Explanation Given Info: Both Aluminum and Copper wires have same value of resistance and length and The diameter of the aluminum wire ( d al ) is 2.14 mm . The general formula to find area of circular cross sectional wire is, A = π d 2 4 d is the diameter of the wire. The formula to find the resistance of copper wire ( R cu ) . R cu = ρ cu L A cu ρ cu is the resistivity of the copper wire, L is the length of the copper wire, A cu is the area of cross section of the copper wire. Substitute π d cu 2 4 for A cu to get general expression for R cu . R cu = ρ cu L π d cu 2 / 4 (I) d cu is the diameter of the copper wire. The formula to find the resistance of Aluminum wire ( R al ) . R al = ρ al L A al ρ al is the resistivity of the aluminum wire, L is the length of the aluminum wire, A al is the area of cross section of the aluminum wire. Substitute π d al 2 4 for A al to get general expression for R al . R al = ρ al L π d al 2 / 4 (II) d al is the diameter of the aluminum wire. It is given that resistance of copper wire ( R cu ) is equal to resistance of aluminum wire ( R al )

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ISBN: 9781323575208

Author: YOUNG

Publisher: PEARSON C

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Resistivity

Resistivity is a characteristic property of the conductor’s material that measures the extent to which the material opposes the flow of current. It is denoted by the Greek letter “rho”. Electrical resistivity, also known as specific resistance, depends o…

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Chapter 25, Problem 25.18E

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The diameter of the copper wire (dcu).

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Chapter 25, Problem 25.17E

Chapter 25, Problem 25.19E

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Chapter 25 Solutions

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The diameter of the copper wire ( d cu ) .

Solution Summary: The author explains that both aluminum and copper wires have the same value of resistance and length. The general formula to find area of circular cross sectional wire is, A=pi d24

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The diameter of the copper wire (dcu).

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Chapter 25 Solutions