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Concept explainers
To determine: The presence of mutants even when no
Introduction:
Drug
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Explanation of Solution
Explanation:
Experiments were carried out in two strains of bacteria with wild type
These strains are then grown in culture media with observance of few colonies in mutant
Conclusion:
To explain: That treatment with drug
Introduction:
Genotoxic activity of drug is its chemical property that induces mutations in the genome.
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Explanation of Solution
Explanation:
Treatment with drug
Conclusion:
The addition of this drug alkylates nucleotides leading to the formation of mutations in the genome.
To determine: The differences in the mutagenesis curve and survival curves in the two bacterial strains
Introduction:
Mutagenesis curve growth rate analyzes the rate of growth of bacterial strain after increasing the concentration of mutation causing drug in bacteria. Survival curve analyzes the percent of bacteria which survive after adding the mutation causing drug.
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Explanation of Solution
Explanation:
The percent survival of
Conclusion:
There is more decrease in the survival rate of
To explain: The amount of drops in
Introduction:
Radioactive labeling with thymidine incorporates these labeled atoms inside the formation of adducts of drug-
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Explanation of Solution
Explanation:
Conclusion:
The counts of incorporation of radioactive drug decreases in wild type strain and increases in mutant strain of
To determine: The types of mutations which show significant increases due to treatment with
Introduction:
Mutations are changes in nucleotides present at specific positions in the genome. These mutations convert purines to pyrimidines and pyrimidines to purines in the genome.
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Explanation of Solution
Explanation:
The strains used in this experimental study include the following with the nomenclature provided as follows:
Conclusion:
There is occurrence of mutations in all strains of bacteria but the frequency is different depending upon the characteristics of strain and amount of drug added to the strain of bacteria.
To determine: The different mutations occurring due to the formation of
Introduction:
Mutations occur in the genome of bacteria due to conversion of nucleotides after the formation of adducts of
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Explanation of Solution
Explanation:
The adduct formation takes place at guanine with formation of derivates with drug. This causes the change in base pairing from
Conclusion:
The adducts are formed by the addition of drug which changes the base pairing from
To determine: The base pairs that form
Introduction:
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Explanation of Solution
Explanation:
Refer to Figure
Conclusion:
The base pairs that form
To determine: Whether all the mutation types are repaired with same fidelity.
Introduction:
Fidelity is the precision with which the nucleotides are repaired in the genome. It depends upon the enzyme complexes which take an active part in excising and replacing the error prone nucleotides in the genome.
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Explanation of Solution
Explanation:
The different mutation types are not repaired with the same fidelity as given in the table below:
|
Higher repair, less number of colonies. |
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Not much difference |
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Less repair. |
|
High repair in both strains. |
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High repair in both strains |
|
Low repair. |
Conclusion:
The formation of different base-pairs with transitions occurs in both the wild type and mutant strains with formation of
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Chapter 25 Solutions
Lehninger Principles of Biochemistry
- Problem 15 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:33 CO Problem 4 of 15 4G 54% Done On the following Lineweaver-Burk -1 plot, identify the by dragging the Km point to the appropriate value. 1/V 40 35- 30- 25 20 15 10- T Км -15 10 -5 0 5 ||| 10 15 №20 25 25 30 1/[S] Г powered by desmosarrow_forward1:30 5G 47% Problem 10 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without a competitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' s mM¹ with 10 mg pe 20 V' 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward
- Problem 14 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:36 CO Problem 9 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of the catalytic efficiency (specificity constant) given that the enzyme concentration in this experiment is 5.0 μ.Μ. 1 [S] ¨‚ μM-1 1 V sμM-1 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| O Гarrow_forwardProblem 11 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without a noncompetitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' 20 V' s mM¹ with 10 μg per 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward
- Problem 13 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:33 CO Problem 8 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of kcat given that the enzyme concentration in this experiment is 5.0 μM. 1 [S] , мм -1 1 V₁ s μM 1 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forward1:33 5G. 46% Problem 12 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without an uncompetitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' 20 V' s mM¹ with 10 μg per 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward
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