A parallel-plate capacitor has plates of area 10cm 2 separated by a 0.10-nun layer of glass insulation with resistivity ρ = 1.2 × 10 13 Ω·m and dielectric constant κ = 5.6. Because of the finite resistivity, charge leaks through the insulation, (a) How can such a leaky capacitor be represented in a circuit diagram? (b) Find the time constant for this capacitor to discharge through its insulation, and show that it depends only on the properties of the insulating material and not on its dimensions.
A parallel-plate capacitor has plates of area 10cm 2 separated by a 0.10-nun layer of glass insulation with resistivity ρ = 1.2 × 10 13 Ω·m and dielectric constant κ = 5.6. Because of the finite resistivity, charge leaks through the insulation, (a) How can such a leaky capacitor be represented in a circuit diagram? (b) Find the time constant for this capacitor to discharge through its insulation, and show that it depends only on the properties of the insulating material and not on its dimensions.
A parallel-plate capacitor has plates of area 10cm2 separated by a 0.10-nun layer of glass insulation with resistivity ρ = 1.2 × 1013 Ω·m and dielectric constant κ = 5.6. Because of the finite resistivity, charge leaks through the insulation, (a) How can such a leaky capacitor be represented in a circuit diagram? (b) Find the time constant for this capacitor to discharge through its insulation, and show that it depends only on the properties of the insulating material and not on its dimensions.
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Required information
The radius of the Moon is 1.737 Mm and the distance between Earth and the Moon is 384.5 Mm.
The intensity of the moonlight incident on her eye is 0.0220 W/m². What is the intensity incident on her retina if the
diameter of her pupil is 6.54 mm and the diameter of her eye is 1.94 cm?
W/m²
Required information
An object is placed 20.0 cm from a converging lens with focal length 15.0 cm (see the figure, not drawn to scale). A
concave mirror with focal length 10.0 cm is located 76.5 cm to the right of the lens. Light goes through the lens, reflects
from the mirror, and passes through the lens again, forming a final image.
Converging
lens
Object
Concave
mirror
15.0 cm
-20.0 cm-
10.0 cm
d cm
d = 76.5.
What is the location of the final image?
cm to the left of the lens
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Required information
A man requires reading glasses with +2.15-D refractive power to read a book held 40.0 cm away with a relaxed eye.
Assume the glasses are 1.90 cm from his eyes.
His uncorrected near point is 1.00 m. If one of the lenses is the one for distance vision, what should the refractive power of the other
lens (for close-up vision) in his bifocals be to give him clear vision from 25.0 cm to infinity?
2.98 D
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