Explanation Given info: The frequency of the clavus sample is 80 Hz , the capacitance of the clavus sample is 1.2 nF , the resistance of the clavus sample is 1100 kΩ , the capacitance of the verruca sample is 5.25 nF , and the resistance of the verruca sample is 1020 kΩ . Explanation: Formula to calculate the impedance of the circuit when clavus is connected, Z = R clavus 2 + X clavus 2 (1) Here, X clavus is the reactance of clavus. R clavus is the resistance of the circuit. Formula to calculate the reactance of clavus, X clavus = 1 ω C Here, ω is the angular frequency of the clavus. C is the capacitance of the clavus. Formula to calculate the angular frequency, ω = 2 π f Here, f is the natural frequency of the circuit Substitute 2 π f in above equation. X clavus = 1 2 π f C Substitute 1 2 π f C for X C in equation (1). Z = R clavus 2 + ( 1 2 π f C ) 2 Formula to calculate the power factor cos ϕ = R Z Substitute R clavus 2 + ( 1 2 π f C ) 2 for Z in above equation and solve for ϕ , cos ϕ = R R clavus 2 + ( 1 2 π f C ) 2 ϕ = cos − 1 ( R R clavus 2 + ( 1 2 π f C ) 2 ) Substitute 1100 kΩ for R clavus , 1

5th Edition

ISBN: 8220103026918

Author: Walker

Publisher: PEARSON

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Chapter 24, Problem 97PP

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The phase angle for the typical clavus sample.

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Chapter 24, Problem 96PP

Chapter 24, Problem 98PP

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The phase angle for the typical clavus sample.

Solution Summary: The author explains that the option (D) is the correct answer to determine the phase angle for the typical clavus sample.

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The phase angle for the typical clavus sample.

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Chapter 24 Solutions