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In Exercises 1–6, solve the equation Ax = b by using the LU factorization given for A. In Exercises 1 and 2, also solve Ax = b by ordinary row reduction.
2.
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Linear Algebra and Its Applications (5th Edition)
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- For Exercises 19–26, simplify each expression and write the result in standard form, a + bi. 8 + 3i 19. 4 + 5i 20. -4 - 6i 21. 9 - 15i 22. 14 6. -2 -3 -18 + V-48 23. - 20 + V-50 14 - V-98 25. - 10 + V-125 24. 26. 4 10 -7arrow_forwardIn Problems 57–68, solve each equation in the real number system. 57. x* - x + 2x? - 4x - 8 = 0 58. 2x + 3x? + 2x + 3 = 0 59. 3x + 4x? - 7x + 2 = 0 60. 2x – 3x –- 3x – 5 = 0 234 CHAPTER 4 Polynomial and Rational Functions 61. 3x – x? - 15x + 5 = 0 62. 2x - 11x² + 10x + 8 = 0 63. x* + 4x + 2r? - x + 6 = 0 64. x* - 2x + 10x? - 1&r + 9 == (0 8 +x +1 = 0 65. x 66. х + + 3x - 2 = 0 67. 2x - 19x + 57x - 64x + 20 = 0 68. 2x + x - 24x + 20x + 16 = 0arrow_forwardSolve, z² – 4z + 5 = 0 Given that z1 = 3 + i, z2 = 4 – 3i, Z3 = -1+ 2i and z4 = -2 – 5i, determine in the form a + ib, where a, b E R, (real numbers), the following: (i) Z1 + Z2 ii) Z3Z4arrow_forward
- part C Darrow_forwardIn Exercises 65–74, factor by grouping to obtain the difference of two squares. 6x + 9 – y? 12x + 36 – y? 65. x? 66. x2 67. x + 20xr + 100 68. x? + 16x + 64 – x4 69. 9x2 70. 25x? – 20x + 4 – 81y? 30x + 25 – 36y? 71. x* - x? – 2x – 1 72. x4 -х2 — бх — 9 x? + 4xy – 4y2 x²+ 10xy - 25y2 73. z? 74. z? - rarrow_forwardIn Problems 75–84, find the real solutions of each equation.arrow_forward
- In Problems 81–86, solve each equation by the Square Root Method.arrow_forwardIn Exercises 49–55, solve each rational equation. If an equation has no solution, so state. 3 1 + 3 49. 3 50. Зх + 4 2x - 8 1 3 6. 51. x + 5 x² 25 x + 5 52. x + 1 4x + 1 x + 2 x2 + 3x + 2 2 53. 3 - 3x .2 2 7 54. 4 x + 2 2x + 7 55. x + 5 8. x + 18 x - 4 x + x - 20arrow_forward2 (8a 3) 3 in simplest form.arrow_forward
- Section 2.2 2.1. Solve the following difference equations: (a) Yk+1+Yk = 2+ k, (b) Yk+1 – 2Yk k3, (c) Yk+1 – 3 (d) Yk+1 – Yk = 1/k(k+ 1), (e) Yk+1+ Yk = 1/k(k+ 1), (f) (k + 2)yk+1 – (k+1)yk = 5+ 2* – k2, (g) Yk+1+ Yk = k +2 · 3k, (h) Yk+1 Yk 0, Yk = ke*, (i) Yk+1 Bak? Yk (j) Yk+1 ayk = cos(bk), (k) Yk+1 + Yk = (-1)k, (1) - * = k. Yk+1 k+1arrow_forwardSolve the ytem 2x -44 =6 X +Z +y=' ダ+ダ= /o Solarrow_forwardSection 2.2 2.1. Solve the following difference equations: (a) Yk+1+ Yk = 2+ k, (b) Yk+1 – 2yk = k³, (с) ук+1 "Yk = 0, (d) Yk+1 – Yk = 1/k(k+1), (e) Yk+1+ Yk = 1/k(k+1), (f) (k+2)yk+1 – (k + 1)yk = 5 + 2k – k², (g) Yk+1+ Yk = k + 2 · 3k, (h) Yk+1 – Yk = ke“, Yk = Bak*, = cos (bk), (k) Yk+1 + Yk = (-1)*, Yk – k. ,2k (i) Ук+1 (j) Yk+1 – aYk (1) Yk+1 k+1arrow_forward
- Algebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:CengageAlgebra: Structure And Method, Book 1AlgebraISBN:9780395977224Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. ColePublisher:McDougal Littell
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