The intermediate formed during the conversion of adenine to hypoxanthine, hydrogen bonds of hypoxanthine-cytosine base pair and the consequences it would have through two rounds of DNA (deoxyribonucleic acid) replication is to be shown. Concept Introduction: ▸ Normally, in DNA, adenine pairs with thymine by forming two hydrogen bonds. On treatment with nitrous acid, amino group of adenine undergoes changes to form diazonium and finally gets removed. ▸ Hypoxanthine forms two hydrogen bonds with cytosine instead of thymine. This mispairing then passes on to the daughter DNA formed during replication and further brings about permanent changes (mutations).

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Answer 1

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Chapter 25, Problem 8PP

Interpretation Introduction

Interpretation:

The intermediate formed during the conversion of adenine to hypoxanthine, hydrogen bonds of hypoxanthine-cytosine base pair and the consequences it would have through two rounds of DNA (deoxyribonucleic acid) replication is to be shown.

Concept Introduction:

▸ Normally, in DNA, adenine pairs with thymine by forming two hydrogen bonds. On treatment with nitrous acid, amino group of adenine undergoes changes to form diazonium and finally gets removed.

▸ Hypoxanthine forms two hydrogen bonds with cytosine instead of thymine. This mispairing then passes on to the daughter DNA formed during replication and further brings about permanent changes (mutations).

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Answer 2

Question

Chapter 25, Problem 8PP

Interpretation Introduction

Interpretation:

The intermediate formed during the conversion of adenine to hypoxanthine, hydrogen bonds of hypoxanthine-cytosine base pair and the consequences it would have through two rounds of DNA (deoxyribonucleic acid) replication is to be shown.

Concept Introduction:

▸ Normally, in DNA, adenine pairs with thymine by forming two hydrogen bonds. On treatment with nitrous acid, amino group of adenine undergoes changes to form diazonium and finally gets removed.

▸ Hypoxanthine forms two hydrogen bonds with cytosine instead of thymine. This mispairing then passes on to the daughter DNA formed during replication and further brings about permanent changes (mutations).

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Answer 3

Question

Chapter 25, Problem 8PP

Interpretation Introduction

Interpretation:

The intermediate formed during the conversion of adenine to hypoxanthine, hydrogen bonds of hypoxanthine-cytosine base pair and the consequences it would have through two rounds of DNA (deoxyribonucleic acid) replication is to be shown.

Concept Introduction:

▸ Normally, in DNA, adenine pairs with thymine by forming two hydrogen bonds. On treatment with nitrous acid, amino group of adenine undergoes changes to form diazonium and finally gets removed.

▸ Hypoxanthine forms two hydrogen bonds with cytosine instead of thymine. This mispairing then passes on to the daughter DNA formed during replication and further brings about permanent changes (mutations).

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Answer 4

Question

Chapter 25, Problem 8PP

Interpretation Introduction

Interpretation:

The intermediate formed during the conversion of adenine to hypoxanthine, hydrogen bonds of hypoxanthine-cytosine base pair and the consequences it would have through two rounds of DNA (deoxyribonucleic acid) replication is to be shown.

Concept Introduction:

▸ Normally, in DNA, adenine pairs with thymine by forming two hydrogen bonds. On treatment with nitrous acid, amino group of adenine undergoes changes to form diazonium and finally gets removed.

▸ Hypoxanthine forms two hydrogen bonds with cytosine instead of thymine. This mispairing then passes on to the daughter DNA formed during replication and further brings about permanent changes (mutations).

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Answer 5

Chapter 25, Problem 8PP

Interpretation Introduction

Interpretation:

The intermediate formed during the conversion of adenine to hypoxanthine, hydrogen bonds of hypoxanthine-cytosine base pair and the consequences it would have through two rounds of DNA (deoxyribonucleic acid) replication is to be shown.

Concept Introduction:

▸ Normally, in DNA, adenine pairs with thymine by forming two hydrogen bonds. On treatment with nitrous acid, amino group of adenine undergoes changes to form diazonium and finally gets removed.

▸ Hypoxanthine forms two hydrogen bonds with cytosine instead of thymine. This mispairing then passes on to the daughter DNA formed during replication and further brings about permanent changes (mutations).

Answer 6

Chapter 25, Problem 8PP

Interpretation Introduction

Interpretation:

The intermediate formed during the conversion of adenine to hypoxanthine, hydrogen bonds of hypoxanthine-cytosine base pair and the consequences it would have through two rounds of DNA (deoxyribonucleic acid) replication is to be shown.

Concept Introduction:

▸ Normally, in DNA, adenine pairs with thymine by forming two hydrogen bonds. On treatment with nitrous acid, amino group of adenine undergoes changes to form diazonium and finally gets removed.

▸ Hypoxanthine forms two hydrogen bonds with cytosine instead of thymine. This mispairing then passes on to the daughter DNA formed during replication and further brings about permanent changes (mutations).

Answer 7

Chapter 25, Problem 8PP

Interpretation Introduction

Interpretation:

The intermediate formed during the conversion of adenine to hypoxanthine, hydrogen bonds of hypoxanthine-cytosine base pair and the consequences it would have through two rounds of DNA (deoxyribonucleic acid) replication is to be shown.

Concept Introduction:

▸ Normally, in DNA, adenine pairs with thymine by forming two hydrogen bonds. On treatment with nitrous acid, amino group of adenine undergoes changes to form diazonium and finally gets removed.

▸ Hypoxanthine forms two hydrogen bonds with cytosine instead of thymine. This mispairing then passes on to the daughter DNA formed during replication and further brings about permanent changes (mutations).

Answer 8

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Answer 9

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Answer 11

Ch. 25 - Prob. 1PP Ch. 25 - Prob. 2PP Ch. 25 - Prob. 3PP Ch. 25 - Prob. 4PP Ch. 25 - Prob. 5PP Ch. 25 - Practice Problem 25.6 (a) There are approximately...Ch. 25 - Prob. 7PP Ch. 25 - Prob. 8PP Ch. 25 - Prob. 9PP Ch. 25 - Practice Problem 25.10 The sense strand of a...

Solution Summary: The author explains the intermediate formed during the conversion of adenine to hypoxanthine and the consequences it would have through two rounds of DNA replication.

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Chapter 25 Solutions