Explanation Given data: B L = 2 T . B R = 1 T . Length of magnetic field on left is 20 cm. Length of magnetic field on right is 20 cm Breadth of magnetic field is 20 cm. Formula used: Consider the expression of magnetic flux. Φ = B A cos θ (1) Here, B is the magnetic field strength, A is the area, and θ is the angle between magnetic field and area. Explanation: Refer to Figure P25.10 in the textbook. Since the loop is in the rectangular shape, the area of the magnetic field present on left side is, A = Length ×Breadth (2) Substitute 20 cm for Length and 20 cm for Breadth in equation (2), A L = 20 cm ×20 cm = 0 .2 m × 0 .2 m = 0 .04 m 2 Consider the area to be into the page. So, the angle made by B L with area is 0 ° because B L is also into the page. Magnetic flux on left side is calculated as follows. Substitute 2 T for B , 0 ° for θ , and 0 .04 m 2 for A in equation (1), Φ L = 2 T × 0 .04 m 2 × cos 0 ° = 0.08 Wb Area of the magnetic field present on right side is calculated as follows. Substitute 20 cm for Length and 20 cm for Breadth in equation (2), A R = 20 cm ×20 cm = 0

Mastering Physics with Pearson eText -- Standalone Access Card -- for College Physics: A Strategic Approach (3rd Edition)

3rd Edition

ISBN: 9780321908803

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

See similar textbooks

Question

Chapter 25, Problem 10P

To determine

The magnetic flux through the loop.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 25, Problem 9P

Chapter 25, Problem 11P

Students have asked these similar questions

No chatgpt pls will upvote

a cubic foot of argon at 20 degrees celsius is isentropically compressed from 1 atm to 425 KPa. What is the new temperature and density?

Calculate the variance of the calculated accelerations. The free fall height was 1753 mm. The measured release and catch times were: 222.22 800.00 61.11 641.67 0.00 588.89 11.11 588.89 8.33 588.89 11.11 588.89 5.56 586.11 2.78 583.33 Give in the answer window the calculated repeated experiment variance in m/s2.

Chapter 25 Solutions

Mastering Physics with Pearson eText -- Standalone Access Card -- for College Physics: A Strategic Approach (3rd Edition)

Ch. 25 - Prob. 1CQ Ch. 25 - The rapid vibration accompanying the swimming...Ch. 25 - Prob. 3CQ Ch. 25 - Prob. 4CQ Ch. 25 - Prob. 5CQ Ch. 25 - Prob. 6CQ Ch. 25 - The power lines that run through your neighborhood...Ch. 25 - The magnetic flux passing through a coil of wire...Ch. 25 - There is a counterclockwise induced current in the...Ch. 25 - A magnet dropped through a clear plastic tube...

Ch. 25 - The conducting loop in Figure Q25.11 is moving...Ch. 25 - Figure Q25.12 shows two concentric, conducting...Ch. 25 - Figure Q25.13 shows conducting loops next to each...Ch. 25 - Two loops of wire are stacked vertically, one...Ch. 25 - Prob. 15CQ Ch. 25 - A bar magnet is pushed toward a loop of wire, as...Ch. 25 - Prob. 17CQ Ch. 25 - A metal wire is resting on a U-shaped conducting...Ch. 25 - Prob. 19CQ Ch. 25 - Old-fashioned roof-mounted television antennas...Ch. 25 - An AM radio detects the oscillating magnetic field...Ch. 25 - Prob. 22CQ Ch. 25 - Prob. 23CQ Ch. 25 - The frequency of a beam of light is increased but...Ch. 25 - Arc welding uses electric current to make an...Ch. 25 - A circular loop of wire has an area of 0.30 m2. It...Ch. 25 - In Figure Q25.27, a square loop is rotating in the...Ch. 25 - A diamond-shaped loop of wire is pulled at a...Ch. 25 - Figure Q25.29 shows a triangular loop of wire in a...Ch. 25 - A device called a flip coil can be used to measure...Ch. 25 - The electromagnetic waves that carry FM radio...Ch. 25 - The beam from a laser is focused with a lens,...Ch. 25 - A spacecraft in orbit around the moon measures its...Ch. 25 - A 6.0 mW vertically polarized laser beam passes...Ch. 25 - Communication with submerged submarines via radio...Ch. 25 - Prob. 36MCQ Ch. 25 - Prob. 1P Ch. 25 - Prob. 2P Ch. 25 - A l0-cm-long wire is pulled along a U-shaped...Ch. 25 - Figure P25.4 shows a 15-cm-long metal rod pulled...Ch. 25 - Prob. 5P Ch. 25 - In the rainy season, the Amazon flows fast and...Ch. 25 - A delivery truck with 2.8-m-high aluminum sides is...Ch. 25 - Prob. 8P Ch. 25 - Prob. 9P Ch. 25 - Prob. 10P Ch. 25 - Prob. 11P Ch. 25 - At a typical location in the United States, the...Ch. 25 - Prob. 13P Ch. 25 - A magnet and a coil are oriented as shown in...Ch. 25 - A 1000-turn coil of wire 2.0 cm in diameter is in...Ch. 25 - Figure P25.I6 shows a 100-turn coil of wire of...Ch. 25 - Figure P25.17 shows a 10-cm-diameter loop in three...Ch. 25 - The plane of a loop of wire is perpendicular to a...Ch. 25 - Prob. 19P Ch. 25 - Prob. 20P Ch. 25 - Prob. 21P Ch. 25 - A 5.0-cm-diameter loop of wire has resistance 1.2...Ch. 25 - Prob. 23P Ch. 25 - Prob. 24P Ch. 25 - Prob. 25P Ch. 25 - Prob. 26P Ch. 25 - A microwave oven operates at 2.4 GHz with an...Ch. 25 - The maximum allowed leakage of microwave radiation...Ch. 25 - Prob. 29P Ch. 25 - Prob. 30P Ch. 25 - At what distance from a 10 mW point source of...Ch. 25 - Prob. 32P Ch. 25 - A radio antenna broadcasts a 1.0 MHz radio wave...Ch. 25 - A 200 MW laser pulse is focused with a lens to a...Ch. 25 - The intensity of a polarized electromagnetic wave...Ch. 25 - Prob. 36P Ch. 25 - Prob. 37P Ch. 25 - Prob. 38P Ch. 25 - The polarization of a helium-neon laser can change...Ch. 25 - Prob. 40P Ch. 25 - Prob. 41P Ch. 25 - Prob. 42P Ch. 25 - One recent study has shown that x rays with a...Ch. 25 - Prob. 44P Ch. 25 - Prob. 45P Ch. 25 - Prob. 46P Ch. 25 - Prob. 47P Ch. 25 - Prob. 48P Ch. 25 - Prob. 49P Ch. 25 - A particular species of copepod, a small marine...Ch. 25 - Prob. 51P Ch. 25 - Prob. 52P Ch. 25 - While using a dimmer switch to investigate a new...Ch. 25 - Prob. 54P Ch. 25 - Prob. 55P Ch. 25 - A python can detect thermal radiation with...Ch. 25 - If astronomers look toward any point in outer...Ch. 25 - A 100-turn, 2.0-cm diameter coil is at rest in a...Ch. 25 - A 25-turn, 10.0-cm-diameter coil is oriented in a...Ch. 25 - People immersed in strong unchanging magnetic...Ch. 25 - Prob. 61GP Ch. 25 - Prob. 62GP Ch. 25 - A 20-cm-long, zero-resistance wire is pulled...Ch. 25 - A TMS (transeranial magnetic stimulation) device...Ch. 25 - The 10-cm-wide, zero-resistance wire shown in...Ch. 25 - Experiments to study vision often need to track...Ch. 25 - A LASIK vision correction system uses a laser that...Ch. 25 - When the Voyager 2 spacecraft passed Neptune in...Ch. 25 - A new cordless phone emits 4.0 mW at 5.8 GHz. The...Ch. 25 - In reading the instruction manual that came with...Ch. 25 - Unpolarized light passes through a vertical...Ch. 25 - Prob. 73GP Ch. 25 - Prob. 74GP Ch. 25 - What is the wavelength of 27 MHz radio waves? A....Ch. 25 - If the frequency of the radio waves is increased,...Ch. 25 - Prob. 77MSPP Ch. 25 - The metal detector will not detect insulators...Ch. 25 - A metal detector can detect the presence of metal...Ch. 25 - Which of the following changes would not produce a...

Knowledge Booster

The magnetic flux through the loop.

Solution Summary: The author explains that the magnetic flux through the loop is 0.040 Wb.

The magnetic flux through the loop.

Want to see the full answer?

Chapter 25 Solutions