Chapter 26, Problem 22P

To determine

The loss in mass.

Answer to Problem 22P

  $3.56\times {10}^{-28}kg$ .

Explanation of Solution

Given info:

Energy is $200MeV$ and $1MeV=1.60\times {10}^{-13}J$

Formula used:

It is known that $\Delta m=\frac{\Delta E}{c^2}$

Where,

  $\Delta E$ is the energy of the system changes by an amount

  $\Delta m$ is the mass of the system changes by an amount

  $c$ is a factor, $3.00\times {10}^{8}m/s$

Calculation:

Substitute the given values in the formula: $\Delta m=\frac{\Delta E}{c^2}$

  $\Delta m=\frac{\left(200MeV\right)\frac{\left(1.60\times {10}^{-13}J\right)}{1MeV}}{{\left(3.00\times {10}^{8}m/s\right)}^2}$

  $\Delta m=3.56\times {10}^{-28}kg$

Conclusion: The required value is $3.56\times {10}^{-28}kg$ .