(a) Interpretation: Between P 15 29 a n d P 15 33 the one that emits β + and one that emits β − is to be determined. Concept introduction: Beta-decay is a subtype of radioactive decay that emits beta particles. In this case, a proton of the nucleus of a radioactive atom is converted into a neutron and releases a positron and an electron. Similarly, in case of β − decay, a neutron of a nucleus turns into a proton.

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Answer 1

Question

Chapter 25, Problem 43E

Interpretation Introduction

(a)

Interpretation:

Between P1529andP1533 the one that emits β+ and one that emits β− is to be determined.

Concept introduction:

Beta-decay is a subtype of radioactive decay that emits beta particles. In this case, a proton of the nucleus of a radioactive atom is converted into a neutron and releases a positron and an electron. Similarly, in case of β− decay, a neutron of a nucleus turns into a proton.

Interpretation Introduction

(b)

Interpretation:

Between I53120andI53134 the one that emits β+ and one that emits β− is to be determined.

Concept introduction:

Radioactive decay is subdivided into β+ and β− decay. In case of a β+ decaying proton inside a nucleus of a radioactive atom is converted into a neutron and releases a positron with an electron neutrino. And in case of β− decay, a neutron of a nucleus turns into a proton.

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Using reaction free energy to predict equilibrium composition Consider the following equilibrium: 2NOCI (g) 2NO (g) + Cl2 (g) AGº =41. kJ Now suppose a reaction vessel is filled with 4.50 atm of nitrosyl chloride (NOCI) and 6.38 atm of chlorine (C12) at 212. °C. Answer the following questions about this system: ? rise Under these conditions, will the pressure of NOCI tend to rise or fall? x10 fall Is it possible to reverse this tendency by adding NO? In other words, if you said the pressure of NOCI will tend to rise, can that be changed to a tendency to fall by adding NO? Similarly, if you said the pressure of NOCI will tend to fall, can that be changed to a tendency to rise by adding NO? yes no If you said the tendency can be reversed in the second question, calculate the minimum pressure of NO needed to reverse it. Round your answer to 2 significant digits. 0.035 atm ✓ G 00. 18 Ar

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Answer 2

Question

Chapter 25, Problem 43E

Interpretation Introduction

(a)

Interpretation:

Between P1529andP1533 the one that emits β+ and one that emits β− is to be determined.

Concept introduction:

Beta-decay is a subtype of radioactive decay that emits beta particles. In this case, a proton of the nucleus of a radioactive atom is converted into a neutron and releases a positron and an electron. Similarly, in case of β− decay, a neutron of a nucleus turns into a proton.

Interpretation Introduction

(b)

Interpretation:

Between I53120andI53134 the one that emits β+ and one that emits β− is to be determined.

Concept introduction:

Radioactive decay is subdivided into β+ and β− decay. In case of a β+ decaying proton inside a nucleus of a radioactive atom is converted into a neutron and releases a positron with an electron neutrino. And in case of β− decay, a neutron of a nucleus turns into a proton.

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Answer 3

Question

Chapter 25, Problem 43E

Interpretation Introduction

(a)

Interpretation:

Between P1529andP1533 the one that emits β+ and one that emits β− is to be determined.

Concept introduction:

Beta-decay is a subtype of radioactive decay that emits beta particles. In this case, a proton of the nucleus of a radioactive atom is converted into a neutron and releases a positron and an electron. Similarly, in case of β− decay, a neutron of a nucleus turns into a proton.

Interpretation Introduction

(b)

Interpretation:

Between I53120andI53134 the one that emits β+ and one that emits β− is to be determined.

Concept introduction:

Radioactive decay is subdivided into β+ and β− decay. In case of a β+ decaying proton inside a nucleus of a radioactive atom is converted into a neutron and releases a positron with an electron neutrino. And in case of β− decay, a neutron of a nucleus turns into a proton.

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Answer 4

Question

Chapter 25, Problem 43E

Interpretation Introduction

(a)

Interpretation:

Between P1529andP1533 the one that emits β+ and one that emits β− is to be determined.

Concept introduction:

Beta-decay is a subtype of radioactive decay that emits beta particles. In this case, a proton of the nucleus of a radioactive atom is converted into a neutron and releases a positron and an electron. Similarly, in case of β− decay, a neutron of a nucleus turns into a proton.

Interpretation Introduction

(b)

Interpretation:

Between I53120andI53134 the one that emits β+ and one that emits β− is to be determined.

Concept introduction:

Radioactive decay is subdivided into β+ and β− decay. In case of a β+ decaying proton inside a nucleus of a radioactive atom is converted into a neutron and releases a positron with an electron neutrino. And in case of β− decay, a neutron of a nucleus turns into a proton.

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Answer 5

Chapter 25, Problem 43E

Interpretation Introduction

(a)

Interpretation:

Between P1529andP1533 the one that emits β+ and one that emits β− is to be determined.

Concept introduction:

Beta-decay is a subtype of radioactive decay that emits beta particles. In this case, a proton of the nucleus of a radioactive atom is converted into a neutron and releases a positron and an electron. Similarly, in case of β− decay, a neutron of a nucleus turns into a proton.

Interpretation Introduction

(b)

Interpretation:

Between I53120andI53134 the one that emits β+ and one that emits β− is to be determined.

Concept introduction:

Radioactive decay is subdivided into β+ and β− decay. In case of a β+ decaying proton inside a nucleus of a radioactive atom is converted into a neutron and releases a positron with an electron neutrino. And in case of β− decay, a neutron of a nucleus turns into a proton.

Answer 6

Chapter 25, Problem 43E

Interpretation Introduction

(a)

Interpretation:

Between P1529andP1533 the one that emits β+ and one that emits β− is to be determined.

Concept introduction:

Beta-decay is a subtype of radioactive decay that emits beta particles. In this case, a proton of the nucleus of a radioactive atom is converted into a neutron and releases a positron and an electron. Similarly, in case of β− decay, a neutron of a nucleus turns into a proton.

Answer 7

Chapter 25, Problem 43E

Interpretation Introduction

(a)

Interpretation:

Between P1529andP1533 the one that emits β+ and one that emits β− is to be determined.

Concept introduction:

Beta-decay is a subtype of radioactive decay that emits beta particles. In this case, a proton of the nucleus of a radioactive atom is converted into a neutron and releases a positron and an electron. Similarly, in case of β− decay, a neutron of a nucleus turns into a proton.

Answer 8

Interpretation Introduction

(b)

Interpretation:

Between I53120andI53134 the one that emits β+ and one that emits β− is to be determined.

Concept introduction:

Radioactive decay is subdivided into β+ and β− decay. In case of a β+ decaying proton inside a nucleus of a radioactive atom is converted into a neutron and releases a positron with an electron neutrino. And in case of β− decay, a neutron of a nucleus turns into a proton.

Answer 9

Interpretation Introduction

(b)

Interpretation:

Between I53120andI53134 the one that emits β+ and one that emits β− is to be determined.

Concept introduction:

Radioactive decay is subdivided into β+ and β− decay. In case of a β+ decaying proton inside a nucleus of a radioactive atom is converted into a neutron and releases a positron with an electron neutrino. And in case of β− decay, a neutron of a nucleus turns into a proton.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 25 - Prob. 1E Ch. 25 - Prob. 2E Ch. 25 - Prob. 3E Ch. 25 - Prob. 4E Ch. 25 - Prob. 5E Ch. 25 - Prob. 6E Ch. 25 - Prob. 7E Ch. 25 - Prob. 8E Ch. 25 - Prob. 9E Ch. 25 - Prob. 10E

Solution Summary: The author explains that beta-decay is a subtype of radioactive decay that emits beta particles.

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Chapter 25 Solutions