EBK PHYSICS FOR SCIENTISTS AND ENGINEER
6th Edition
ISBN: 9781319321710
Author: Mosca
Publisher: VST
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 25, Problem 49P
To determine
The expression for resistance of the wire.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A cylindrical conductor has resistance of R0 = 950 Ω. It has length L, radius of the cross section r, and resistivity ρ.
a) If the resistivity was restored to its original value and instead the length of the conductor decreased by a factor of 2, what would the value of the new resistance be, in ohms?
b) If the resistivity and length of the conductor were at their original values and the radius of the conductor increased by a factor of 4, what would be the value of the new resistance, in ohms?
The resistivity of copper is 1.72E-8 Ω·m. We would like to use a copper wire to connect two devices that are 6.65 m apart and require the wire resistance to be no higher than 7.21E-3 Ω. What is the minimum cross section area of the copper wire that we should use (in m2)?
Part (a) I measure the resistance of this wire and find it to be R = 156 Q. What is the resistivity of the material the wire is made out of?
p=
Problem 7: A particular wire has a length of L = 2.7 m and a circular cross-sectional area of radius r= 1.69 mm.
G=
sin()
cos
cotan()
asin())
acotan()
atan()
cosh() tanh()
I=
sin())
cos()
cotan()
asin()
sinh()
atan() acotan
cosh() tanh() cotanh()
Degrees O Radians
B
Degrees O Radians
Part (b) What is the conductivity of this wire, in inverse Ohms per meter?
0
tan()) π (
acos() E ^^^L
sinh()
cotanh()
g
L
P
Y
d
h
m
r
tan() π
acos() E ^^^^
π
E
1
Part (c) Give an expression for the current density in the wire if an electric field E is passing through it. Write this in terms of the resistivity and the other
variables in the problem.
J=
n
R
(
^^^
sin()
cos()
cotan()
asin()
atan() acotan()
cosh()
+
+
7 8 9
4 5 6
1 2 3
0
END
NO BACKSPACE DEL CLEAR
Part (d) Calculate the current in the wire, in milliamperes, if the field strength is 5.28 V/m.
-
END
NO…
Chapter 25 Solutions
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
Ch. 25 - Prob. 1PCh. 25 - Prob. 2PCh. 25 - Prob. 3PCh. 25 - Prob. 4PCh. 25 - Prob. 5PCh. 25 - Prob. 6PCh. 25 - Prob. 7PCh. 25 - Prob. 8PCh. 25 - Prob. 9PCh. 25 - Prob. 10P
Ch. 25 - Prob. 11PCh. 25 - Prob. 12PCh. 25 - Prob. 13PCh. 25 - Prob. 14PCh. 25 - Prob. 15PCh. 25 - Prob. 16PCh. 25 - Prob. 17PCh. 25 - Prob. 18PCh. 25 - Prob. 19PCh. 25 - Prob. 20PCh. 25 - Prob. 21PCh. 25 - Prob. 22PCh. 25 - Prob. 23PCh. 25 - Prob. 24PCh. 25 - Prob. 25PCh. 25 - Prob. 26PCh. 25 - Prob. 27PCh. 25 - Prob. 28PCh. 25 - Prob. 29PCh. 25 - Prob. 30PCh. 25 - Prob. 31PCh. 25 - Prob. 32PCh. 25 - Prob. 33PCh. 25 - Prob. 34PCh. 25 - Prob. 35PCh. 25 - Prob. 36PCh. 25 - Prob. 37PCh. 25 - Prob. 38PCh. 25 - Prob. 39PCh. 25 - Prob. 40PCh. 25 - Prob. 41PCh. 25 - Prob. 42PCh. 25 - Prob. 43PCh. 25 - Prob. 44PCh. 25 - Prob. 45PCh. 25 - Prob. 46PCh. 25 - Prob. 47PCh. 25 - Prob. 48PCh. 25 - Prob. 49PCh. 25 - Prob. 50PCh. 25 - Prob. 51PCh. 25 - Prob. 52PCh. 25 - Prob. 53PCh. 25 - Prob. 54PCh. 25 - Prob. 55PCh. 25 - Prob. 56PCh. 25 - Prob. 57PCh. 25 - Prob. 58PCh. 25 - Prob. 59PCh. 25 - Prob. 60PCh. 25 - Prob. 61PCh. 25 - Prob. 62PCh. 25 - Prob. 63PCh. 25 - Prob. 64PCh. 25 - Prob. 65PCh. 25 - Prob. 66PCh. 25 - Prob. 67PCh. 25 - Prob. 68PCh. 25 - Prob. 69PCh. 25 - Prob. 70PCh. 25 - Prob. 71PCh. 25 - Prob. 72PCh. 25 - Prob. 73PCh. 25 - Prob. 74PCh. 25 - Prob. 75PCh. 25 - Prob. 76PCh. 25 - Prob. 77PCh. 25 - Prob. 78PCh. 25 - Prob. 79PCh. 25 - Prob. 80PCh. 25 - Prob. 81PCh. 25 - Prob. 82PCh. 25 - Prob. 83PCh. 25 - Prob. 84PCh. 25 - Prob. 85PCh. 25 - Prob. 86PCh. 25 - Prob. 87PCh. 25 - Prob. 88PCh. 25 - Prob. 89PCh. 25 - Prob. 90PCh. 25 - Prob. 91PCh. 25 - Prob. 92PCh. 25 - Prob. 93PCh. 25 - Prob. 94PCh. 25 - Prob. 95PCh. 25 - Prob. 96PCh. 25 - Prob. 97PCh. 25 - Prob. 98PCh. 25 - Prob. 99PCh. 25 - Prob. 100PCh. 25 - Prob. 101PCh. 25 - Prob. 102PCh. 25 - Prob. 103PCh. 25 - Prob. 104PCh. 25 - Prob. 105PCh. 25 - Prob. 106PCh. 25 - Prob. 107PCh. 25 - Prob. 108PCh. 25 - Prob. 109PCh. 25 - Prob. 110PCh. 25 - Prob. 111PCh. 25 - Prob. 112PCh. 25 - Prob. 113PCh. 25 - Prob. 114PCh. 25 - Prob. 115PCh. 25 - Prob. 116PCh. 25 - Prob. 117PCh. 25 - Prob. 118PCh. 25 - Prob. 119PCh. 25 - Prob. 120P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Wire C and wire D are made from the same material of resistivity p- 2.0 x 10 am. The length and radius of wire Care Le 1.0m and re 2.00 mm, and those of wire D are Le- 0.50.m and ro-0.75 mm. The wires are joined as shown in the figure. What is the resistance R between points 1 and 2?arrow_forwardThe figure shows cross sections through three long conductors of the same length andmaterial, with square cross sections of edge lengths as shown. Conductor B fits snugly withinconductor A, and conductor C fits snugly within conductor B. Rank the resistance of A, B, and C?arrow_forwardTwo copper wires (call them A and B) both have length 19.0 m but wire A has a radius 7.045 mm and wire B has a radius 2.668 mm. What is the ratio of the resistances of the two wires? The resistivity of copper is 1.68x10-8 Ω/m. Report your answer to three decimal places.arrow_forward
- The radius r of a wire grows linearly with its length I according to r(2) = a+x, where z is the distance from the thinner end of the wire with radius a. Express the resistance as a function of the resistivity of the material p, the length of the wire I and the radii a and b. View Available Hint(s ?arrow_forwardA cylindrical conductor with resistivity ρ, length L, and radius r , has resistance R0=302Ω. If the resistivity and the length of the conductor both have their original values, but instead the radius of the conductor is increased by a factor of 5, what is the new value, in ohms, of the resistance?arrow_forwardA copper (resistivity = 1.72 EXP-8 Ω.m) conductor with a square cross section, 1.0 mm on a side is 100 m long and is initially 20oC. 1. If the temperature coefficient (a) of copper is 0.00393 per degree Celsius, what is the change in resistance of the copper conductor if the temperature is increased to 100 degrees Celsius? 2. What is the resistance of this conductor?arrow_forward
- Two identical resistors of R0 = 98 Ω are connected head-to-tail. Express the resistance R0 of one of the resistors in terms of the resistivity ρ, length L, and the cross section area A. Calculate the total resistance R of the two resistors in ohms.arrow_forwardAn iron wire has a diameter 6.05 mm and resistivity 9.71x 10-8 Qm. What will be the length of this wire to make a resistance of 400. What will be the new resistance, if the radius is doubled? (a) Length of the wire (in m) = (b) Resistance of the wire (in = Finish attempt .. NG 4) GO f2 f3 O f4 O f6 D f7 ) f8 f9 * f10 3 $ &y 4 7 8. R 28 Y Se D[ F 1 GY H i K -u ) 43 ) # 3arrow_forwardThe resistivity of silver ρ = 1.61 x 10-8 Ω.m. If you have a length of silver wire that is 3.15 m in length, and that has a cross-sectional diameter of 482 μm, what is the resistance of that wire (in Ω, or Ohms)?arrow_forward
- Two identical resistors of R0=32 omega are connected head to tail. Part (a) Express the resistance R0 of one of the resistors in terms of the resistivity, length L, and the cross section area A. Part (b) calculate the total resistance R of the two resistors in ohms.arrow_forwardPlease asaparrow_forwardWhat is the resistance (in units of 2) of a wire made of a material with a resistivity of 3.2 x 10-8.m, if its length is 49.1 m and its diameter is 0.50 mm? Solect ono:arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Electric Fields: Crash Course Physics #26; Author: CrashCourse;https://www.youtube.com/watch?v=mdulzEfQXDE;License: Standard YouTube License, CC-BY