Chapter 2.5, Problem 22P

Solve each equation for the given variable.

$4k+mn=n-3;n$

To determine

To find : the solution of the equation for the variable n.

Answer to Problem 22P

  $n=\frac{4k+3}{1-m}$

Explanation of Solution

Given equation: $4k+mn=n-3$

Calculation:

Adding both sides of equation by 3, we get

  $\begin{array}{l}4k+mn+3=n-3+3\\ 4k+mn+3=n\end{array}$

By subtracting mn from both sides of the equation, we get

  $\begin{array}{l}4k+mn+3-mn=n-mn\\ 4k+3=n\left(1-m\right)\\ n\left(1-m\right)=4k+3\end{array}$

Dividing both sides of equation by 1 -m , we get

  $n=\frac{4k+3}{1-m}$