Chapter 26, Problem 21A

To determine

(a)

Find the addition of the given expression with same unit.

Answer to Problem 21A

$8\text{ft}$.

Explanation of Solution

Given:

The given addition is, $3\text{ft}9\text{in}.+4\text{ft}7\text{in}.$

Calculation:

Given: $3\text{ft}9\text{in}.+4\text{ft}7\text{in}.$

Add the numerical values and leave the units unchanged.

Arrange like units in the same column and add each column.

$\begin{array}{l}3\text{ft}9\text{in}.\\ \underset{\_}{4\text{ft}7\text{in}.}\\ 7\text{ft}12\text{in}.\end{array}$

Simplify the sum. Divide $12\text{in}$ by $12$ to express as feet.

$\frac{12}{12}\text{in}.=1\text{ft}$

Now,

Add : $7\text{ft}+1\text{ft}=8\text{ft}$

Hence the solution is, $8\text{ft}$.

To determine

(b)

Find the subtraction of the given expression with same unit.

Answer to Problem 21A

$\text{1 ft}8\text{in}.$.

Explanation of Solution

Given:

The given addition is, $6\text{ft}5\text{in}.-4\text{ft}9\text{in}.$

Calculation:

Given: $6\text{ft}5\text{in}.-4\text{ft}9\text{in}.$

subtract the numerical values and leave the units unchanged.

Arrange like units in the same column and add each column.

$6\text{ft}5\text{in}.=5\text{ft}\text{17}\text{in}.$

$\begin{array}{l}5\text{ft}17\text{in}.\\ \underset{\_}{4\text{ft}9\text{in}.}\\ \text{1 ft}8\text{in}.\end{array}$

Hence the solution is, $\text{1 ft}8\text{in}.$.

To determine

(c)

Find the multiplicationof the given expression with same unit.

Answer to Problem 21A

$23\text{ft}\frac{1}{3}\text{in}.$

Explanation of Solution

Given:

The given addition is, $7\text{ft}9\text{in}.\times 3$

Calculation:

Given: $7\text{ft}9\text{in}.\times 3$

Multiply the numerical values and leave the units unchanged.

$7\text{ft}9\text{in}.\times 3=21\text{ft}27\text{in}.$

Simplify the product.

$27\text{in}.=\frac{27}{12}\text{ft}=2\text{ft}\frac{1}{3}\text{in}.$

Now the product is,

$23\text{ft}\frac{1}{3}\text{in}.$

Hence the solution is, $23\text{ft}\frac{1}{3}\text{in}.$.

To determine

(d)

Find the division of the given expression with same unit.

Answer to Problem 21A

$1\text{ft}$

$7\text{in}.$

Explanation of Solution

Given:

The given addition is, $7\text{ft}11\text{in}.÷5$

Calculation:

Given: $7\text{ft}11\text{in}.÷5$

Divide the numerical values and leave the units unchanged.

Divide $7\text{ft}$ by $5$.

$7\text{ft}÷5=1\text{ft}\left(\text{quotient}\right)\text{and}a2\text{ft}\text{remainder}\text{.}$

Express the $2\text{ft}$ remainder as $24\text{in}.$.

$2\text{ft}=2\times 12\text{in}.=24\text{in}.$

Add $24$ inches to the $11$ inches.

$24\text{in}.+11\text{in}.=35\text{in}.$

Divide $35$ inches by $5$.

$35\text{in}.÷5=7\text{in}.\left(\text{quotient}\right)$

Collect quotient.

$1\text{ft}$

$7\text{in}.$

Hence the solution is, $1\text{ft}$

$7\text{in}.$