Degarmo's Materials And Processes In Manufacturing
13th Edition
ISBN: 9781119492825
Author: Black, J. Temple, Kohser, Ronald A., Author.
Publisher: Wiley,
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Textbook Question
Chapter 25, Problem 2P
How much time will be required to drill the hole in Problem 1 using the HSS drill?
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Students have asked these similar questions
You are working as an engineer in a bearing systems design company. The flow of
lubricant inside a hydrodynamic bearing (p = 0.001 kg m-1 s-1) can be approximated
as a parallel, steady, two-dimensional, incompressible flow between two parallel plates.
The top plate, representing the moving part of the bearing, travels at a constant speed,
U, while the bottom plate remains stationary (Figure Q1). The plates are separated by
a distance of 2h = 1 cm and are W = 20 cm wide. Their length is L = 10 cm. By
applying the above approximations to the Navier-Stokes equations and assuming that
end effects can be neglected, the horizontal velocity profile can be shown to be
y = +h
I
2h = 1 cm
x1
y = -h
u(y)
1 dP
2μ dx
-y² + Ay + B
moving plate
stationary plate
U
2
I2
L = 10 cm
Figure Q1: Flow in a hydrodynamic bearing. The plates extend a width, W = 20 cm,
into the page.
Question 1
You are working as an engineer in a bearing systems design company. The flow of
lubricant inside a hydrodynamic bearing (µ = 0.001 kg m¯¹ s¯¹) can be approximated
as a parallel, steady, two-dimensional, incompressible flow between two parallel plates.
The top plate, representing the moving part of the bearing, travels at a constant speed,
U, while the bottom plate remains stationary (Figure Q1). The plates are separated by
a distance of 2h = 1 cm and are W = 20 cm wide. Their length is L = 10 cm. By
applying the above approximations to the Navier-Stokes equations and assuming that
end effects can be neglected, the horizontal velocity profile can be shown to be
1 dP
u(y)
=
2μ dx
-y² + Ay + B
y= +h
Ꮖ
2h=1 cm
1
x1
y = −h
moving plate
stationary plate
2
X2
L = 10 cm
Figure Q1: Flow in a hydrodynamic bearing. The plates extend a width, W = 20 cm,
into the page.
(a) By considering the appropriate boundary conditions, show that the constants take
the following forms:
U
U
1 dP
A =…
Question 2
You are an engineer working in the propulsion team for a supersonic civil transport
aircraft driven by a turbojet engine, where you have oversight of the design for the
engine intake and the exhaust nozzle, indicated in Figure Q2a. The turbojet engine can
operate when provided with air flow in the Mach number range, 0.60 to 0.80. You are
asked to analyse a condition where the aircraft is flying at 472 m/s at an altitude of
14,000 m. For all parts of the question, you can assume that the flow path of air through
the engine has a circular cross section.
(a)
← intake
normal
shock
472 m/s
A B
(b)
50 m/s
H
472 m/s
B
engine
altitude: 14,000 m
exhaust nozzle
E
F
exit to
atmosphere
diameter: DE = 0.30 m
E
F
diameter: DF = 0.66 m
Figure Q2: Propulsion system for a supersonic aircraft.
a) When the aircraft is at an altitude of 14,000 m, use the International Standard
Atmosphere in the Module Data Book to state the local air pressure and tempera-
ture. Thus show that the aircraft speed…
Chapter 25 Solutions
Degarmo's Materials And Processes In Manufacturing
Ch. 25 - What functions are performed by the flutes on a...Ch. 25 - What determines the rake angle of a drill? See...Ch. 25 - Basically, what determines what helix angle a...Ch. 25 - When a large-diameter hole is to be drilled, why...Ch. 25 - Equation 25.4 for the MRR for drilling can be...Ch. 25 - Are the recommended surface speeds for spade...Ch. 25 - What can happen when an improperly ground drill is...Ch. 25 - Why are many drilled holes oversize with respect...Ch. 25 - What are the two primary functions of a...Ch. 25 - What is the function of the margins on a twist...
Ch. 25 - What factors tend to cause a drill to drift off...Ch. 25 - The drill shown in Figure 25.13 has coolant...Ch. 25 - Prob. 13RQCh. 25 - Why do cutting fluids for drilling usually have...Ch. 25 - How does a gang-drilling machine differ from a...Ch. 25 - Prob. 16RQCh. 25 - How does the thrust force vary with feed? Why?Ch. 25 - Holding the workpiece by hand when drilling is not...Ch. 25 - Prob. 19RQCh. 25 - In terms of thrust, what is unusual about the...Ch. 25 - Prob. 21RQCh. 25 - Prob. 22RQCh. 25 - What are the primary purposes of reaming?Ch. 25 - What are the advantages of shell reamers?Ch. 25 - A drill that operated satisfactorily for drilling...Ch. 25 - What precautionary procedures should be used when...Ch. 25 - What is the advantage of a spade drill? Is it...Ch. 25 - Prob. 28RQCh. 25 - Why does drill feed increase with drill size?Ch. 25 - Suppose you specified a drilling feed rate that...Ch. 25 - Suppose you wanted to drill a 1.5-in.-diameter...Ch. 25 - How much time will be required to drill the hole...Ch. 25 - What is the metal removal rate when a...Ch. 25 - If the specific horsepower for the steel in...Ch. 25 - If the specific power of an AISI 1020 steel of...Ch. 25 - Prob. 6PCh. 25 - Assume that you are drilling eight holes, equally...Ch. 25 - What machining difficulties should this process...Ch. 25 - Why were the distances between the holes too...
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