Explanation Given data : Consider that radio station broadcasts the power 10 W of electromagnetic waves. Explanation: Consider the following expression that relates the intensity of wave with electric field amplitude. I = c ε 0 E 0 2 2 (1) Here, ε 0 is permittivity of free space, which is generally known as 8.85 × 10 − 12 C 2 N ⋅ m 2 , and c is the velocity of light in vacuum, which is generally 3 × 10 8 m s . Consider the following expression that relates the intensity of wave with power and area of cross-section. I = P A (2) Here, A is cross-sectional area of the spherical space, which is generally known as 4 π r 2 . Consider that r is the distance from the antenna. Compare equations (1) and (2). P A = c ε 0 E 0 2 2 Substitute 4 π r 2 for A , P 4 π r 2 = c ε 0 E 0 2 2 Re-arrange the equation. r 2 = 2 P 4 π c ε 0 E 0 2 Apply square root on both sides of the equation. r = 2 P 4 π c ε 0 E 0 2 Substitute 10 W for P , 2.0 × 10 − 3 V m for E 0 , 3 × 10 8 m s for c , and 8

Mastering Physics with Pearson eText -- Standalone Access Card -- for College Physics: A Strategic Approach (3rd Edition)

3rd Edition

ISBN: 9780321908803

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

See similar textbooks

Question

Chapter 25, Problem 36P

To determine

To find: The distance from the antenna when the electric field amplitude is 2.0×10−3 Vm .

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 25, Problem 35P

Chapter 25, Problem 37P

Students have asked these similar questions

For number 11 please sketch the harmonic on graphing paper.

# E 94 20 13. Time a) What is the frequency of the above wave? b) What is the period? c) Highlight the second cycle d) Sketch the sine wave of the second harmonic of this wave % 7 & 5 6 7 8 * ∞ Y U 9 0 0 P 150

Show work using graphing paper

Chapter 25 Solutions

Mastering Physics with Pearson eText -- Standalone Access Card -- for College Physics: A Strategic Approach (3rd Edition)

Ch. 25 - Prob. 1CQ Ch. 25 - The rapid vibration accompanying the swimming...Ch. 25 - Prob. 3CQ Ch. 25 - Prob. 4CQ Ch. 25 - Prob. 5CQ Ch. 25 - Prob. 6CQ Ch. 25 - The power lines that run through your neighborhood...Ch. 25 - The magnetic flux passing through a coil of wire...Ch. 25 - There is a counterclockwise induced current in the...Ch. 25 - A magnet dropped through a clear plastic tube...

Ch. 25 - The conducting loop in Figure Q25.11 is moving...Ch. 25 - Figure Q25.12 shows two concentric, conducting...Ch. 25 - Figure Q25.13 shows conducting loops next to each...Ch. 25 - Two loops of wire are stacked vertically, one...Ch. 25 - Prob. 15CQ Ch. 25 - A bar magnet is pushed toward a loop of wire, as...Ch. 25 - Prob. 17CQ Ch. 25 - A metal wire is resting on a U-shaped conducting...Ch. 25 - Prob. 19CQ Ch. 25 - Old-fashioned roof-mounted television antennas...Ch. 25 - An AM radio detects the oscillating magnetic field...Ch. 25 - Prob. 22CQ Ch. 25 - Prob. 23CQ Ch. 25 - The frequency of a beam of light is increased but...Ch. 25 - Arc welding uses electric current to make an...Ch. 25 - A circular loop of wire has an area of 0.30 m2. It...Ch. 25 - In Figure Q25.27, a square loop is rotating in the...Ch. 25 - A diamond-shaped loop of wire is pulled at a...Ch. 25 - Figure Q25.29 shows a triangular loop of wire in a...Ch. 25 - A device called a flip coil can be used to measure...Ch. 25 - The electromagnetic waves that carry FM radio...Ch. 25 - The beam from a laser is focused with a lens,...Ch. 25 - A spacecraft in orbit around the moon measures its...Ch. 25 - A 6.0 mW vertically polarized laser beam passes...Ch. 25 - Communication with submerged submarines via radio...Ch. 25 - Prob. 36MCQ Ch. 25 - Prob. 1P Ch. 25 - Prob. 2P Ch. 25 - A l0-cm-long wire is pulled along a U-shaped...Ch. 25 - Figure P25.4 shows a 15-cm-long metal rod pulled...Ch. 25 - Prob. 5P Ch. 25 - In the rainy season, the Amazon flows fast and...Ch. 25 - A delivery truck with 2.8-m-high aluminum sides is...Ch. 25 - Prob. 8P Ch. 25 - Prob. 9P Ch. 25 - Prob. 10P Ch. 25 - Prob. 11P Ch. 25 - At a typical location in the United States, the...Ch. 25 - Prob. 13P Ch. 25 - A magnet and a coil are oriented as shown in...Ch. 25 - A 1000-turn coil of wire 2.0 cm in diameter is in...Ch. 25 - Figure P25.I6 shows a 100-turn coil of wire of...Ch. 25 - Figure P25.17 shows a 10-cm-diameter loop in three...Ch. 25 - The plane of a loop of wire is perpendicular to a...Ch. 25 - Prob. 19P Ch. 25 - Prob. 20P Ch. 25 - Prob. 21P Ch. 25 - A 5.0-cm-diameter loop of wire has resistance 1.2...Ch. 25 - Prob. 23P Ch. 25 - Prob. 24P Ch. 25 - Prob. 25P Ch. 25 - Prob. 26P Ch. 25 - A microwave oven operates at 2.4 GHz with an...Ch. 25 - The maximum allowed leakage of microwave radiation...Ch. 25 - Prob. 29P Ch. 25 - Prob. 30P Ch. 25 - At what distance from a 10 mW point source of...Ch. 25 - Prob. 32P Ch. 25 - A radio antenna broadcasts a 1.0 MHz radio wave...Ch. 25 - A 200 MW laser pulse is focused with a lens to a...Ch. 25 - The intensity of a polarized electromagnetic wave...Ch. 25 - Prob. 36P Ch. 25 - Prob. 37P Ch. 25 - Prob. 38P Ch. 25 - The polarization of a helium-neon laser can change...Ch. 25 - Prob. 40P Ch. 25 - Prob. 41P Ch. 25 - Prob. 42P Ch. 25 - One recent study has shown that x rays with a...Ch. 25 - Prob. 44P Ch. 25 - Prob. 45P Ch. 25 - Prob. 46P Ch. 25 - Prob. 47P Ch. 25 - Prob. 48P Ch. 25 - Prob. 49P Ch. 25 - A particular species of copepod, a small marine...Ch. 25 - Prob. 51P Ch. 25 - Prob. 52P Ch. 25 - While using a dimmer switch to investigate a new...Ch. 25 - Prob. 54P Ch. 25 - Prob. 55P Ch. 25 - A python can detect thermal radiation with...Ch. 25 - If astronomers look toward any point in outer...Ch. 25 - A 100-turn, 2.0-cm diameter coil is at rest in a...Ch. 25 - A 25-turn, 10.0-cm-diameter coil is oriented in a...Ch. 25 - People immersed in strong unchanging magnetic...Ch. 25 - Prob. 61GP Ch. 25 - Prob. 62GP Ch. 25 - A 20-cm-long, zero-resistance wire is pulled...Ch. 25 - A TMS (transeranial magnetic stimulation) device...Ch. 25 - The 10-cm-wide, zero-resistance wire shown in...Ch. 25 - Experiments to study vision often need to track...Ch. 25 - A LASIK vision correction system uses a laser that...Ch. 25 - When the Voyager 2 spacecraft passed Neptune in...Ch. 25 - A new cordless phone emits 4.0 mW at 5.8 GHz. The...Ch. 25 - In reading the instruction manual that came with...Ch. 25 - Unpolarized light passes through a vertical...Ch. 25 - Prob. 73GP Ch. 25 - Prob. 74GP Ch. 25 - What is the wavelength of 27 MHz radio waves? A....Ch. 25 - If the frequency of the radio waves is increased,...Ch. 25 - Prob. 77MSPP Ch. 25 - The metal detector will not detect insulators...Ch. 25 - A metal detector can detect the presence of metal...Ch. 25 - Which of the following changes would not produce a...

Knowledge Booster

The distance from the antenna when the electric field amplitude is 2.0 × 10 − 3 V m .

Solution Summary: The author explains how to find the distance from the antenna when the electric field amplitude is 2.0times 10-3

To find: The distance from the antenna when the electric field amplitude is 2.0×10−3 Vm .

Want to see the full answer?

Chapter 25 Solutions