(a)
Interpretation:
For each of the given compounds, whether it is D or L sugar should be determined, the configuration of each chiral center should be assigned and the trend on the configuration of each chiral center should be explained.
Concept introduction:
- The stereo-descriptor used for carbohydrates is D or L. it is based on the dextrorotatory or levorotatory of smallest carbohydrate glyceraldehyde (1 chiral center).
The stereo-descriptor for other carbohydrates of having more than one chiral center will be evaluated by the location of –OH group (right or left) of farthest chiral carbon from the carbonyl group. Such as,
If the –OH group is located in right side then, the carbohydrate is a D-sugar.
If the –OH group is located in left side then, the carbohydrate is a L-sugar.
- Chiral carbon: Chiral carbon is the one which is bonded to four different molecules or groups.
- Configuration of a molecule: The configurations of a molecule arise due to the spatial arrangement of atoms. The configuration can be assigned by following CIP rules as follows.
- Assign numbering to the groups which are bonded to the chiral carbon based on the molecular weight and electronegativity.
- If the sequence of the numbering follows clockwise direction the chiral atom is assigned as R configuration.
- If the sequence of the numbering follows anticlockwise direction the chiral atom is assigned as S configuration.
- If the least priority group is on horizontal line in the fisher projection, then configuration is inverted to the obtained configuration from the above CIP rule which means R configuration becomes S and vice versa.
- The D-configuration is needed not to be dextrorotatory; rather it means the chirality center of farthest from aldo-group is having R-configuration or the –OH group is on right side.
To identify: the given carbohydrate (a) is D or L sugar and the configuration of each chiral center.
(b)
Interpretation:
For each of the given compounds, whether it is D or L sugar should be determined, the configuration of each chiral center should be assigned and the trend on the configuration of each chiral center should be explained.
Concept introduction:
- The stereo-descriptor used for carbohydrates is D or L. it is based on the dextrorotatory or levorotatory of smallest carbohydrate glyceraldehyde (1 chiral center).
The stereo-descriptor for other carbohydrates of having more than one chiral center will be evaluated by the location of –OH group (right or left) of farthest chiral carbon from the carbonyl group. Such as,
If the –OH group is located in right side then, the carbohydrate is a D-sugar.
If the –OH group is located in left side then, the carbohydrate is a L-sugar.
- Chiral carbon: Chiral carbon is the one which is bonded to four different molecules or groups.
- Configuration of a molecule: The configurations of a molecule arise due to the spatial arrangement of atoms. The configuration can be assigned by following CIP rules as follows.
- Assign numbering to the groups which are bonded to the chiral carbon based on the molecular weight and electronegativity.
- If the sequence of the numbering follows clockwise direction the chiral atom is assigned as R configuration.
- If the sequence of the numbering follows anticlockwise direction the chiral atom is assigned as S configuration.
- If the least priority group is on horizontal line in the fisher projection, then configuration is inverted to the obtained configuration from the above CIP rule which means R configuration becomes S and vice versa.
- The D-configuration is needed not to be dextrorotatory; rather it means the chirality center of farthest from aldo-group is having R-configuration or the –OH group is on right side.
To identify: the given carbohydrate (b) is D or L sugar and the configuration of each chiral center.
(c)
Interpretation:
For each of the given compounds, whether it is D or L sugar should be determined, the configuration of each chiral center should be assigned and the trend on the configuration of each chiral center should be explained.
Concept introduction:
- The stereo-descriptor used for carbohydrates is D or L. it is based on the dextrorotatory or levorotatory of smallest carbohydrate glyceraldehyde (1 chiral center).
The stereo-descriptor for other carbohydrates of having more than one chiral center will be evaluated by the location of –OH group (right or left) of farthest chiral carbon from the carbonyl group. Such as,
If the –OH group is located in right side then, the carbohydrate is a D-sugar.
If the –OH group is located in left side then, the carbohydrate is a L-sugar.
- Chiral carbon: Chiral carbon is the one which is bonded to four different molecules or groups.
- Configuration of a molecule: The configurations of a molecule arise due to the spatial arrangement of atoms. The configuration can be assigned by following CIP rules as follows.
- Assign numbering to the groups which are bonded to the chiral carbon based on the molecular weight and electronegativity.
- If the sequence of the numbering follows clockwise direction the chiral atom is assigned as R configuration.
- If the sequence of the numbering follows anticlockwise direction the chiral atom is assigned as S configuration.
- If the least priority group is on horizontal line in the fisher projection, then configuration is inverted to the obtained configuration from the above CIP rule which means R configuration becomes S and vice versa.
- The D-configuration is needed not to be dextrorotatory; rather it means the chirality center of farthest from aldo-group is having R-configuration or the –OH group is on right side.
To identify: the given carbohydrate (c) is D or L sugar and the configuration of each chiral center.
(d)
Interpretation:
For each of the given compounds, whether it is D or L sugar should be determined, the configuration of each chiral center should be assigned and the trend on the configuration of each chiral center should be explained.
Concept introduction:
- The stereo-descriptor used for carbohydrates is D or L. it is based on the dextrorotatory or levorotatory of smallest carbohydrate glyceraldehyde (1 chiral center).
The stereo-descriptor for other carbohydrates of having more than one chiral center will be evaluated by the location of –OH group (right or left) of farthest chiral carbon from the carbonyl group. Such as,
If the –OH group is located in right side then, the carbohydrate is a D-sugar.
If the –OH group is located in left side then, the carbohydrate is a L-sugar.
- Chiral carbon: Chiral carbon is the one which is bonded to four different molecules or groups.
- Configuration of a molecule: The configurations of a molecule arise due to the spatial arrangement of atoms. The configuration can be assigned by following CIP rules as follows.
- Assign numbering to the groups which are bonded to the chiral carbon based on the molecular weight and electronegativity.
- If the sequence of the numbering follows clockwise direction the chiral atom is assigned as R configuration.
- If the sequence of the numbering follows anticlockwise direction the chiral atom is assigned as S configuration.
- If the least priority group is on horizontal line in the fisher projection, then configuration is inverted to the obtained configuration from the above CIP rule which means R configuration becomes S and vice versa.
- The D-configuration is needed not to be dextrorotatory; rather it means the chirality center of farthest from aldo-group is having R-configuration or the –OH group is on right side.
To identify: the given carbohydrate (d) is D or L sugar and the configuration of each chiral center.
(e)
Interpretation:
For each of the given compounds, whether it is D or L sugar should be determined, the configuration of each chiral center should be assigned and the trend on the configuration of each chiral center should be explained.
Concept introduction:
- The stereo-descriptor used for carbohydrates is D or L. it is based on the dextrorotatory or levorotatory of smallest carbohydrate glyceraldehyde (1 chiral center).
The stereo-descriptor for other carbohydrates of having more than one chiral center will be evaluated by the location of –OH group (right or left) of farthest chiral carbon from the carbonyl group. Such as,
If the –OH group is located in right side then, the carbohydrate is a D-sugar.
If the –OH group is located in left side then, the carbohydrate is a L-sugar.
- Chiral carbon: Chiral carbon is the one which is bonded to four different molecules or groups.
- Configuration of a molecule: The configurations of a molecule arise due to the spatial arrangement of atoms. The configuration can be assigned by following CIP rules as follows.
- Assign numbering to the groups which are bonded to the chiral carbon based on the molecular weight and electronegativity.
- If the sequence of the numbering follows clockwise direction the chiral atom is assigned as R configuration.
- If the sequence of the numbering follows anticlockwise direction the chiral atom is assigned as S configuration.
- If the least priority group is on horizontal line in the fisher projection, then configuration is inverted to the obtained configuration from the above CIP rule which means R configuration becomes S and vice versa.
- The D-configuration is needed not to be dextrorotatory; rather it means the chirality center of farthest from aldo-group is having R-configuration or the –OH group is on right side.
To identify: the given carbohydrate (e) is D or L sugar and the configuration of each chiral center.
(f)
Interpretation:
For each of the given compounds, whether it is D or L sugar should be determined, the configuration of each chiral center should be assigned and the trend on the configuration of each chiral center should be explained.
Concept introduction:
- The stereo-descriptor used for carbohydrates is D or L. it is based on the dextrorotatory or levorotatory of smallest carbohydrate glyceraldehyde (1 chiral center).
The stereo-descriptor for other carbohydrates of having more than one chiral center will be evaluated by the location of –OH group (right or left) of farthest chiral carbon from the carbonyl group. Such as,
If the –OH group is located in right side then, the carbohydrate is a D-sugar.
If the –OH group is located in left side then, the carbohydrate is a L-sugar.
- Chiral carbon: Chiral carbon is the one which is bonded to four different molecules or groups.
- Configuration of a molecule: The configurations of a molecule arise due to the spatial arrangement of atoms. The configuration can be assigned by following CIP rules as follows.
- Assign numbering to the groups which are bonded to the chiral carbon based on the molecular weight and electronegativity.
- If the sequence of the numbering follows clockwise direction the chiral atom is assigned as R configuration.
- If the sequence of the numbering follows anticlockwise direction the chiral atom is assigned as S configuration.
- If the least priority group is on horizontal line in the fisher projection, then configuration is inverted to the obtained configuration from the above CIP rule which means R configuration becomes S and vice versa.
- The D-configuration is needed not to be dextrorotatory; rather it means the chirality center of farthest from aldo-group is having R-configuration or the –OH group is on right side.
To explain: the trend on the configuration of each chiral center in each given carbohydrates.
![Check Mark](/static/check-mark.png)
Want to see the full answer?
Check out a sample textbook solution![Blurred answer](/static/blurred-answer.jpg)
Chapter 24 Solutions
ORGANIC CHEM PRINT STUDY GDE & SSM
- I need help working this problem out step by step, I was trying to use my example from the txt book but all I know how to do is set it up. I need to be shown step by step as I am a visual learner. Please help me.arrow_forwardDon't used hand raitingarrow_forwardDon't used Ai solution and don't used hand raitingarrow_forward
- & Calculate the molar enthalpy of combustion (A combH) of 1.80 g of pyruvic acid (CH3COCOOH; 88.1 g mol-1) at 37 °C when they are combusted in a calorimeter at constant volume with a calorimeter constant = 1.62 kJ °C-1 and the temperature rose by 1.55 °C. Given: R = 8.314 J mol −1 °C-1 and the combustion reaction: AN C3H4O3 + 2.502(g) → 3CO2(g) + 2H2O(l)arrow_forwardAn unknown salt, AB, has the following precipitation reaction:A+(aq) + B-(aq) ⇌ AB(s) the K value for this reaction is 4.50 x10-6. Draw a model that represents what will happen when 1.00 L each of 1.00 M solution of A+(aq) and 1.00M solution of B-(aq) are combined.arrow_forward5. a) Use the rules in Example 4.4 (p. 99) and calculate sizes of octahedral and tetrahedral cavities in titanium and in zirconium. Use values for atomic radii given in Fig. 9.1 (p.291). (3 points) b) Consider the formation of carbides (MC) of these metals. Which metal is able to accommodate carbon atoms better, and which cavities (octahedral or tetrahedral) would be better suited to accommodate C atoms into metal's lattice? (4 points)arrow_forward
- 2. Read paragraph 3.4 in your textbook ("Chiral Molecules"), and explain if Cobalt(ethylenediamine) 33+ shown in previous problem is a chiral species. If yes, draw projections of both enantiomers as mirror images, analogous to mirror projections of hands (below). Mirror (4 points)arrow_forward3. Borane (BH3) belongs to D3h point group. Consider the vibrational (stretching) modes possible for B-H bonds under D3h symmetry. Using the methods we used in class, construct the reducible representation I, and break it down into irreducible representations using the character table provided. Sketch those modes, indicate whether they are IR-active. (6 points) D3h E 2C3 3C2 σh 283 30% A₁' 1 1 1 1 1 1 x² + y², z² 1 -1 1 1 -1 R₂ E' 2 0 2 0 (x, y) (x² - y², xy) " A₁" 1 1 -1 A2" 1 -1 -1 1 Z E" 2 -1 0 -2 1 0 (Ry, Ry) (xz, yz)arrow_forward1. List all the symmetry elements, and assign the compounds to proper point groups: a) HCIBrC-BrCIH Cl Br H (2 points) H Br b) Pentacarbonylmanganese(I)bromide Br OEC-Mn-CEO 00- c) Phenazine (aromatic molecule, with delocalized bonding) 1 d) Cobalt(ethylenediamine)33+ (just the cation) 3+ H₂N H₂ .NH2 (CI)3 NH2 H2 H₂N. (2 points) (2 points) (2 points)arrow_forward
- Hello, I desperately need help figuring out 8-14; I also wanted to see if you would mind letting me know if I picked the right degree as my melting points on the two graphs. Please and thank you in advance! All the information is provided.arrow_forwardThe reaction: A + B ⇌ 2 C, can be represented by the equilibrium expression, KC =[C]2[A][B]=258 at 520K.When 1.00 M of C was allowed to reach equilibrium and 0.055 M of A was formed. If this reaction wasperformed at the same temperature using 0.500 M C, what would the equilibrium concentration of Abe?arrow_forward1. What is the functional group of an alcohol and a phenol? 2. Why are some alcohols soluble in water? 3. Classify each of the following alcohols as primary, secondary or tertiary. a. 3-pentanol b. 2-methyl-2-butanol c. 1-propanolarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305957404/9781305957404_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781259911156/9781259911156_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305577213/9781305577213_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780078021558/9780078021558_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305079373/9781305079373_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781118431221/9781118431221_smallCoverImage.gif)