(a) Explanation Given info: The capacitance of the 1 capacitor is 2.50 μF and 2 capacitor is 6.25 μF . The potential difference along the capacitor is 6.00 V . Write the expression for the capacitance of the series connected two capacitors. 1 C eq = 1 C 1 + 1 C 2 C eq = C 1 C 2 C 1 + C 2 Here, C 1 is the capacitance of the 1 capacitor. C 2 is the capacitance of the 2 capacitor. Substitute 2.5 μF for C 1 and 6.25 μF for C 2 in the above expression for the equivalent capacitance of the capacitors (b) To determine The charge on the each capacitors when they are connected parallel across the battery.

Bundle: Physics for Scientists and Engineers, Technology Update, 9th Loose-leaf Version + WebAssign Printed Access Card, Multi-Term

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ISBN: 9781305714892

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Chapter 26, Problem 26.16P

(a)

To determine

The charge on the each capacitor when they are connected in series across the battery.

(b)

To determine

The charge on the each capacitors when they are connected parallel across the battery.

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Chapter 26, Problem 26.15P

Chapter 26, Problem 26.17P

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Chapter 26 Solutions

Bundle: Physics for Scientists and Engineers, Technology Update, 9th Loose-leaf Version + WebAssign Printed Access Card, Multi-Term

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The charge on the each capacitor when they are connected in series across the battery.

Solution Summary: The author explains the charge on the capacitors when they are connected in series across the battery.

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The charge on the each capacitor when they are connected in series across the battery.

The charge on the each capacitors when they are connected parallel across the battery.

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Chapter 26 Solutions