General Chemistry
General Chemistry
4th Edition
ISBN: 9781891389603
Author: Donald A. McQuarrie, Peter A. Rock, Ethan B. Gallogly
Publisher: University Science Books
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Chapter 25, Problem 25.36P

(a)

Interpretation Introduction

Interpretation:

The value of Ecello has to be calculated for the given reaction 2 Ag(s) + F2(aq) 2 Ag+(aq) + 2 F(aq).

Concept Introduction:

Standard potential (Ecello) can be calculated by the following formula,

  Ecello= Eredo+Eoxo

(a)

Expert Solution
Check Mark

Answer to Problem 25.36P

The value of Ecello is 1.88 V.

Explanation of Solution

The given reaction is shown below,

  2 Na(s) + 2H2O(l) 2 Na+(aq) + 2 OH(aq) + H2(g)

Reduction half-cell is given below,

  2H2O(l)+ 2e(aq)  2 OH(aq) + H2(g) Eredo=0.828 V

Oxidation half-cell is given below,

  Na(s) Na+(aq)+ 1e(aq)Eoxo[Na|Na+]=Eredo[Na+|Na]=(2.71 V) =2.71 V

Calculate Ecello for the following reaction as follows,

  Ecello= Eredo+Eoxo= (0.828 V)+(2.71 V)=1.88 V

(b)

Interpretation Introduction

Interpretation:

The value of Ecello has to be calculated for the given reaction 2 H+(aq) + Pd(s) Pd2+(aq) + H2(g).

Concept Introduction:

Refer to (a).

(b)

Expert Solution
Check Mark

Answer to Problem 25.36P

The value of Ecello is 0.951 V.

Explanation of Solution

The given reaction is shown below,

  2 H+(aq) + Pd(s) Pd2+(aq) + H2(g)

Reduction half-cell is given below,

  2 H+(aq)+ 2e(aq) H2(g) Eredo=0.00 V

Oxidation half-cell is given below,

  Pd(s) Pd2+(aq)+ 2e(aq)Eoxo[Pd|Pd2+]=Eredo[Pd2+|Pd]=0.951 V

Calculate Ecello for the following reaction as follows,

  Ecello= Eredo+Eoxo= (0.00 V)+(0.951 V)=0.951 V

(c)

Interpretation Introduction

Interpretation:

The value of Ecello has to be calculated for the given reaction 4 Fe(OH)2(s) + O2(g) + H2O(l) 4 Fe(OH)3(s).

Concept Introduction:

Refer to (a).

(c)

Expert Solution
Check Mark

Answer to Problem 25.36P

The value of Ecello is 0.962 V.

Explanation of Solution

The given reaction is shown below,

  4 Fe(OH)2(s) + O2(g) + H2O(l) 4 Fe(OH)3(s)

Reduction half-cell is given below,

  O2(g) + H2O(l)+ 4e(aq) 4 OH(aq) Eredo=0.401 V

Oxidation half-cell is given below,

  4 Fe(OH)2(s) + OH(aq)  4 Fe(OH)3(s)+ e(aq)Eoxo[Fe(OH)3|Fe(OH)2]=Eredo[Fe(OH)2|Fe(OH)3]       =(0.56 V) = 0.56 V

Calculate Ecello for the following reaction as follows,

  Ecello= Eredo+Eoxo= (0.401 V)+(0.56 V)=0.962 V

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