A parallel-plate capacitor has plates of area 0.12 m 2 and a separation of 1.2 cm. A battery charges the plates to a potential difference of 120 V and is then disconnected. A dielectric slab of thickness 4.0 mm and dielectric constant 4.8 is then placed symmetrically between the plates. (a) What is the capacitance before the slab is inserted? (b) What is the capacitance with the slab in place? What is the free charge q (c) before and (d) after the slab is inserted? What is the magnitude of the electric field (e) in the space between the plates and dielectric and (f) in the dielectric itself? (g) With the slab in place, what is the potential difference across the plates? (h) How much external work is involved in inserting the slab?
A parallel-plate capacitor has plates of area 0.12 m 2 and a separation of 1.2 cm. A battery charges the plates to a potential difference of 120 V and is then disconnected. A dielectric slab of thickness 4.0 mm and dielectric constant 4.8 is then placed symmetrically between the plates. (a) What is the capacitance before the slab is inserted? (b) What is the capacitance with the slab in place? What is the free charge q (c) before and (d) after the slab is inserted? What is the magnitude of the electric field (e) in the space between the plates and dielectric and (f) in the dielectric itself? (g) With the slab in place, what is the potential difference across the plates? (h) How much external work is involved in inserting the slab?
A parallel-plate capacitor has plates of area 0.12 m2 and a separation of 1.2 cm. A battery charges the plates to a potential difference of 120 V and is then disconnected. A dielectric slab of thickness 4.0 mm and dielectric constant 4.8 is then placed symmetrically between the plates. (a) What is the capacitance before the slab is inserted? (b) What is the capacitance with the slab in place? What is the free charge q (c) before and (d) after the slab is inserted? What is the magnitude of the electric field (e) in the space between the plates and dielectric and (f) in the dielectric itself? (g) With the slab in place, what is the potential difference across the plates? (h) How much external work is involved in inserting the slab?
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19:39 ·
C
Chegg
1 69%
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The compound beam is fixed at Ę and supported by rollers at A and B. There are pins at C and D. Take
F=1700 lb. (Figure 1)
Figure
800 lb
||-5-
F
600 lb
بتا
D
E
C
BO
10 ft 5 ft 4 ft-—— 6 ft — 5 ft-
Solved Part A The compound
beam is fixed at E and...
Hình ảnh có thể có bản quyền. Tìm hiểu thêm
Problem
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800 lb
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600 lb
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E
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Trying
Cheaa
Những kết quả này có
hữu ích không?
There are pins at C and D To F-1200 Egue!)
Chegg
Solved The compound b...
Có Không ☑
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Chegg
10
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