EBK AUTOMOTIVE TECHNOLOGY: A SYSTEMS AP
6th Edition
ISBN: 8220100474392
Author: ERJAVEC
Publisher: Cengage Learning US
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Chapter 26, Problem 14RQ
The magnetic field surrounding the coil in a magnetic pulse generator moves when the.
a. Reluctor tooth approaches the coil
b. Reluctor tooth begins to move away from the pickup coil pole
c. Reluctor is aligned with the pickup coil pole
d. Both a and b
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6. A part of the structure for a factory automation system is
a beam that spans 30.0 in as shown in Figure P5-6. Loads
are applied at two points, each 8.0 in from a support. The
left load F₁ = 1800 lb remains constantly applied, while
the right load F₂ = 1800 lb is applied and removed fre-
quently as the machine cycles. Evaluate the beam at both
B and C.
A
8 in
F₁ = 1800 lb
14 in
F2 = 1800 lb
8 in
D
RA
B
C
4X2X1/4
Steel
tube
Beam cross section
RD
30. Repeat Problem 28, except using a shaft that is rotating
and transmitting a torque of 150 N⚫m from the left bear-
ing to the middle of the shaft. Also, there is a profile key-
seat at the middle under the load.
28. The shaft shown in Figure P5-28 is supported by bear-
ings at each end, which have bores of 20.0 mm. Design
the shaft to carry the given load if it is steady and the
shaft is stationary. Make the dimension a as large as pos-
sible while keeping the stress safe. Determine the required
d = 20mm
D = ?
R = ?|
5.4 kN d=20mm
Length not
to scale
-a = ?-
+а=
a = ? +
-125 mm-
-250 mm-
FIGURE P5-28 (Problems 28, 29, and 30)
Chapter 26 Solutions
EBK AUTOMOTIVE TECHNOLOGY: A SYSTEMS AP
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Ch. 26 - Reach, heat range, and air gap are all...Ch. 26 - True or False? The spark plug wire is eliminated...Ch. 26 - Modern ignition cables contain fiber cores that...Ch. 26 - The magnetic field surrounding the coil in a...Ch. 26 - Which of the following electronic switching...Ch. 26 - Technician A says that a magneto resistive sensor...Ch. 26 - While discussing ignition systems: Technician A...Ch. 26 - While discussing ignition timing requirements:...Ch. 26 - While discussing secondary voltage: Technician A...Ch. 26 - Prob. 5ASRQCh. 26 - In El systems using one ignition coil for every...Ch. 26 - While discussing EI systems: Technician A says...Ch. 26 - While discussing El systems: Technician A says...Ch. 26 - Technician A says the switching device controls...Ch. 26 - While discussing spark plugs: Technician A says...
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- 12. Compute the estimated actual endurance limit for SAE 4130 WQT 1300 steel bar with a rectangular cross sec- tion of 20.0 mm by 60 mm. It is to be machined and subjected to repeated and reversed bending stress. A reli- ability of 99% is desired.arrow_forward28. The shaft shown in Figure P5-28 is supported by bear- ings at each end, which have bores of 20.0 mm. Design the shaft to carry the given load if it is steady and the shaft is stationary. Make the dimension a as large as pos- sible while keeping the stress safe. Determine the required d = 20mm D = ? R = ?| 5.4 kN d=20mm Length not to scale -a = ?- +а= a = ? + -125 mm- -250 mm- FIGURE P5-28 (Problems 28, 29, and 30)arrow_forward2. A strut in a space frame has a rectangular cross section of 10.0 mm by 30.0 mm. It sees a load that varies from a tensile force of 20.0 kN to a compressive force of 8.0 kN.arrow_forward
- find stress at Qarrow_forwardI had a theoretical question about attitude determination. In the attached images, I gave two axis and angles. The coefficient of the axes are the same and the angles are the same. The only difference is the vector basis. Lets say there is a rotation going from n hat to b hat. Then, you introduce a intermediate rotation s hat. So, I want to know if the DCM produced from both axis and angles will be the same or not. Does the vector basis affect the numerical value of the DCM? The DCM formula only cares about the coefficient of the axis and the angle. So, they should be the same right?arrow_forward3-15. A small fixed tube is shaped in the form of a vertical helix of radius a and helix angle y, that is, the tube always makes an angle y with the horizontal. A particle of mass m slides down the tube under the action of gravity. If there is a coefficient of friction μ between the tube and the particle, what is the steady-state speed of the particle? Let y γ 30° and assume that µ < 1/√3.arrow_forward
- The plate is moving at 0.6 mm/s when the force applied to the plate is 4mN. If the surface area of the plate in contact with the liquid is 0.5 m^2, deterimine the approximate viscosity of the liquid, assuming that the velocity distribution is linear.arrow_forward3-9. Given that the force acting on a particle has the following components: Fx = −x + y, Fy = x − y + y², F₂ = 0. Solve for the potential energy V. -arrow_forward2.5 (B). A steel rod of cross-sectional area 600 mm² and a coaxial copper tube of cross-sectional area 1000 mm² are firmly attached at their ends to form a compound bar. Determine the stress in the steel and in the copper when the temperature of the bar is raised by 80°C and an axial tensile force of 60 kN is applied. For steel, E = 200 GN/m² with x = 11 x 10-6 per °C. E = 100 GN/m² with α = 16.5 × 10-6 For copper, per °C. [E.I.E.] [94.6, 3.3 MN/m².]arrow_forward
- 3–16. A particle of mass m is embedded at a distance R from the center of a massless circular disk of radius R which can roll without slipping on the inside surface of a fixed circular cylinder of radius 3R. The disk is released with zero velocity from the position shown and rolls because of gravity, all motion taking place in the same vertical plane. Find: (a) the maximum velocity of the particle during the resulting motion; (b) the reaction force acting on the disk at the point of contact when it is at its lowest position. KAR 60° 3R M Fig. P3-16arrow_forwardI have figured out the support reactions, Ay = 240 kN, Ax = 0 kN, Ma = 639.2 kN*m and the constant term for V(x) is 240. I am not figuring out the function of x part right. Show how to derive V(x) and M(x) for this distributed load.arrow_forward2.4 (A). A 75 mm diameter compound bar is constructed by shrinking a circular brass bush onto the outside of a 50 mm diameter solid steel rod. If the compound bar is then subjected to an axial compressive load of 160 kN determine the load carried by the steel rod and the brass bush and the compressive stress set up in each material. For steel, E 210 GN/m²; for brass, E = 100 GN/m². [I. Struct. E.] [100.3, 59.7 kN; 51.1, 24.3 MN/m².]arrow_forward
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