EP GENERAL CHEMISTRY-MOD.MASTERINGCHEM.
11th Edition
ISBN: 9780133897340
Author: Petrucci
Publisher: PEARSON CO
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Chapter 25, Problem 66IAE
Interpretation Introduction
Interpretation:
The minimum kinetic energy of
Concept introduction: Energy associated with an object which is in motion is known as kinetic energy. Due to collision between two atoms, nuclear instability is seen. This is the cause of radiation from radioactive substance and the radiation can be in form of alpha, beta or gamma particle.
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6. The equilibrium constant for the reaction
2 HBr (g)
→ H2(g) + Br2(g)
Can be expressed by the empirical formula
11790 K
In K-6.375 + 0.6415 In(T K-¹)
-
T
Use this formula to determine A,H as a function of temperature. Calculate A,-H at 25 °C and at
100 °C.
3. Nitrosyl chloride, NOCI, decomposes according to
2 NOCI (g) → 2 NO(g)
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Assuming that we start with no moles of NOCl (g) and no NO(g) or Cl2(g), derive an expression
for Kp in terms of the equilibrium value of the extent of reaction, Seq, and the pressure, P.
Given that K₂ = 2.00 × 10-4, calculate Seq/
of
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по
ƒª/ at equilibrium when P = 0.160 bar? Is this result in accord with Le Châtelier's
Principle?
Consider the following chemical equilibrium:
2SO2(g) + O2(g) = 2SO3(g)
•
Write the equilibrium constant expression for this reaction.
Now compare it to the equilibrium constant expression for the related reaction:
•
.
1
SO2(g) + O2(g) = SO3(g)
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Chapter 25 Solutions
EP GENERAL CHEMISTRY-MOD.MASTERINGCHEM.
Ch. 25 - Prob. 1ECh. 25 - Prob. 2ECh. 25 - Prob. 3ECh. 25 - Prob. 4ECh. 25 - Prob. 5ECh. 25 - Prob. 6ECh. 25 - Prob. 7ECh. 25 - Prob. 8ECh. 25 - Prob. 9ECh. 25 - Prob. 10E
Ch. 25 - Prob. 11ECh. 25 - Prob. 12ECh. 25 - Prob. 13ECh. 25 - Prob. 14ECh. 25 - Prob. 15ECh. 25 - Prob. 16ECh. 25 - Prob. 17ECh. 25 - Prob. 18ECh. 25 - Prob. 19ECh. 25 - Prob. 20ECh. 25 - Prob. 21ECh. 25 - Prob. 22ECh. 25 - Prob. 23ECh. 25 - Prob. 24ECh. 25 - Prob. 25ECh. 25 - Prob. 26ECh. 25 - Prob. 27ECh. 25 - Prob. 28ECh. 25 - Prob. 29ECh. 25 - Prob. 30ECh. 25 - Prob. 31ECh. 25 - Prob. 32ECh. 25 - Prob. 33ECh. 25 - Prob. 34ECh. 25 - Prob. 35ECh. 25 - Prob. 36ECh. 25 - Prob. 37ECh. 25 - Prob. 38ECh. 25 - Prob. 39ECh. 25 - Prob. 40ECh. 25 - Prob. 41ECh. 25 - Prob. 42ECh. 25 - Prob. 43ECh. 25 - Prob. 44ECh. 25 - Prob. 45ECh. 25 - Prob. 46ECh. 25 - Prob. 47ECh. 25 - Prob. 48ECh. 25 - Prob. 49ECh. 25 - Prob. 50ECh. 25 - Prob. 51ECh. 25 - Prob. 52ECh. 25 - Prob. 53ECh. 25 - Prob. 54ECh. 25 - Prob. 55ECh. 25 - Prob. 56ECh. 25 - Prob. 57IAECh. 25 - Prob. 58IAECh. 25 - Prob. 59IAECh. 25 - Prob. 60IAECh. 25 - Prob. 61IAECh. 25 - Prob. 62IAECh. 25 - Prob. 63IAECh. 25 - Prob. 64IAECh. 25 - Prob. 65IAECh. 25 - Prob. 66IAECh. 25 - Prob. 67IAECh. 25 - Prob. 68IAECh. 25 - Prob. 69IAECh. 25 - Prob. 70IAECh. 25 - Prob. 71IAECh. 25 - Prob. 72FPCh. 25 - Prob. 73FPCh. 25 - Radioactive decay and mass spectrometry are often...Ch. 25 - Prob. 75SAECh. 25 - Prob. 76SAECh. 25 - Prob. 77SAECh. 25 - Prob. 78SAECh. 25 - Prob. 79SAECh. 25 - Prob. 80SAECh. 25 - Prob. 81SAECh. 25 - Prob. 82SAECh. 25 - Prob. 83SAECh. 25 - Prob. 84SAECh. 25 - Prob. 85SAECh. 25 - Prob. 86SAECh. 25 - Prob. 87SAECh. 25 - Prob. 88SAECh. 25 - Prob. 89SAECh. 25 - Prob. 90SAECh. 25 - Prob. 91SAECh. 25 - Prob. 92SAECh. 25 - Prob. 93SAE
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- (3 pts) Use the Kapustinskii equation to calculate the lattice enthalpy for MgBr2 anddiscuss any differences between this result and that from #4.arrow_forward(3 pts) Silver metal adopts a fcc unit cell structure and has an atomic radius of 144 pm. Fromthis information, calculate the density of silver. Show all work.arrow_forward4. (3 pts) From the information below, determine the lattice enthalpy for MgBr2. Show all work. AH/(kJ mol-¹) Sublimation of Mg(s) +148 lonization of Mg(g) +2187 to Mg2+(g) Vaporization of Br₂(1) +31 Dissociation of Br,(g) +193 Electron gain by Br(g) -331 Formation of MgBr₂(s) -524arrow_forward
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