Chemistry: The Central Science, Books a la Carte Edition & Modified Mastering Chemistry with Pearson eText -- ValuePack Access Card Package

1st Edition

ISBN: 9780133910919

Author: Theodore E. Brown, H. Eugene LeMay, Bruce E. Bursten, Catherine Murphy, Patrick Woodward, Matthew E. Stoltzfus

Publisher: PEARSON

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Textbook Question

Chapter 24.3, Problem 24.4.2PE

Consider the hypothetical reaction A(g) + 2B(g) ⇌ 2 C(g), for which K_c = 0.25 at a centain temperature. A 1.00-L reaction vessel is loaded with 1.00 mol of compound C, which is allowed to reach equilibrium. Let the variable x represent the number of mol/L of compound A present at equilibrium.
a. In terms of x, what are the equilibrium concentrations of compounds B and C?
b. What limits must be placed on the value of x so that all concentrations are positive?
c. By putting the equilibrium concentrations (in terms of x ) into the equilibrium- constant expression, derive an equation that can be solved for x.
d. The equation from part(c ) is a cubic equation (one that has the form ax³ + bx² + cx + d =0). In general, cubic equations cannot be solved in closed form. However, you can estimate the solution by plotting the cubic equation in the allowed range of x that you specified in part (b). The point at which the cubic equation crosses the x-axis is the solution.
e. From the plot in part (d), estimate the equilibrium concentrations of A, B, and C. (Hint : You can check the accuracy of your answer by substituting these concentrations into the equilibrium expression.)

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Chapter 24.3, Problem 24.4.1PE

Chapter 24.3, Problem 24.5.1PE

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need help please and thanks dont understand only need help with C-F Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal…

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need help please and thanks dont understand a-b Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal energy Divide the…

Chapter 24 Solutions

Chemistry: The Central Science, Books a la Carte Edition & Modified Mastering Chemistry with Pearson eText -- ValuePack Access Card Package

Ch. 24.2 - Prob. 24.1.1PE Ch. 24.2 - The equilibrium constant Kc for C(s) +CO2 2CO(g)...Ch. 24.2 - Prob. 24.2.1PE Ch. 24.2 - Le Chatelier noted that many industrial processes...Ch. 24.3 - Prob. 24.3.1PE Ch. 24.3 - Prob. 24.3.2PE Ch. 24.3 - [15.91] An equilibrium mixture of H2, I2, and HI...Ch. 24.3 - Consider the hypothetical reaction A(g) + 2B(g) 2...Ch. 24.3 - Prob. 24.5.1PE Ch. 24.3 - Prob. 24.5.2PE

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