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In addition to organic halides, alkyl tosylates (
a. b.
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- When (ft)-6-bromo-2,6-dimethylnonane is dissolved in CH3OH, nucleophilic substitution yields an optically inactive solution. When the isomeric halide (fl)-2-bromo-2,5- dimethylnonane is dissolved in CH3OH under the same conditions, nucleophilic substitution forms an optically active solution. Draw the products formed in each reaction, and explain why the difference in optical activity is observed.arrow_forwardCurved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the arrows to draw the missing intermediates and product formed in this reaction. Include all lone pairs and charges as appropriate. Ignore inorganic byproducts.arrow_forwardNonconjugated B,y-unsaturated ketones are in base-catalyzed equilibrium with their conjugated a,ß-unsaturated isomers. The mechanism of interconversion involves the formation of a resonance-stabilized intermediate with three resonance contributors. Draw the structures of these three resonance contributors. OH • You do not have to consider stereochemistry. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate resonance structures using the symbol from the drop-down menu. + *** Sn [Farrow_forward
- The major product of the given reaction has the molecular formula CH03. Draw its structure in the most stable tautomeric form. Select Draw Rings More Erase H 1. NaOCH,CH3 2. H3O* CH;CH2OHarrow_forwardEach of the following may participate in an elimination reaction, under the proper conditions. (a) Circle the alpha (a) carbon. (b) Circle the beta (B) carbon(s). (c) Draw the alkene product(s) that may form, with the new double bond between the a and ß positions. (d) If more than one alkene product is possible, circle the most stable (Zaitsev) product. A В J C K E F G 33-0arrow_forwardAlcohols react with sulfonyl chlorides to form sulfonate esters. Only the O-H bond of the alcohol is broken in the reaction, and so no inversion of configuration occurs. The resulting sulfonate esters are reactive in SN1 and SN2 reactions since the sulfonate group is a very weak base and is therefore a good leaving group.Draw curved arrows to show the movement of electrons in this step of the mechanism.arrow_forward
- Alcohols react with sulfonyl chlorides to form sulfonate esters. Only the O-H bond of the alcohol is broken in the reaction, and so no inversion of configuration occurs. The resulting sulfonate esters are reactive in SN1 and SN2 reactions since the sulfonate group is a very weak base and is therefore a good leaving group.Draw curved arrows to show the movement of electrons in this step of the mechanism.arrow_forwardWhat would be the major product of this reaction? Click on a letter A through D to answer. CH:CHCHCH2CI AICL CH,CH,CH,CH, CH:CHCHzCH3 C(CH,) CHCH(CHa вarrow_forwardDraw the structure of compound A. Be sure to include stereochemistry.arrow_forward
- Draw the products formed when p-methylaniline (p-CH3C6H4NH2) istreated with following reagent. CH3COCl, AlCl3arrow_forwardlost on this guy as well Be sure to answer all parts. Determine a stepwise mechanism for the following reaction that illustrates why two substitution products are formed. Explain why 1-bromohex-2-ene reacts rapidly with a wide ph Meme under Sx1 reaction conditions, even though it is a 1° alkyl halide. 1-bromohex-2-ene CH₂OH Part 1: The first step in the reaction proceeds according to which mechanism? CH₂CH₂CH₂CH=CHCH₂ CH₂CH₂CH₂CH=CHCH₂ + CH₂OH Part 2 out of 5 Draw the missing resonance contributor. Check my work OCH₁ CH₂CH₂CH₂CH=CH-CH₂ + Br CH₂CH₂CH₂CH=CHCH₂ CH OCH₂ edit structure... Next part +HBrarrow_forwardDraw the products formed when p-methylaniline (p-CH3C6H4NH2) istreated with following reagent. Part (b), then CH3COCl, AlCl3arrow_forward
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