
Concept explainers
To determine: The presence of mutants even when no
Introduction:
Drug

Explanation of Solution
Explanation:
Experiments were carried out in two strains of bacteria with wild type
These strains are then grown in culture media with observance of few colonies in mutant
Conclusion:
To explain: That treatment with drug
Introduction:
Genotoxic activity of drug is its chemical property that induces mutations in the genome.

Explanation of Solution
Explanation:
Treatment with drug
Conclusion:
The addition of this drug alkylates nucleotides leading to the formation of mutations in the genome.
To determine: The differences in the mutagenesis curve and survival curves in the two bacterial strains
Introduction:
Mutagenesis curve growth rate analyzes the rate of growth of bacterial strain after increasing the concentration of mutation causing drug in bacteria. Survival curve analyzes the percent of bacteria which survive after adding the mutation causing drug.

Explanation of Solution
Explanation:
The percent survival of
Conclusion:
There is more decrease in the survival rate of
To explain: The amount of drops in
Introduction:
Radioactive labeling with thymidine incorporates these labeled atoms inside the formation of adducts of drug-

Explanation of Solution
Explanation:
Conclusion:
The counts of incorporation of radioactive drug decreases in wild type strain and increases in mutant strain of
To determine: The types of mutations which show significant increases due to treatment with
Introduction:
Mutations are changes in nucleotides present at specific positions in the genome. These mutations convert purines to pyrimidines and pyrimidines to purines in the genome.

Explanation of Solution
Explanation:
The strains used in this experimental study include the following with the nomenclature provided as follows:
Conclusion:
There is occurrence of mutations in all strains of bacteria but the frequency is different depending upon the characteristics of strain and amount of drug added to the strain of bacteria.
To determine: The different mutations occurring due to the formation of
Introduction:
Mutations occur in the genome of bacteria due to conversion of nucleotides after the formation of adducts of

Explanation of Solution
Explanation:
The adduct formation takes place at guanine with formation of derivates with drug. This causes the change in base pairing from
Conclusion:
The adducts are formed by the addition of drug which changes the base pairing from
To determine: The base pairs that form
Introduction:

Explanation of Solution
Explanation:
Refer to Figure
Conclusion:
The base pairs that form
To determine: Whether all the mutation types are repaired with same fidelity.
Introduction:
Fidelity is the precision with which the nucleotides are repaired in the genome. It depends upon the enzyme complexes which take an active part in excising and replacing the error prone nucleotides in the genome.

Explanation of Solution
Explanation:
The different mutation types are not repaired with the same fidelity as given in the table below:
|
Higher repair, less number of colonies. |
|
Not much difference |
|
Less repair. |
|
High repair in both strains. |
|
High repair in both strains |
|
Low repair. |
Conclusion:
The formation of different base-pairs with transitions occurs in both the wild type and mutant strains with formation of
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Chapter 25 Solutions
EBK LEHNINGER PRINCIPLES OF BIOCHEMISTR
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- Examine the metabolic pathway. The enzymes that catalyze each step are identified as "e" with a numeric subscript. e₁ e3 e4 A B с 1° B' 02 e5 e6 e7 E F Which enzymes catalyze irreversible reactions? ப e ez ☐ ez e4 ☐ ப es 26 5 e7 Which of the enzymes is likely to be the allosteric enzyme that controls the synthesis of G? €2 ез e4 es 26 5 e7arrow_forwardAn allosteric enzyme that follows the concerted model has an allosteric coefficient (T/R) of 300 in the absence of substrate. Suppose that a mutation reversed the ratio. Select the effects this mutation will have on the relationship between the rate of the reaction (V) and substrate concentration, [S]. ㅁㅁㅁ The enzyme would likely follow Michaelis-Menten kinetics. The plot of V versus [S] would be sigmoidal. The enzyme would mostly be in the T form. The plot of V versus [S] would be hyperbolic. The enzyme would be more active.arrow_forwardPenicillin is hydrolyzed and thereby rendered inactive by penicillinase (also known as ẞ-lactamase), an enzyme present in some penicillin-resistant bacteria. The mass of this enzyme in Staphylococcus aureus is 29.6 kDa. The amount of penicillin hydrolyzed in 1 minute in a 10.0 mL. solution containing 1.00 x 10 g of purified penicillinase was measured as a function of the concentration of penicillin. Assume that the concentration of penicillin does not change appreciably during the assay. Plots of V versus [S] and 1/V versus 1/[S] for these data are shown. Vo (* 10 M minute"¹) 7.0 6.0 5.0 4.0 3.0 20 1.0 0.0 о 10 20 30 1/Vo (* 10 M1 minute) 20 103 90 BO 70 50 [S] (* 100 M) 40 50 60 y=762x+1.46 × 10" [Penicillin] (M) Amount hydrolyzed (uM) 1 0.11 3 0.25 5 0.34 10 0.45 30 0.58 50 0.61arrow_forward
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- Consider the reaction. kp S P kg What effects are produced by an enzyme on the general reaction? AG for the reaction increases. The rate constant for the reverse reaction (kr) increases. The reaction equilibrium is shifted toward the products. The concentration of the reactants is increased. The activation energy for the reaction is lowered. The formation of the transition state is promoted.arrow_forwardThe graph displays the activities of wild-type and several mutated forms of subtilisin on a logarithmic scale. The mutations are identified as: • The first letter is the one-letter abbreviation for the amino acid being altered. • The number identifies the position of the residue in the primary structure. ⚫ The second letter is the one-letter abbreviation for the amino acid replacing the original one. • Uncat. refers to the estimated rate for the uncatalyzed reaction. Log₁(S-1) Wild type S221A H64A -5 D32A S221A H64A D32A -10 Uncat. How would the activity of a reaction catalyzed by a version of subtilisin with all three residues in the catalytic triad mutated compare to the activity of the uncatalyzed reaction? It would have more activity, because the reaction catalyzed by the triple mutant is approximately three-fold faster than the uncatalyzed reaction. It would have less activity, because the reaction catalyzed by the triple mutant is approximately 1000-fold slower than the…arrow_forwardB Substrate Product AL Product Substrate Reaction progress- Reaction progress- omplete the passage describing the two reactions. In reaction A, the stability of the substrate is (AG) of the reaction is positive, Incorrect Answer greater than the stability of the product. The free-energy change Incorrect Answer so the reaction is considered In reaction B, the stability of the substrate is (AG) of the reaction is less than Incorrect Answer endergonic and Incorrect Answer not spontaneous. Incorrect Answer the stability of the product. The free-energy change negative, so the reaction is considered Incorrect Answer exergonic and spontaneous. Incorrect Answer Incorrect Answerarrow_forward
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