Two plane mirrors meet at right angles at the origin, as indicated in Figure 26-54. Suppose an L-shaped object has the position and orientation labeled A. Draw the location and orientation of all the images of object A formed by the two mirrors. Figure 26-54

Question

Want to see more full solutions like this?

Answer 1

Textbook Question

Chapter 26, Problem 1CQ

Two plane mirrors meet at right angles at the origin, as indicated in Figure 26-54. Suppose an L-shaped object has the position and orientation labeled A. Draw the location and orientation of all the images of object A formed by the two mirrors.

Chapter 26, Problem 1CQ, Two plane mirrors meet at right angles at the origin, as indicated in Figure 26-54. Suppose an

Figure 26-54

Expert Solution & Answer

To determine

To draw: The location and orientation of all the images of object A formed by the two mirrors.

Answer to Problem 1CQ

The all images of object A in different quadrants on the basis of coordinate points is shown below.

Physics (5th Edition), Chapter 26, Problem 1CQ , additional homework tip 1

Figure (1)

Explanation of Solution

Introduction: The mirror image of the object shows the opposite position with same size and at same distance. This is described by the reflection and total reflection of light.

Explanation:

Formula to calculate the number of images formed when the two mirrors meet at right angle is,

n=360°θ−1

Here,

θ is the angle between two mirrors.

n is the number of images formed.

Substitute 90° for θ in above equation to find n .

n=360°90°−1=3

Thus, three images will form by reflection and the image formed by the plane mirror is of same size and at same distance as object but behind the mirror.

The coordinates of the image A are (2 m, 2 m) , (1 m, 2 m) and (1 m, 3 m) .

The coordinates of the image A in second quadrant are (−2 m, 2 m) , (−1 m, 2 m) and (−1 m, 3 m) .

The coordinates of the image A in third quadrant are (−2 m, −2 m) , (−1 m, −2 m) and (−1 m, −3 m) .

The coordinates of the image A in fourth quadrant are (2 m, −2 m) , (1 m, −2 m) and (1 m, −3 m) .

Thus, the all images of object A in different quadrants on the basis of above coordinate points is shown below.

Physics (5th Edition), Chapter 26, Problem 1CQ , additional homework tip 2

Figure (1)

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

Two resistors of resistances R1 and R2, with R2>R1, are connected to a voltage source with voltage V0. When the resistors are connected in series, the current is Is. When the resistors are connected in parallel, the current Ip from the source is equal to 10Is. Let r be the ratio R1/R2. Find r. I know you have to find the equations for V for both situations and relate them, I'm just struggling to do so. Please explain all steps, thank you.

Bheem and Ram, jump off either side of a bridge while holding opposite ends of a rope and swing back and forth under the bridge to save a child while avoiding a fire. Looking at the swing of just Bheem, we can approximate him as a simple pendulum with a period of motion of 5.59 s. How long is the pendulum ? When Bheem swings, he goes a full distance, from side to side, of 10.2 m. What is his maximum velocity? What is his maximum acceleration?

The position of a 0.300 kg object attached to a spring is described by x=0.271 m ⋅ cos(0.512π⋅rad/s ⋅t) (Assume t is in seconds.) Find the amplitude of the motion. Find the spring constant. Find the position of the object at t = 0.324 s. Find the object's velocity at t = 0.324 s.

Answer 2

Textbook Question

Chapter 26, Problem 1CQ

Two plane mirrors meet at right angles at the origin, as indicated in Figure 26-54. Suppose an L-shaped object has the position and orientation labeled A. Draw the location and orientation of all the images of object A formed by the two mirrors.

Chapter 26, Problem 1CQ, Two plane mirrors meet at right angles at the origin, as indicated in Figure 26-54. Suppose an

Figure 26-54

Expert Solution & Answer

To determine

To draw: The location and orientation of all the images of object A formed by the two mirrors.

Answer to Problem 1CQ

The all images of object A in different quadrants on the basis of coordinate points is shown below.

Physics (5th Edition), Chapter 26, Problem 1CQ , additional homework tip 1

Figure (1)

Explanation of Solution

Introduction: The mirror image of the object shows the opposite position with same size and at same distance. This is described by the reflection and total reflection of light.

Explanation:

Formula to calculate the number of images formed when the two mirrors meet at right angle is,

n=360°θ−1

Here,

θ is the angle between two mirrors.

n is the number of images formed.

Substitute 90° for θ in above equation to find n .

n=360°90°−1=3

Thus, three images will form by reflection and the image formed by the plane mirror is of same size and at same distance as object but behind the mirror.

The coordinates of the image A are (2 m, 2 m) , (1 m, 2 m) and (1 m, 3 m) .

The coordinates of the image A in second quadrant are (−2 m, 2 m) , (−1 m, 2 m) and (−1 m, 3 m) .

The coordinates of the image A in third quadrant are (−2 m, −2 m) , (−1 m, −2 m) and (−1 m, −3 m) .

The coordinates of the image A in fourth quadrant are (2 m, −2 m) , (1 m, −2 m) and (1 m, −3 m) .

Thus, the all images of object A in different quadrants on the basis of above coordinate points is shown below.

Physics (5th Edition), Chapter 26, Problem 1CQ , additional homework tip 2

Figure (1)

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Textbook Question

Chapter 26, Problem 1CQ

Two plane mirrors meet at right angles at the origin, as indicated in Figure 26-54. Suppose an L-shaped object has the position and orientation labeled A. Draw the location and orientation of all the images of object A formed by the two mirrors.

Chapter 26, Problem 1CQ, Two plane mirrors meet at right angles at the origin, as indicated in Figure 26-54. Suppose an

Figure 26-54

Expert Solution & Answer

To determine

To draw: The location and orientation of all the images of object A formed by the two mirrors.

Answer to Problem 1CQ

The all images of object A in different quadrants on the basis of coordinate points is shown below.

Physics (5th Edition), Chapter 26, Problem 1CQ , additional homework tip 1

Figure (1)

Explanation of Solution

Introduction: The mirror image of the object shows the opposite position with same size and at same distance. This is described by the reflection and total reflection of light.

Explanation:

Formula to calculate the number of images formed when the two mirrors meet at right angle is,

n=360°θ−1

Here,

θ is the angle between two mirrors.

n is the number of images formed.

Substitute 90° for θ in above equation to find n .

n=360°90°−1=3

Thus, three images will form by reflection and the image formed by the plane mirror is of same size and at same distance as object but behind the mirror.

The coordinates of the image A are (2 m, 2 m) , (1 m, 2 m) and (1 m, 3 m) .

The coordinates of the image A in second quadrant are (−2 m, 2 m) , (−1 m, 2 m) and (−1 m, 3 m) .

The coordinates of the image A in third quadrant are (−2 m, −2 m) , (−1 m, −2 m) and (−1 m, −3 m) .

The coordinates of the image A in fourth quadrant are (2 m, −2 m) , (1 m, −2 m) and (1 m, −3 m) .

Thus, the all images of object A in different quadrants on the basis of above coordinate points is shown below.

Physics (5th Edition), Chapter 26, Problem 1CQ , additional homework tip 2

Figure (1)

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 26, Problem 1CQ

Two plane mirrors meet at right angles at the origin, as indicated in Figure 26-54. Suppose an L-shaped object has the position and orientation labeled A. Draw the location and orientation of all the images of object A formed by the two mirrors.

Chapter 26, Problem 1CQ, Two plane mirrors meet at right angles at the origin, as indicated in Figure 26-54. Suppose an

Figure 26-54

Expert Solution & Answer

To determine

To draw: The location and orientation of all the images of object A formed by the two mirrors.

Answer to Problem 1CQ

The all images of object A in different quadrants on the basis of coordinate points is shown below.

Physics (5th Edition), Chapter 26, Problem 1CQ , additional homework tip 1

Figure (1)

Explanation of Solution

Introduction: The mirror image of the object shows the opposite position with same size and at same distance. This is described by the reflection and total reflection of light.

Explanation:

Formula to calculate the number of images formed when the two mirrors meet at right angle is,

n=360°θ−1

Here,

θ is the angle between two mirrors.

n is the number of images formed.

Substitute 90° for θ in above equation to find n .

n=360°90°−1=3

Thus, three images will form by reflection and the image formed by the plane mirror is of same size and at same distance as object but behind the mirror.

The coordinates of the image A are (2 m, 2 m) , (1 m, 2 m) and (1 m, 3 m) .

The coordinates of the image A in second quadrant are (−2 m, 2 m) , (−1 m, 2 m) and (−1 m, 3 m) .

The coordinates of the image A in third quadrant are (−2 m, −2 m) , (−1 m, −2 m) and (−1 m, −3 m) .

The coordinates of the image A in fourth quadrant are (2 m, −2 m) , (1 m, −2 m) and (1 m, −3 m) .

Thus, the all images of object A in different quadrants on the basis of above coordinate points is shown below.

Physics (5th Edition), Chapter 26, Problem 1CQ , additional homework tip 2

Figure (1)

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

To determine

To draw: The location and orientation of all the images of object A formed by the two mirrors.

Answer to Problem 1CQ

The all images of object A in different quadrants on the basis of coordinate points is shown below.

Physics (5th Edition), Chapter 26, Problem 1CQ , additional homework tip 1

Figure (1)

Explanation of Solution

Introduction: The mirror image of the object shows the opposite position with same size and at same distance. This is described by the reflection and total reflection of light.

Explanation:

Formula to calculate the number of images formed when the two mirrors meet at right angle is,

n=360°θ−1

Here,

θ is the angle between two mirrors.

n is the number of images formed.

Substitute 90° for θ in above equation to find n .

n=360°90°−1=3

Thus, three images will form by reflection and the image formed by the plane mirror is of same size and at same distance as object but behind the mirror.

The coordinates of the image A are (2 m, 2 m) , (1 m, 2 m) and (1 m, 3 m) .

The coordinates of the image A in second quadrant are (−2 m, 2 m) , (−1 m, 2 m) and (−1 m, 3 m) .

The coordinates of the image A in third quadrant are (−2 m, −2 m) , (−1 m, −2 m) and (−1 m, −3 m) .

The coordinates of the image A in fourth quadrant are (2 m, −2 m) , (1 m, −2 m) and (1 m, −3 m) .

Thus, the all images of object A in different quadrants on the basis of above coordinate points is shown below.

Physics (5th Edition), Chapter 26, Problem 1CQ , additional homework tip 2

Figure (1)

Answer 8

Expert Solution & Answer

To determine

To draw: The location and orientation of all the images of object A formed by the two mirrors.

Answer to Problem 1CQ

The all images of object A in different quadrants on the basis of coordinate points is shown below.

Physics (5th Edition), Chapter 26, Problem 1CQ , additional homework tip 1

Figure (1)

Explanation of Solution

Introduction: The mirror image of the object shows the opposite position with same size and at same distance. This is described by the reflection and total reflection of light.

Explanation:

Formula to calculate the number of images formed when the two mirrors meet at right angle is,

n=360°θ−1

Here,

θ is the angle between two mirrors.

n is the number of images formed.

Substitute 90° for θ in above equation to find n .

n=360°90°−1=3

Thus, three images will form by reflection and the image formed by the plane mirror is of same size and at same distance as object but behind the mirror.

The coordinates of the image A are (2 m, 2 m) , (1 m, 2 m) and (1 m, 3 m) .

The coordinates of the image A in second quadrant are (−2 m, 2 m) , (−1 m, 2 m) and (−1 m, 3 m) .

The coordinates of the image A in third quadrant are (−2 m, −2 m) , (−1 m, −2 m) and (−1 m, −3 m) .

The coordinates of the image A in fourth quadrant are (2 m, −2 m) , (1 m, −2 m) and (1 m, −3 m) .

Thus, the all images of object A in different quadrants on the basis of above coordinate points is shown below.

Physics (5th Edition), Chapter 26, Problem 1CQ , additional homework tip 2

Figure (1)

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

To determine

To draw: The location and orientation of all the images of object A formed by the two mirrors.

Answer 12

Answer to Problem 1CQ

The all images of object A in different quadrants on the basis of coordinate points is shown below.

Physics (5th Edition), Chapter 26, Problem 1CQ , additional homework tip 1

Figure (1)

Answer 13

Explanation of Solution

Introduction: The mirror image of the object shows the opposite position with same size and at same distance. This is described by the reflection and total reflection of light.

Explanation:

Formula to calculate the number of images formed when the two mirrors meet at right angle is,

n=360°θ−1

Here,

θ is the angle between two mirrors.

n is the number of images formed.

Substitute 90° for θ in above equation to find n .

n=360°90°−1=3

Thus, three images will form by reflection and the image formed by the plane mirror is of same size and at same distance as object but behind the mirror.

The coordinates of the image A are (2 m, 2 m) , (1 m, 2 m) and (1 m, 3 m) .

The coordinates of the image A in second quadrant are (−2 m, 2 m) , (−1 m, 2 m) and (−1 m, 3 m) .

The coordinates of the image A in third quadrant are (−2 m, −2 m) , (−1 m, −2 m) and (−1 m, −3 m) .

The coordinates of the image A in fourth quadrant are (2 m, −2 m) , (1 m, −2 m) and (1 m, −3 m) .

Thus, the all images of object A in different quadrants on the basis of above coordinate points is shown below.

Physics (5th Edition), Chapter 26, Problem 1CQ , additional homework tip 2

Figure (1)

Answer 14

Ch. 26.1 - A ray of light reflects from a horizontal flat...Ch. 26.2 - A meterstick is placed 40 cm in front of a plane...Ch. 26.3 - Rank the following spherical mirrors in order of...Ch. 26.4 - A spherical mirror with an object at the distance...Ch. 26.5 - (a) As a beam of light passes from flint glass to...Ch. 26.6 - The lenses shown in Figure 26-49 have objects that...Ch. 26.7 - An object at the distance do = 15 cm from a lens...Ch. 26.8 - Referring to Figure 26-53, do you expect the index...Ch. 26 - Two plane mirrors meet at right angles at the...Ch. 26 - Two plane mirrors meet at right angles at the...

Two plane mirrors meet at right angles at the origin, as indicated in Figure 26-54. Suppose an L-shaped object has the position and orientation labeled A. Draw the location and orientation of all the images of object A formed by the two mirrors. Figure 26-54

Concept explainers

Videos

Answer to Problem 1CQ

Explanation of Solution

Want to see more full solutions like this?

Chapter 26 Solutions

Additional Science Textbook Solutions