By comparing the bond energies of the given bonds to that of C-H bond, it is to be verified that halogens and peroxides have weak bonds. Concept introduction: The energy that would be required to increase the distance between two bonded atoms from the bond length to infinity, that is, breaking of one mole of molecules into their individual atoms, is termed as the bond energy. The larger value of bond energy represents strong bond. Table: Homolytic Bond Dissociation Energies Bond Homolytic Bond Dissociation Energy (kJ/mol) Cl - Cl 243 Br - Br 192 I - I 151 HO - OH 211 H 3 C - H 439

Question

Want to see the full answer?

Answer 1

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 25, Problem 25.2YT

Interpretation Introduction

Interpretation:

By comparing the bond energies of the given bonds to that of C-H bond, it is to be verified that halogens and peroxides have weak bonds.

Concept introduction:

The energy that would be required to increase the distance between two bonded atoms from the bond length to infinity, that is, breaking of one mole of molecules into their individual atoms, is termed as the bond energy. The larger value of bond energy represents strong bond.

Table: Homolytic Bond Dissociation Energies

Bond Homolytic Bond Dissociation Energy(kJ/mol)

Cl - Cl 243

Br - Br 192

I - I 151

HO - OH 211

H3C - H 439

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

In an experiment, 74.3 g of metallic copper was heated to 100.0°C and then quickly dropped into 200.0 mL of water in a calorimeter. The heat capacity of the calorimeter with the water was 875 J/°C. The initial temperature of the calorimeter was 27.5°C, and the final temperature after addition of the metal was 29.8°C. What is the value of the molar heat capacity of copper?

The Haber-Bosch process permits the direct conversion of molecular nitrogen to ammonia, which can be used in large-scale fertilizer production. Given the balanced Haber-Bosch reaction and using the bond energies in the table below, estimate the enthalpy change associated with the reaction. N2(g) + 3H2(g) → 2NH3(g) Bond N=N N = N Energy (kJ/mol) 941 418 N-N H-H N-H 163 435 388

Benzoic acid is used to determine the heat capacity of bomb calorimeters because it can be obtained in pure form and its energy of combustion is known very accurately (−26.43 kJ/g). Determine the heat capacity of a calorimeter that had a temperature increase of 9.199°C when 3.500 g of benzoic acid was used.

Answer 2

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 25, Problem 25.2YT

Interpretation Introduction

Interpretation:

By comparing the bond energies of the given bonds to that of C-H bond, it is to be verified that halogens and peroxides have weak bonds.

Concept introduction:

The energy that would be required to increase the distance between two bonded atoms from the bond length to infinity, that is, breaking of one mole of molecules into their individual atoms, is termed as the bond energy. The larger value of bond energy represents strong bond.

Table: Homolytic Bond Dissociation Energies

Bond Homolytic Bond Dissociation Energy(kJ/mol)

Cl - Cl 243

Br - Br 192

I - I 151

HO - OH 211

H3C - H 439

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 25, Problem 25.2YT

Interpretation Introduction

Interpretation:

By comparing the bond energies of the given bonds to that of C-H bond, it is to be verified that halogens and peroxides have weak bonds.

Concept introduction:

The energy that would be required to increase the distance between two bonded atoms from the bond length to infinity, that is, breaking of one mole of molecules into their individual atoms, is termed as the bond energy. The larger value of bond energy represents strong bond.

Table: Homolytic Bond Dissociation Energies

Bond Homolytic Bond Dissociation Energy(kJ/mol)

Cl - Cl 243

Br - Br 192

I - I 151

HO - OH 211

H3C - H 439

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 25, Problem 25.2YT

Interpretation Introduction