EBK ORGANIC CHEMISTRY-STUD.SOLNS.MAN+SG
4th Edition
ISBN: 9781119659525
Author: Klein
Publisher: WILEY CONS
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Question
Chapter 24.5, Problem 12PTS
(a)
Interpretation Introduction
Interpretation:
The Haworth projection for each of the given compounds are needed to be drawn.
Concept introduction:
- Haworth projection is used to represent sugars in their cyclic forms.
- In Haworth projection,
- α-indicates the –OH group of anomeric carbon C1 and
- D indicates the
- The right side and left side –OH groups of chiral carbons in fisher projection are drawn as down side and upward side respectively.
- α-indicates the –OH group of anomeric carbon C1 and
To draw: the Haworth projection for the given compound (a).
(b)
Interpretation Introduction
Interpretation:
The Haworth projection for each of the given compounds are needed to be drawn.
Concept introduction:
- Haworth projection is used to represent sugars in their cyclic forms.
- In Haworth projection,
- α-indicates the –OH group of anomeric carbon C1 and
- D indicates the
- The right side and left side –OH groups of chiral carbons in fisher projection are drawn as down side and upward side respectively.
- α-indicates the –OH group of anomeric carbon C1 and
To draw: the Haworth projection for the given compound (b).
(c)
Interpretation Introduction
Interpretation:
The Haworth projection for each of the given compounds are needed to be drawn.
Concept introduction:
- Haworth projection is used to represent sugars in their cyclic forms.
- In Haworth projection,
- α-indicates the –OH group of anomeric carbon C1 and
- D indicates the
- The right side and left side –OH groups of chiral carbons in fisher projection are drawn as down side and upward side respectively.
- α-indicates the –OH group of anomeric carbon C1 and
To draw: the Haworth projection for the given compound (c).
(d)
Interpretation Introduction
Interpretation:
The Haworth projection for each of the given compounds are needed to be drawn.
Concept introduction:
- Haworth projection is used to represent sugars in their cyclic forms.
- In Haworth projection,
- α-indicates the –OH group of anomeric carbon C1 and
- D indicates the
- The right side and left side –OH groups of chiral carbons in fisher projection are drawn as down side and upward side respectively.
- α-indicates the –OH group of anomeric carbon C1 and
To draw: the Haworth projection for the given compound (d).
(e)
Interpretation Introduction
Interpretation:
The Haworth projection for each of the given compounds are needed to be drawn.
Concept introduction:
- Haworth projection is used to represent sugars in their cyclic forms.
- In Haworth projection,
- α-indicates the –OH group of anomeric carbon C1 and
- D indicates the
- The right side and left side –OH groups of chiral carbons in fisher projection are drawn as down side and upward side respectively.
- α-indicates the –OH group of anomeric carbon C1 and
To draw: the Haworth projection for the given compound (e).
(f)
Interpretation Introduction
Interpretation:
The Haworth projection for each of the given compounds are needed to be drawn.
Concept introduction:
- Haworth projection is used to represent sugars in their cyclic forms.
- In Haworth projection,
- α-indicates the –OH group of anomeric carbon C1 and
- D indicates the
- The right side and left side –OH groups of chiral carbons in fisher projection are drawn as down side and upward side respectively.
- α-indicates the –OH group of anomeric carbon C1 and
To draw: the Haworth projection for the given compound (f).
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Using the general properties of equilibrium constants
At a certain temperature, the equilibrium constant K for the following reaction is 1.3 × 10 4:
Cl2(g) + CHCl3(g) HCl(g) + CC₁(g)
Use this information to complete the following table.
Suppose a 16. L reaction vessel is filled with 1.6 mol of HCI and
1.6 mol of CCl4. What can you say about the composition of the
mixture in the vessel at equilibrium?
There will be very little Cl2 and CHCl3.
☐ x10
There will be very little HCI and CCl4.
Neither of the above is true.
What is the equilibrium constant for the following reaction? Be
sure your answer has the correct number of significant digits.
HCl(g)+CC14(g)
12
Cl2(9)+CHCl3(9)
K = 0 ☐
What is the equilibrium constant for the following reaction? Be
sure your answer has the correct number of significant digits.
2 Cl₂(9)+2CHCl3(9)
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Chapter 24 Solutions
EBK ORGANIC CHEMISTRY-STUD.SOLNS.MAN+SG
Ch. 24.2 - Prob. 1CCCh. 24.2 - Prob. 2CCCh. 24.2 - Prob. 3CCCh. 24.2 - Prob. 4CCCh. 24.2 - Prob. 5CCCh. 24.2 - Prob. 6CCCh. 24.4 - Prob. 7CCCh. 24.4 - Prob. 8CCCh. 24.5 - Prob. 1LTSCh. 24.5 - Prob. 9PTS
Ch. 24.5 - Prob. 2LTSCh. 24.5 - Prob. 12PTSCh. 24.5 - Prob. 13PTSCh. 24.5 - Prob. 3LTSCh. 24.5 - Prob. 16PTSCh. 24.5 - Prob. 19CCCh. 24.5 - Prob. 20CCCh. 24.5 - Prob. 21CCCh. 24.5 - Prob. 22CCCh. 24.6 - Prob. 23CCCh. 24.6 - Prob. 24CCCh. 24.6 - Prob. 25CCCh. 24.6 - Prob. 26CCCh. 24.6 - Prob. 27CCCh. 24.6 - Prob. 28CCCh. 24.6 - Prob. 29CCCh. 24.6 - Prob. 30CCCh. 24.6 - Prob. 4LTSCh. 24.6 - Prob. 31PTSCh. 24.6 - Prob. 34CCCh. 24.6 - Prob. 35CCCh. 24.6 - Prob. 36CCCh. 24.6 - Prob. 37CCCh. 24.6 - Prob. 38CCCh. 24.7 - Prob. 5LTSCh. 24.7 - Prob. 39PTSCh. 24.7 - Prob. 41CCCh. 24 - Prob. 42PPCh. 24 - Prob. 43PPCh. 24 - Prob. 44PPCh. 24 - Prob. 45PPCh. 24 - Prob. 46PPCh. 24 - Prob. 47PPCh. 24 - Prob. 48PPCh. 24 - Prob. 49PPCh. 24 - Prob. 50PPCh. 24 - Prob. 51PPCh. 24 - Prob. 52PPCh. 24 - Prob. 53PPCh. 24 - Prob. 54PPCh. 24 - Prob. 55PPCh. 24 - Prob. 56PPCh. 24 - Prob. 57PPCh. 24 - Prob. 58PPCh. 24 - Prob. 59PPCh. 24 - Prob. 60PPCh. 24 - Prob. 61PPCh. 24 - Prob. 62PPCh. 24 - Prob. 63PPCh. 24 - Prob. 64PPCh. 24 - Prob. 65PPCh. 24 - Prob. 66PPCh. 24 - Prob. 67PPCh. 24 - Prob. 68PPCh. 24 - Prob. 69PPCh. 24 - Prob. 70PPCh. 24 - Prob. 71PPCh. 24 - Prob. 72PPCh. 24 - Prob. 73PPCh. 24 - Prob. 74PPCh. 24 - Prob. 75PPCh. 24 - Prob. 76PPCh. 24 - Prob. 77PPCh. 24 - Prob. 78PPCh. 24 - Prob. 79PPCh. 24 - Prob. 80PPCh. 24 - Prob. 86IPCh. 24 - Prob. 87IPCh. 24 - Prob. 88IPCh. 24 - Prob. 89IP
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