Organic Chemistry, Books a la Carte Edition (9th Edition)
Organic Chemistry, Books a la Carte Edition (9th Edition)
9th Edition
ISBN: 9780134160382
Author: Leroy G. Wade, Jan W. Simek
Publisher: PEARSON
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Chapter 26, Problem 26.32SP

(a)

Interpretation Introduction

To determine: The structure of cellulose acetate.

Interpretation: The structure of cellulose acetate is to be drawn.

Concept Introduction: Cellulose is the polymer of glucose. A larger number of glucose molecules combine together to form cellulose polymer.

(b)

Interpretation Introduction

To determine: The reason for cellulose acetate being soluble in organic solvents.

Interpretation: The reason for cellulose acetate is soluble in organic solvent even though cellulose is not is to be explained.

Concept Introduction: Solubility obeys the principle of ‘like dissolve like’ which means polar solutes dissolves in the polar solvent and non polar solute dissolves in non polar solvents.

(c)

Interpretation Introduction

To determine: The reason for the given observation.

Interpretation: The reason for the disintegration of acetate blouse into a pile of white stuff on the action of acetone is to be explained.

Concept Introduction: Solubility obeys the principle of ‘like dissolve like’ which means polar solutes dissolves in the polar solvent and non polar solute dissolves in non polar solvents.

(d)

Interpretation Introduction

To determine: The fact which comes true as a result of the given action.

Interpretation: The fact which results when students wear polyvinyl chloride shoes to the organic laboratory is to be stated.

Concept Introduction: Solubility obeys the principle of ‘like dissolve like’ which means polar solutes dissolves in the polar solvent and non polar solute dissolves in non polar solvents.

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43) 10.00 ml of vinegar (active ingredient is acetic acid) is titrated to the endpoint using 19.32 ml of 0.250 M sodium hydroxide. What is the molarity of acetic acid in the vinegar? YOU MUST SHOW YOUR WORK. NOTE: MA x VA = MB x VB
424 Repon Sheet Rates of Chemical Reactions : Rate and Order of 1,0, Deception B. Effect of Temperature BATH TEMPERATURE 35'c Yol of Oh نام Time 485 Buret rend ing(n) 12 194 16. 6 18 20 10 22 24 14 115 95 14738 2158235 8:26 CMS 40148 Total volume of 0, collected Barometric pressure 770-572 ml mm Hg Vapor pressure of water at bath temperature (see Appendix L) 42.2 Slope Compared with the rate found for solution 1, there is Using the ideal gas law, calculate the moles of O; collected (show calculations) times faster 10 Based on the moles of O, evolved, calculate the molar concentration of the original 3% 1,0, solution (sho calculations)
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