Chapter 26, Problem 20A

To determine

(a)

Find the addition of the given expression with same unit.

Answer to Problem 20A

$12\text{ft}5\frac{7}{8}\text{in}.$.

Explanation of Solution

Given:

The given addition is, $7\text{ft}3\frac{1}{2}\text{in}.+5\text{ft}2\frac{3}{8}\text{in}.$

Calculation:

Given: $7\text{ft}3\frac{1}{2}\text{in}.+5\text{ft}2\frac{3}{8}\text{in}.$

Add the numerical values and leave the units unchanged.

Arrange like units in the same column and add each column.

$\begin{array}{l}7\text{ft}3\frac{1}{2}\text{in}.\\ \underset{\_}{5\text{ft}2\frac{3}{8}\text{in}.}\\ 12\text{ft}5\frac{7}{8}\text{in}.\end{array}$

Hence the solution is, $12\text{ft}5\frac{7}{8}\text{in}.$.

To determine

(b)

Find the addition of the given expression with same unit.

Answer to Problem 20A

$5\text{ft}10\frac{3}{16}\text{in}.$.

Explanation of Solution

Given:

The given addition is, $2\text{ft}5\frac{3}{4}\text{in}.+3\text{ft}4\frac{7}{16}\text{in}.$

Calculation:

Given: $2\text{ft}5\frac{3}{4}\text{in}.+3\text{ft}4\frac{7}{16}\text{in}.$

Add the numerical values and leave the units unchanged.

Arrange like units in the same column and add each column.

$\begin{array}{l}2\text{ft}5\frac{3}{4}\text{in}.\\ \underset{\_}{3\text{ft}4\frac{7}{16}\text{in}.}\\ 5\text{ft}10\frac{3}{16}\text{in}.\end{array}$

Hence the solution is, $5\text{ft}10\frac{3}{16}\text{in}.$.

To determine

(c)

Find the subtraction of the given expression with same unit.

Answer to Problem 20A

$1\text{ft}\frac{3}{4}\text{in}.$

Explanation of Solution

Given:

The given addition is, $7\text{ft}6\frac{1}{2}\text{in}.+6\text{ft}5\frac{3}{4}\text{in}$

Calculation:

Given: $7\text{ft}6\frac{1}{2}\text{in}.+6\text{ft}5\frac{3}{4}\text{in}$

subtract the numerical values and leave the units unchanged.

Arrange like units in the same column and subtract each column.

$\begin{array}{l}7\text{ft}6\frac{1}{2}\text{in}.\\ \underset{\_}{6\text{ft}5\frac{3}{4}\text{in}.}\\ 1\text{ft}\frac{3}{4}\text{in}.\end{array}$

Hence the solution is, $1\text{ft}\frac{3}{4}\text{in}.$.

To determine

(d)

Find the subtraction of the given expression with same unit.

Answer to Problem 20A

$2\text{ft}2\frac{9}{16}\text{in}.$

Explanation of Solution

Given:

The given addition is, $3\text{ft}9\frac{7}{8}\text{in}.-1\text{ft}7\frac{5}{16}\text{in}.$

Calculation:

Given: $3\text{ft}9\frac{7}{8}\text{in}.-1\text{ft}7\frac{5}{16}\text{in}.$

subtract the numerical values and leave the units unchanged.

Arrange like units in the same column and subtract each column.

$\begin{array}{l}3\text{ft}9\frac{7}{8}\text{in}.\\ \underset{\_}{1\text{ft}7\frac{5}{16}\text{in}.}\\ 2\text{ft}2\frac{9}{16}\text{in}.\end{array}$

Hence the solution is, $2\text{ft}2\frac{9}{16}\text{in}.$.