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(a)
Interpretation:
The retention time for both isomers and the average width of the peak has to be calculated.
(a)
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Answer to Problem 25.BE
The retention time of R-isomer (
The retention time of S-isomer (
The average width (
Explanation of Solution
To find the retention time of R-isomer,
Retention factor (
Substitution of the above values in the retention factor equation, the retention time (
The retention time of R-isomer is calculated as
To find the retention time of S-isomer,
The retention time can be found by using the equation for Relative retention.
Relative retention (
Retention time (
The retention time of S-isomer is
To calculate the average width,
The average width can be calculated form the resolution and the difference in retention time of the two isomers,
Difference in retention time is found as
Resolution is given as
The average width can be calculated as shown below,
The average width at the base is calculated as
(b)
Interpretation:
The half-width of each peak present in the chromatogram has to be calculated.
(b)
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Answer to Problem 25.BE
The half-width of peak 1 is
The half-width of peak 2 is
Explanation of Solution
The plate number can be calculated using the equation given below,
From this we infer that retention time is proportional to half-width, if the plate number is a constant. Hence,
The average width at the base was calculated as
We know that for each peak, the width (
From the above two equations,
The average base width is
We know that,
Substituting this in the average width at the base equation,
The half-width of peak 2 is
From this half-width of peak 1 can be calculated as shown below,
The half-width of both peaks present in the given chromatogram was calculated.
(c)
Interpretation:
The relative heights of the two peaks has to be calculated.
(c)
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Answer to Problem 25.BE
The relative heights of two peaks is
Explanation of Solution
The half-width of peak 1 is
The half-width of peak 2 is
In the problem statement it is given that the areas under both the peaks are equal.
The relative heights of the two peaks is calculated as
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Chapter 25 Solutions
Quantitative Chemical Analysis
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