We need to prove that relation R , on { 0 , 1 , 2 , 3 } given by R = { ( 0 , 0 ) , ( 1 , 1 ) , ( 2 , 2 ) , ( 3 , 3 ) , ( 0 , 1 ) , ( 1 , 2 ) , ( 2 , 3 ) , ( 0 , 2 ) , ( 1 , 3 ) } is not partial ordering on { 0 , 1 , 2 , 3 } .

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Chapter 2.5, Problem 7E

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We need to prove that relation R, on {0,1,2,3} given by R={(0,0),(1,1),(2,2),(3,3),(0,1),(1,2),(2,3),(0,2),(1,3)} is not partial ordering on {0,1,2,3}.

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Please conduct a step by step of these statistical tests on separate sheets of Microsoft Excel. If the calculations in Microsoft Excel are incorrect, the null and alternative hypotheses, as well as the conclusions drawn from them, will be meaningless and will not receive any points 3. Paired T-Test: A company implemented a training program to improve employee performance. To evaluate the effectiveness of the program, the company recorded the test scores of 25 employees before and after the training. Determine if the training program is effective in terms of scores of participants before and after the training. (Hints: The null can be about maintaining status-quo or no difference among groups; if alternative hypothesis is non-directional, use the two-tailed p-value from excel file to make a decision about rejecting or not rejecting the null) H0 = H1= Conclusion:

please question 9

Please conduct a step by step of these statistical tests on separate sheets of Microsoft Excel. If the calculations in Microsoft Excel are incorrect, the null and alternative hypotheses, as well as the conclusions drawn from them, will be meaningless and will not receive any points. The data for the following questions is provided in Microsoft Excel file on 4 separate sheets. Please conduct these statistical tests on separate sheets of Microsoft Excel. If the calculations in Microsoft Excel are incorrect, the null and alternative hypotheses, as well as the conclusions drawn from them, will be meaningless and will not receive any points. 1. One Sample T-Test: Determine whether the average satisfaction rating of customers for a product is significantly different from a hypothetical mean of 75. (Hints: The null can be about maintaining status-quo or no difference; If your alternative hypothesis is non-directional (e.g., μ≠75), you should use the two-tailed p-value from excel file to…

Answer 2

Question

Chapter 2.5, Problem 7E

To determine

To explain:

We need to prove that relation R, on {0,1,2,3} given by R={(0,0),(1,1),(2,2),(3,3),(0,1),(1,2),(2,3),(0,2),(1,3)} is not partial ordering on {0,1,2,3}.

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Answer 3

Question

Chapter 2.5, Problem 7E

To determine

To explain:

We need to prove that relation R, on {0,1,2,3} given by R={(0,0),(1,1),(2,2),(3,3),(0,1),(1,2),(2,3),(0,2),(1,3)} is not partial ordering on {0,1,2,3}.

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Answer 4

Question

Chapter 2.5, Problem 7E

To determine

To explain:

We need to prove that relation R, on {0,1,2,3} given by R={(0,0),(1,1),(2,2),(3,3),(0,1),(1,2),(2,3),(0,2),(1,3)} is not partial ordering on {0,1,2,3}.

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Answer 5

Chapter 2.5, Problem 7E

To determine

To explain:

We need to prove that relation R, on {0,1,2,3} given by R={(0,0),(1,1),(2,2),(3,3),(0,1),(1,2),(2,3),(0,2),(1,3)} is not partial ordering on {0,1,2,3}.

Answer 6

Chapter 2.5, Problem 7E

To determine

To explain:

We need to prove that relation R, on {0,1,2,3} given by R={(0,0),(1,1),(2,2),(3,3),(0,1),(1,2),(2,3),(0,2),(1,3)} is not partial ordering on {0,1,2,3}.

Answer 7

Chapter 2.5, Problem 7E

To determine

To explain:

We need to prove that relation R, on {0,1,2,3} given by R={(0,0),(1,1),(2,2),(3,3),(0,1),(1,2),(2,3),(0,2),(1,3)} is not partial ordering on {0,1,2,3}.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 2.1 - Prob. 1E Ch. 2.1 - Prob. 2E Ch. 2.1 - Prob. 3E Ch. 2.1 - Prob. 4E Ch. 2.1 - Prob. 5E Ch. 2.1 - Prob. 6E Ch. 2.1 - Prob. 7E Ch. 2.1 - Prob. 8E Ch. 2.1 - Prob. 9E Ch. 2.1 - Prob. 10E

We need to prove that relation R , on { 0 , 1 , 2 , 3 } given by R = { ( 0 , 0 ) , ( 1 , 1 ) , ( 2 , 2 ) , ( 3 , 3 ) , ( 0 , 1 ) , ( 1 , 2 ) , ( 2 , 3 ) , ( 0 , 2 ) , ( 1 , 3 ) } is not partial ordering on { 0 , 1 , 2 , 3 } .

Solution Summary: The author explains that relation R on 0,1,2,3 is a partial ordering. They can determine by Reflexive, Transitive and Antisymmetriy.

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To explain:

We need to prove that relation R, on {0,1,2,3} given by R={(0,0),(1,1),(2,2),(3,3),(0,1),(1,2),(2,3),(0,2),(1,3)} is not partial ordering on {0,1,2,3}.

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Chapter 2 Solutions

We need to prove that relation R , on { 0 , 1 , 2 , 3 } given by R = { ( 0 , 0 ) , ( 1 , 1 ) , ( 2 , 2 ) , ( 3 , 3 ) , ( 0 , 1 ) , ( 1 , 2 ) , ( 2 , 3 ) , ( 0 , 2 ) , ( 1 , 3 ) } is not partial ordering on { 0 , 1 , 2 , 3 } .

Solution Summary: The author explains that relation R on 0,1,2,3 is a partial ordering. They can determine by Reflexive, Transitive and Antisymmetriy.

Videos

To explain: We need to prove that relation R, on {0,1,2,3} given by R={(0,0),(1,1),(2,2),(3,3),(0,1),(1,2),(2,3),(0,2),(1,3)} is not partial ordering on {0,1,2,3}.

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Chapter 2 Solutions

To explain:

We need to prove that relation R, on {0,1,2,3} given by R={(0,0),(1,1),(2,2),(3,3),(0,1),(1,2),(2,3),(0,2),(1,3)} is not partial ordering on {0,1,2,3}.