EBK 3I-EBK: WELDING PRINCIPLES & APPLIC
8th Edition
ISBN: 9780176919764
Author: Jeffus
Publisher: VST
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 25, Problem 13R
How can a notch cause incomplete fusion?
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
For the walking-beam mechanism shown in Figure 3, find and plot the x and y coordinates of the
position of the coupler point P for one complete revolution of the crank O2A. Use the coordinate
system shown in Figure 3. Hint: Calculate them first with respect to the ground link 0204 and
then transform them into the global XY coordinate system.
y
-1.75
Ꮎ
Ꮎ
4
= 2.33
0242.22
L4
x
AP = 3.06
L2 = 1.0
W2
31°
B
03 L3 = 2.06
P
1
8
5
.06
6
7
P'
The link lengths, gear ratio (2), phase angle (Ø), and the value of 02 for some geared five bar
linkages are defined in Table 2. The linkage configuration and terminology are shown in Figure
2. For the rows assigned, find all possible solutions for angles 03 and 04 by the vector loop
method. Show your work in details: vector loop, vector equations, solution procedure.
Table 2
Row
Link 1 Link 2
Link 3
Link 4
Link 5
λ
Φ
Ө
a
6
1
7
9
4
2
30°
60°
P
y 4
YA
B
b
R4
R3
YA
A
Gear ratio:
a
02
d
05
r5
R5
R2
Phase angle: = 0₂-202
R1
05
02
r2
Figure 2.
04
X
Problem 4
A .025 lb bullet C is fired at end B of the 15-lb slender bar AB. The
bar is initially at rest, and the initial velocity of the bullet is 1500 ft/s
as shown. Assuming that the bullet becomes embedded in the bar,
find (a) the angular velocity @2 of the bar immediately after impact,
and (b) the percentage loss of kinetic energy as a result of the impact.
(c) After the impact, does the bar swing up 90° and reach the
horizontal? If it does, what is its angular velocity at this point?
Answers: (a). @2=1.6 rad/s; (b). 99.6% loss
=
(c). Ah2 0.212 ft. The bar does not reach horizontal.
y
X
4 ft
15 lb
V₁
1500 ft/s
0.025 lb
C
30°7
B
A
Chapter 25 Solutions
EBK 3I-EBK: WELDING PRINCIPLES & APPLIC
Ch. 25 - Why are all welds not inspected to the same level...Ch. 25 - Why is the strength of all production parts not...Ch. 25 - Why is it possible to do more than one...Ch. 25 - What is a discontinuity?Ch. 25 - What is a defect?Ch. 25 - What is tolerance?Ch. 25 - What are the 12 most common discontinuities?Ch. 25 - How can porosity form in a weld and not be seen by...Ch. 25 - What welding process can cause porosity to form?Ch. 25 - How is piping porosity formed?
Ch. 25 - What are inclusions, and how are they caused?Ch. 25 - When does inadequate joint penetration usually...Ch. 25 - How can a notch cause incomplete fusion?Ch. 25 - How can an arc strike appear on a guided-bend...Ch. 25 - What is overlap?Ch. 25 - What is undercut?Ch. 25 - What causes crater cracks?Ch. 25 - What is underfill?Ch. 25 - What is the difference between a lamination and a...Ch. 25 - How can stress be reduced through a plate's...Ch. 25 - What would be the tensile strength in pounds per...Ch. 25 - What would be the elongation for a specimen for...Ch. 25 - How are the results of a stress test reported?Ch. 25 - What would be the transverse shear strength per...Ch. 25 - What would be the longitudinal shearing strength...Ch. 25 - What are the three methods of destructive testing...Ch. 25 - How are the specimens bent for a guided-. root-,...Ch. 25 - How wide should a specimen be if the material...Ch. 25 - Why are guidelines drawn on the surface of a...Ch. 25 - What part of a fillet weld break test is examined?Ch. 25 - What can happen if acids are handled carelessly?Ch. 25 - What information about the weld does an impact...Ch. 25 - Which nondestructive test is most commonly used?Ch. 25 - List the five steps to be followed when using a...Ch. 25 - What properties must metal have before it can be...Ch. 25 - Why will some flaws appear larger on an X-ray than...Ch. 25 - How is the size of a flaw determined using...Ch. 25 - What is the major limitation of eddy current...Ch. 25 - What information does a hardness test reveal?Ch. 25 - Why is it important to select the correct welding...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- subject: combustion please include complete solution, no rounding off, with diagram/explanation etc. In a joule cycle, intake of the compressor is 40,000 cfm at 0.3 psig and 90 deg F. The compression ratio is 6.0 and the inlet temperature at the turbine portion is 1900R while at the exit, it is 15 psi. Calculate for the back work ratio in percent.arrow_forwardsubject: combustion please include complete solution, no rounding off, with diagram/explanation etc. A gasoline engine, utilizing cold air, recorded a work of 431 BTU/lb at a maximum temperature of 3,273 K and 1112 deg F temperature at the beginning of constant volume heat addition. What is the compression ratio?arrow_forwardsubject: combustion please do step by step solution and no rounding off, complete solution with diagram/explanation if needed etc. thank you! Air enters the compressor at 101,320 Pascals, 305.15K, and leaves at a pressure of 0.808MPa. The air is heated to 990.15K in the combustion chamber. For a net output of 2,125,000 Watts, find the rate of flow of air per second.arrow_forward
- The link lengths and the value of 2 and offset for some fourbar crank-slide linkages are defined in Table 1. The linkage configuration and terminology are shown in Figure 1. For the rows assigned, find (a) all possible solutions for angle & and slider position d by vector loop method. (b) the transmission angle corresponding to angle 03. (Hint: Treat the vector R4 as virtual rocker) Show your work in details: vector loop, vector equations, solution procedure. Table 1 Row Link 2 Link 3 Offset Ө a 1.4 4 1 45° b 3 8 2 -30° C 5 20 -5 225° 03 slider axis B X offset Link 2 A R3 Link 3 R4 04 R2 02 R1 d Figure 1. Xarrow_forward4. Two links made of heat treated 6061 aluminum (Sy = 276 MPa, Sys = 160 MPa) are pinned together using a steel dowel pin (Sy = 1398 MPa, Sys = 806 MPa) as shown below. The links are to support a load P with a factor of safety of at least 2.0. Determine if the link will fail first by tearout, direct shear of the pin, bearing stress on the link, or tensile stress at section AA. (Hint: find the load P for each case and choose the case that gives the smallest load.) P 8 mm P 8 mm ¡+A 3 mm →A 10 mm Parrow_forward1. For a feature other than a sphere, circularity is where: A. The axis is a straight line B. The modifier is specified with a size dimension C. All points of the surface intersected by any plane perpendicular to an axis or spine (curved line) are equidistant from that axis or spine D. All points of the surface intersected by any plane passing through a common center are equidistant from that center 2. What type of variation is limited by a circularity toler- ance zone? A. Ovality B. Tapering C. Bending D. Warping 3. How does the Rule #1 boundary affect the application of a circularity tolerance? A. The modifier must be used. B. The feature control frame must be placed next to the size dimension. C. The circularity tolerance value must be less than the limits of size tolerance. D. Circularity cannot be applied where a Rule #1 boundary exists. 4. A circularity tolerance may use a modifier. A. Ø B. F C. M D. ℗ 5. A real-world application for a circularity tolerance is: A. Assembly (i.e.,…arrow_forward
- 3. A steel bar is pinned to a vertical support column by a 10 mm diameter hardened dowel pin, Figure 1. For P = 7500 N, find: a. the shear stress in the pin, b. the direct bearing stress on the hole in the bar, c. the minimum value of d to prevent tearout failure if the steel bar has a shear strength of 175 MPa. support column pin bar thickness of bar = 8 mm h d 150 mmarrow_forwardA press that delivers 115 strokes per minute, each stroke providing a force of 7826 N throughout a distance of 18 mm. The press efficiency is 90% and is driven by a 1749-rpm motor. Determine average torque that must be provided by the motor in the units of N-m.arrow_forward·3) find the force (P) for the figures (1) and (2) 15cm 10cm 15 h=10mm h2=6mm // Call = 90 N/2 P Agate Fig (i) Ans: 1)P=112614N 2) P=1956.5 N 25cm 25 cm الفترة أو الحجم تمر بالتي عثر اكو تورشن (ک Fig (2) h₁ = 10mm 42=6mm Cmarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Welding: Principles and Applications (MindTap Cou...Mechanical EngineeringISBN:9781305494695Author:Larry JeffusPublisher:Cengage Learning
Precision Machining Technology (MindTap Course Li...Mechanical EngineeringISBN:9781285444543Author:Peter J. Hoffman, Eric S. Hopewell, Brian JanesPublisher:Cengage Learning
Welding: Principles and Applications (MindTap Cou...
Mechanical Engineering
ISBN:9781305494695
Author:Larry Jeffus
Publisher:Cengage Learning
Precision Machining Technology (MindTap Course Li...
Mechanical Engineering
ISBN:9781285444543
Author:Peter J. Hoffman, Eric S. Hopewell, Brian Janes
Publisher:Cengage Learning
Metal Joining Process-Welding, Brazing and Soldering; Author: Toc H Kochi;https://www.youtube.com/watch?v=PPT5_fDSzGY;License: Standard YouTube License, CC-BY