Chapter 26, Problem 21P

To determine

The mass that was lost in the process.

Answer to Problem 21P

The loss of mass is $\text{4}\text{.0}\times {10}^{-28}\text{kg}$ .

Explanation of Solution

Given info:

The resulting fragments have a total kinetic energy of about $200\text{MeV}$ .

Formula Used:

Consider the formula to determine the value of kinetic energy is,

  $KE=\left(m-m_0\right)c^2$

Calculation:

Consider the kinetic energy is,

  $\begin{array}{c}KE=200\text{MeV}\\ =200\times 1.6\times {10}^{-13}\\ =3.2\times {10}^{-11}\text{J}\end{array}$

Then, the loss of the mass is,

  $\begin{array}{c}\left(m-m_0\right)=\frac{3.2\times {10}^{-11}}{{\left(3.0\times {10}^8\right)}^2}\text{kg}\\ =\text{4}\text{.0}\times {10}^{-28}\text{kg}\end{array}$

Conclusion:

Therefore, the loss of mass is $\text{4}\text{.0}\times {10}^{-28}\text{kg}$ .