
(a)
The unit of the equation is watts.
(a)

Answer to Problem 74P
The unit of the equation on the right hand side is watts.
Explanation of Solution
Given info: The equation of the
The formula to calculate the electromagnetic power is,
Here,
The dimension of
Substitute the dimensions
The dimension
Conclusion:
Therefore, the unit of the equation on the right hand side is watts.
(b)
The acceleration of the electron.
(b)

Answer to Problem 74P
The acceleration of the electron is
Explanation of Solution
Given info: The equation of the electromagnetic power is
The formula to calculate the acceleration is,
Here,
Substitute
Thus, the acceleration of the electron is
Conclusion:
Therefore, the acceleration of the electron is
(c)
The electromagnetic power
(c)

Answer to Problem 74P
The electromagnetic power radiated by the electron is
Explanation of Solution
Given info: The equation of the electromagnetic power is
The expression for the electromagnetic power is,
Substitute
Thus, the electromagnetic power radiated by the electron is
Conclusion:
Therefore, the electromagnetic power radiated by the electron is
(d)
The electromagnetic power of the proton leaving a cyclotron.
(d)

Answer to Problem 74P
The electromagnetic power of the proton leaving a cyclotron is
Explanation of Solution
Given info: The electric flux of the particle is
Given info: The equation of the electromagnetic power is
The formula to calculate the acceleration is,
Here,
Substitute
The expression for the electromagnetic power is,
Substitute
Conclusion:
Therefore, the electromagnetic power of the proton leaving a cyclotron is
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Chapter 24 Solutions
Bundle: Principles of Physics: A Calculus-Based Text, 5th + WebAssign Printed Access Card for Serway/Jewett's Principles of Physics: A Calculus-Based Text, 5th Edition, Multi-Term
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