CHEMISTRY THE CENTRAL SCIENCE 14TH EDI
14th Edition
ISBN: 9780134863016
Author: Brown
Publisher: PEARSON
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Chapter 24.7, Problem 24.7.2PE
Practice Exercise 2
Name the dipeptide and give the two ways of writing its abbreviation.
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B 1 of 2
Additional problems in preparation to Midterm #1:
1.) How can the following compounds be prepared using Diels-Alder reaction:
CH3 O
CN
(a)
(b)
CN
CH3
2.) What is the missing reagent in the shown reaction?
H3C
+ ?
H3C
H3C
CN
H3C
''CN
(၁)
H
3.) Write the products 1,2-addition and 1,4-addition of DBr to 1,3-cyclohexadiene.
Remember, D is deuterium, a heavy isotope of hydrogen. It reacts exactly like hydrogen.
4.) In the shown reaction, which will be the kinetic product and which will be the
thermodynamic product?
H3C
CI
H3C
HCI
H3C
+
5.) Which of the following molecules is aromatic?
(a)
(b)
(c)
H
6.) Which of the following molecules is aromatic?
(a)
(b)
(c)
7.) Write the mechanism for the shown reaction.
+
Ха
AICI 3
CI
8.) Suggest reagents that would convert benzene into the shown compounds.
CI
NO2
-8-6-6-8-a
(a)
(b)
(c)
(d)
(e)
(a)
SO3H
Br
The number of 2sp^2 hybridized atoms in is: A. 8; B. 6; C.4; D.2; E.0;
Chapter 24 Solutions
CHEMISTRY THE CENTRAL SCIENCE 14TH EDI
Ch. 24.2 - Prob. 24.1.1PECh. 24.2 - Prob. 24.1.2PECh. 24.2 - How many hydrogen atoms are in 2, 2-...Ch. 24.2 - Prob. 24.2.2PECh. 24.3 - Prob. 24.3.1PECh. 24.3 - Prob. 24.3.2PECh. 24.3 - Prob. 24.4.1PECh. 24.3 - Prob. 24.4.2PECh. 24.3 - Prob. 24.5.1PECh. 24.3 - Prob. 24.5.2PE
Ch. 24.4 - Prob. 24.6.1PECh. 24.4 - Prob. 24.6.2PECh. 24.7 - Prob. 24.7.1PECh. 24.7 - Practice Exercise 2 Name the dipeptide and give...Ch. 24.7 - How many chiral carbon atoms are there in the...Ch. 24.7 - Prob. 24.8.2PECh. 24 - Prob. 1DECh. 24 - Prob. 1ECh. 24 - Prob. 2ECh. 24 - Prob. 3ECh. 24 - Prob. 4ECh. 24 - Prob. 5ECh. 24 - Prob. 6ECh. 24 - Prob. 7ECh. 24 - Prob. 8ECh. 24 - Prob. 9ECh. 24 - Prob. 10ECh. 24 - Prob. 11ECh. 24 - Prob. 12ECh. 24 - Prob. 13ECh. 24 - Prob. 14ECh. 24 - Prob. 15ECh. 24 - Prob. 16ECh. 24 - Prob. 17ECh. 24 - Prob. 18ECh. 24 - Prob. 19ECh. 24 - Prob. 20ECh. 24 - Prob. 21ECh. 24 - Prob. 22ECh. 24 - Prob. 23ECh. 24 - Prob. 24ECh. 24 - Prob. 25ECh. 24 - Prob. 26ECh. 24 - Prob. 27ECh. 24 - Prob. 28ECh. 24 - Prob. 29ECh. 24 - Prob. 30ECh. 24 - Prob. 31ECh. 24 - Prob. 32ECh. 24 - Prob. 33ECh. 24 - Prob. 34ECh. 24 - Prob. 35ECh. 24 - Prob. 36ECh. 24 - Prob. 37ECh. 24 - Prob. 38ECh. 24 - Prob. 39ECh. 24 - Describe the intermediate that is thought to form...Ch. 24 - Prob. 41ECh. 24 - Prob. 42ECh. 24 - Prob. 43ECh. 24 - Prob. 44ECh. 24 - Prob. 45ECh. 24 - Prob. 46ECh. 24 - Prob. 47ECh. 24 - Prob. 48ECh. 24 - Prob. 49ECh. 24 - Prob. 50ECh. 24 - Prob. 51ECh. 24 - Prob. 52ECh. 24 - Prob. 53ECh. 24 - Prob. 54ECh. 24 - Prob. 55ECh. 24 - Prob. 56ECh. 24 - Prob. 57ECh. 24 - Prob. 58ECh. 24 - Prob. 59ECh. 24 - Prob. 60ECh. 24 - Prob. 61ECh. 24 - Prob. 62ECh. 24 - Prob. 63ECh. 24 - Prob. 64ECh. 24 - Prob. 65ECh. 24 - Prob. 66ECh. 24 - Prob. 67ECh. 24 - Prob. 68ECh. 24 - Prob. 69ECh. 24 - Prob. 70ECh. 24 - Prob. 71ECh. 24 - Prob. 72ECh. 24 - Prob. 73ECh. 24 - Prob. 74ECh. 24 - Prob. 75ECh. 24 - Prob. 76ECh. 24 - Prob. 77ECh. 24 - Prob. 78ECh. 24 - Prob. 79ECh. 24 - Prob. 80ECh. 24 - Prob. 81AECh. 24 - Prob. 82AECh. 24 - Prob. 83AECh. 24 - Prob. 84AECh. 24 - Prob. 85AECh. 24 - Prob. 86AECh. 24 - Prob. 87AECh. 24 - Prob. 88AECh. 24 - Prob. 89AECh. 24 - Prob. 90AECh. 24 - Prob. 91AECh. 24 - Prob. 92AECh. 24 - Prob. 93AECh. 24 - Prob. 94AECh. 24 - Prob. 95IECh. 24 - Prob. 96IECh. 24 - Prob. 97IECh. 24 - Prob. 98IECh. 24 - Prob. 99IECh. 24 - A typical amino acid with one amino group and one...Ch. 24 - Prob. 101IECh. 24 - Prob. 102IE
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