reason for cellulose acetate is soluble in organic solvent even though cellulose is not is to be explained.

Concept Introduction: Solubility obeys the principle of ‘like dissolve like’ which means polar solutes dissolves in the polar solvent and non polar solute dissolves in non polar solvents.

(c)

Interpretation Introduction

To determine: The reason for the given observation.

Interpretation: The reason for the disintegration of acetate blouse into a pile of white stuff on the action of acetone is to be explained.

Concept Introduction: Solubility obeys the principle of ‘like dissolve like’ which means polar solutes dissolves in the polar solvent and non polar solute dissolves in non polar solvents.

(d)

Interpretation Introduction

To determine: The fact which comes true as a result of the given action.

Interpretation: The fact which results when students wear polyvinyl chloride shoes to the organic laboratory is to be stated.

Concept Introduction: Solubility obeys the principle of ‘like dissolve like’ which means polar solutes dissolves in the polar solvent and non polar solute dissolves in non polar solvents.

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The reaction for obtaining NO2 from NO and O2 has the rate equation: v = k[NO]2[O2]. Indicate which of the following options is correct.(A). This rate equation is inconsistent with the reaction consisting of a single trimolecular step.(B). Since the overall order is 3, the reaction must necessarily have some trimolecular step in its mechanism.(C). A two-step mechanism:  1) NO + NO ⇄ N2O2 (fast);   2) N2O2 + O2 → NO2 + NO2 (slow).(D). The mechanism must necessarily consist of three unimolecular elementary steps with very similar rate constants.
a. What is the eluent used in the column chromatography here (a “silica plug filtration” is essentially a very short column)? b. The spectroscopy of compound 5b is described in the second half of this excerpt, including 1H-NMR and 13C-NMR (which you will learn about in CHEM 2412L), MS (which you will learn about later in CHEM 2411L) and IR. One of the IR signals is at 3530 cm-1. What functional group does this indicate might be present in compound 5b?
Steps and explanations. Also provide, if possible, ways to adress this kind of problems in general.
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