(a) Interpretation: For the given reaction there are two possible radical addition steps. The curved arrow notation and product for both radical additions are to be drawn and more stable product is to be predicted. Concept introduction: One atom of a double or triple bond forms a bond to a free radical, and the other atom of the double or triple bond gains an unpaired electron to form a radical, in a radical addition step. A single-barbed arrow is used to show the movement of a single electron in an elementary step. The order for radical stability is 3 o > 2 o > 1 o .

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Answer 1

Question

Chapter 25, Problem 25.36P

Interpretation Introduction

(a)

Interpretation:

For the given reaction there are two possible radical addition steps. The curved arrow notation and product for both radical additions are to be drawn and more stable product is to be predicted.

Concept introduction:

One atom of a double or triple bond forms a bond to a free radical, and the other atom of the double or triple bond gains an unpaired electron to form a radical, in a radical addition step. A single-barbed arrow is used to show the movement of a single electron in an elementary step. The order for radical stability is 3o > 2o > 1o.

Interpretation Introduction

(b)

Interpretation:

For the given reaction there are two possible radical addition steps. The curved arrow notation and product for both radical additions are to be drawn and more stable product is to be predicted. A single-barbed arrow is used to show the movement of a single electron in an elementary step.

Concept introduction:

One atom of a double or triple bond forms a bond to a free radical, and the other atom of the double or triple bond gains an unpaired electron to form a radical, in a radical addition step. A single-barbed arrow is used to show the movement of a single electron in an elementary step. The order for radical stability is 3o > 2o > 1o. Radical adjacent to π bond is more stable.

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The emission data in cps displayed in Table 1 is reported to two decimal places by the chemist. However, the instrument output is shown in Table 2. Table 2. Iron emission from ICP-AES Sample Blank Standard Emission, cps 579.503252562 9308340.13122 Unknown Sample 343.232365741 Did the chemist make the correct choice in how they choose to display the data up in Table 1? Choose the best explanation from the choices below. No. Since the instrument calculates 12 digits for all values, they should all be kept and not truncated. Doing so would eliminate significant information. No. Since the instrument calculates 5 decimal places for the standard, all of the values should be limited to the same number. The other decimal places are not significant for the blank and unknown sample. Yes. The way Saman made the standards was limited by the 250-mL volumetric flask. This glassware can report values to 2 decimal places, and this establishes our number of significant figures. Yes. Instrumental data…

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Answer 2

Question

Chapter 25, Problem 25.36P

Interpretation Introduction

(a)

Interpretation:

For the given reaction there are two possible radical addition steps. The curved arrow notation and product for both radical additions are to be drawn and more stable product is to be predicted.

Concept introduction:

One atom of a double or triple bond forms a bond to a free radical, and the other atom of the double or triple bond gains an unpaired electron to form a radical, in a radical addition step. A single-barbed arrow is used to show the movement of a single electron in an elementary step. The order for radical stability is 3o > 2o > 1o.

Interpretation Introduction

(b)

Interpretation:

For the given reaction there are two possible radical addition steps. The curved arrow notation and product for both radical additions are to be drawn and more stable product is to be predicted. A single-barbed arrow is used to show the movement of a single electron in an elementary step.

Concept introduction:

One atom of a double or triple bond forms a bond to a free radical, and the other atom of the double or triple bond gains an unpaired electron to form a radical, in a radical addition step. A single-barbed arrow is used to show the movement of a single electron in an elementary step. The order for radical stability is 3o > 2o > 1o. Radical adjacent to π bond is more stable.

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Answer 3

Question

Chapter 25, Problem 25.36P

Interpretation Introduction

(a)

Interpretation:

For the given reaction there are two possible radical addition steps. The curved arrow notation and product for both radical additions are to be drawn and more stable product is to be predicted.

Concept introduction:

One atom of a double or triple bond forms a bond to a free radical, and the other atom of the double or triple bond gains an unpaired electron to form a radical, in a radical addition step. A single-barbed arrow is used to show the movement of a single electron in an elementary step. The order for radical stability is 3o > 2o > 1o.

Interpretation Introduction

(b)

Interpretation:

For the given reaction there are two possible radical addition steps. The curved arrow notation and product for both radical additions are to be drawn and more stable product is to be predicted. A single-barbed arrow is used to show the movement of a single electron in an elementary step.

Concept introduction:

One atom of a double or triple bond forms a bond to a free radical, and the other atom of the double or triple bond gains an unpaired electron to form a radical, in a radical addition step. A single-barbed arrow is used to show the movement of a single electron in an elementary step. The order for radical stability is 3o > 2o > 1o. Radical adjacent to π bond is more stable.

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Answer 4

Question

Chapter 25, Problem 25.36P

Interpretation Introduction

(a)

Interpretation:

For the given reaction there are two possible radical addition steps. The curved arrow notation and product for both radical additions are to be drawn and more stable product is to be predicted.

Concept introduction:

One atom of a double or triple bond forms a bond to a free radical, and the other atom of the double or triple bond gains an unpaired electron to form a radical, in a radical addition step. A single-barbed arrow is used to show the movement of a single electron in an elementary step. The order for radical stability is 3o > 2o > 1o.

Interpretation Introduction

(b)

Interpretation:

For the given reaction there are two possible radical addition steps. The curved arrow notation and product for both radical additions are to be drawn and more stable product is to be predicted. A single-barbed arrow is used to show the movement of a single electron in an elementary step.

Concept introduction:

One atom of a double or triple bond forms a bond to a free radical, and the other atom of the double or triple bond gains an unpaired electron to form a radical, in a radical addition step. A single-barbed arrow is used to show the movement of a single electron in an elementary step. The order for radical stability is 3o > 2o > 1o. Radical adjacent to π bond is more stable.

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Answer 5

Chapter 25, Problem 25.36P

Interpretation Introduction

(a)

Interpretation:

For the given reaction there are two possible radical addition steps. The curved arrow notation and product for both radical additions are to be drawn and more stable product is to be predicted.

Concept introduction:

One atom of a double or triple bond forms a bond to a free radical, and the other atom of the double or triple bond gains an unpaired electron to form a radical, in a radical addition step. A single-barbed arrow is used to show the movement of a single electron in an elementary step. The order for radical stability is 3o > 2o > 1o.

Interpretation Introduction

(b)

Interpretation:

For the given reaction there are two possible radical addition steps. The curved arrow notation and product for both radical additions are to be drawn and more stable product is to be predicted. A single-barbed arrow is used to show the movement of a single electron in an elementary step.

Concept introduction:

One atom of a double or triple bond forms a bond to a free radical, and the other atom of the double or triple bond gains an unpaired electron to form a radical, in a radical addition step. A single-barbed arrow is used to show the movement of a single electron in an elementary step. The order for radical stability is 3o > 2o > 1o. Radical adjacent to π bond is more stable.

Answer 6

Chapter 25, Problem 25.36P

Interpretation Introduction

(a)

Interpretation:

For the given reaction there are two possible radical addition steps. The curved arrow notation and product for both radical additions are to be drawn and more stable product is to be predicted.

Concept introduction:

One atom of a double or triple bond forms a bond to a free radical, and the other atom of the double or triple bond gains an unpaired electron to form a radical, in a radical addition step. A single-barbed arrow is used to show the movement of a single electron in an elementary step. The order for radical stability is 3o > 2o > 1o.

Answer 7

Chapter 25, Problem 25.36P

Interpretation Introduction

(a)

Interpretation:

For the given reaction there are two possible radical addition steps. The curved arrow notation and product for both radical additions are to be drawn and more stable product is to be predicted.

Concept introduction:

One atom of a double or triple bond forms a bond to a free radical, and the other atom of the double or triple bond gains an unpaired electron to form a radical, in a radical addition step. A single-barbed arrow is used to show the movement of a single electron in an elementary step. The order for radical stability is 3o > 2o > 1o.

Answer 8

Interpretation Introduction

(b)

Interpretation:

For the given reaction there are two possible radical addition steps. The curved arrow notation and product for both radical additions are to be drawn and more stable product is to be predicted. A single-barbed arrow is used to show the movement of a single electron in an elementary step.

Concept introduction:

One atom of a double or triple bond forms a bond to a free radical, and the other atom of the double or triple bond gains an unpaired electron to form a radical, in a radical addition step. A single-barbed arrow is used to show the movement of a single electron in an elementary step. The order for radical stability is 3o > 2o > 1o. Radical adjacent to π bond is more stable.

Answer 9

Interpretation Introduction

(b)

Interpretation:

For the given reaction there are two possible radical addition steps. The curved arrow notation and product for both radical additions are to be drawn and more stable product is to be predicted. A single-barbed arrow is used to show the movement of a single electron in an elementary step.

Concept introduction:

One atom of a double or triple bond forms a bond to a free radical, and the other atom of the double or triple bond gains an unpaired electron to form a radical, in a radical addition step. A single-barbed arrow is used to show the movement of a single electron in an elementary step. The order for radical stability is 3o > 2o > 1o. Radical adjacent to π bond is more stable.

Answer 10

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Answer 11

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Answer 12

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Answer 13

Ch. 25 - Prob. 25.1P Ch. 25 - Prob. 25.2P Ch. 25 - Prob. 25.3P Ch. 25 - Prob. 25.4P Ch. 25 - Prob. 25.5P Ch. 25 - Prob. 25.6P Ch. 25 - Prob. 25.7P Ch. 25 - Prob. 25.8P Ch. 25 - Prob. 25.9P Ch. 25 - Prob. 25.10P

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Chapter 25 Solutions