EBK ORGANIC CHEMISTRY AS A SECOND LANGU
EBK ORGANIC CHEMISTRY AS A SECOND LANGU
3rd Edition
ISBN: 9781118203774
Author: Klein
Publisher: YUZU
Question
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Chapter 24, Problem 56PP

(a)

Interpretation Introduction

Interpretation:

Name for given compounds should be identified.

Concept introduction:

The Haworth projection: A Haworth projection is a three-dimensional representation of monosaccharides and the structural formula is inscription as a cyclic structures.

In Haworth projection, oxygen atom is placed in back right corner, CH2OH is arranged up at the C5 carbon atom because it is D form. Anomeric hydroxyl group is placed down if it is α-anomer which is trans to the CH2OH of C5 carbon. The remaining hydroxyl group is placed up if the hydroxyl group left side in Fischer projection. Hydroxyl group is placed down if the hydroxyl group right side in Fischer projection.

Fischer Projection: The orientation of the carbon atoms in a molecule is arranged vertically from top to bottom.

The C1 carbon is at the top of the orientation, the hydrogen and hydroxyl groups are placed in right and left side of the orientation. D and L form are depends on the arrangement of the hydroxyl group. If the hydroxyl group is in the right side of the molecule in the penultimate (next-to-last) carbon is called as D sugar, if the If the hydroxyl group is in the left side of the molecule in the penultimate (next-to-last) carbon is called as L sugar.

Pyranose: A six-member cyclic form of a monosaccharide is called as pyronose.

(b)

Interpretation Introduction

Interpretation:

Name for given compounds should be identified.

Concept introduction:

The Haworth projection: A Haworth projection is a three-dimensional representation of monosaccharides and the structural formula is inscription as a cyclic structures.

In Haworth projection, oxygen atom is placed in back right corner, CH2OH is arranged up at the C5 carbon atom because it is D form. Anomeric hydroxyl group is placed down if it is α-anomer which is trans to the CH2OH of C5 carbon. The remaining hydroxyl group is placed up if the hydroxyl group left side in Fischer projection. Hydroxyl group is placed down if the hydroxyl group right side in Fischer projection.

Fischer Projection: The orientation of the carbon atoms in a molecule is arranged vertically from top to bottom.

The C1 carbon is at the top of the orientation, the hydrogen and hydroxyl groups are placed in right and left side of the orientation. D and L form are depends on the arrangement of the hydroxyl group. If the hydroxyl group is in the right side of the molecule in the penultimate (next-to-last) carbon is called as D sugar, if the If the hydroxyl group is in the left side of the molecule in the penultimate (next-to-last) carbon is called as L sugar.

Pyranose: A six-member cyclic form of a monosaccharide is called as pyronose.

To find: Open chain form of given molecule.

(c)

Interpretation Introduction

Interpretation:

Name for given compounds should be identified.

Concept introduction:

The Haworth projection: A Haworth projection is a three-dimensional representation of monosaccharides and the structural formula is inscription as a cyclic structures.

In Haworth projection, oxygen atom is placed in back right corner, CH2OH is arranged up at the C5 carbon atom because it is D form. Anomeric hydroxyl group is placed down if it is α-anomer which is trans to the CH2OH of C5 carbon. The remaining hydroxyl group is placed up if the hydroxyl group left side in Fischer projection. Hydroxyl group is placed down if the hydroxyl group right side in Fischer projection.

Fischer Projection: The orientation of the carbon atoms in a molecule is arranged vertically from top to bottom.

The C1 carbon is at the top of the orientation, the hydrogen and hydroxyl groups are placed in right and left side of the orientation. D and L form are depends on the arrangement of the hydroxyl group. If the hydroxyl group is in the right side of the molecule in the penultimate (next-to-last) carbon is called as D sugar, if the If the hydroxyl group is in the left side of the molecule in the penultimate (next-to-last) carbon is called as L sugar.

Pyranose: A six-member cyclic form of a monosaccharide is called as pyronose.

To find: Open chain form of given molecule.

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3. SYNTHESIS. Propose a sequence of synthetic steps (FGI) that convert the starting material (SM) into the Target molecule. For each FGI in your proposed synthesis, specify the reagents / conditions, and draw the product(s) of that FGI. DO NOT INCLUDE the FGI mxn in the answer you submit. If an FGI requires two reagent sets, specify the order in which the reagent sets are added, e.g., i) Hg(OAc)2 / H₂O; ii) NaBH4/MeOH. Indicate the stereochemistry (if any) of the products of each FGI. FGI 1. Me Starting Material Source of all carbons in the Target molecule (can use multiple copies) Me Me Target molecule + enantiomer
curved arrows are used to illustate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction mechanism steps

Chapter 24 Solutions

EBK ORGANIC CHEMISTRY AS A SECOND LANGU

Ch. 24.5 - Prob. 10ATSCh. 24.5 - Prob. 11ATSCh. 24.5 - Prob. 2LTSCh. 24.5 - Prob. 12PTSCh. 24.5 - Prob. 13PTSCh. 24.5 - Prob. 14ATSCh. 24.5 - Prob. 15ATSCh. 24.5 - Prob. 3LTSCh. 24.5 - Prob. 16PTSCh. 24.5 - Prob. 17ATSCh. 24.5 - Prob. 18ATSCh. 24.5 - Prob. 19CCCh. 24.5 - Prob. 20CCCh. 24.5 - Prob. 21CCCh. 24.5 - Prob. 22CCCh. 24.6 - Prob. 23CCCh. 24.6 - Prob. 24CCCh. 24.6 - Prob. 25CCCh. 24.6 - Prob. 26CCCh. 24.6 - Prob. 27CCCh. 24.6 - Prob. 28CCCh. 24.6 - Prob. 29CCCh. 24.6 - Prob. 30CCCh. 24.6 - Prob. 4LTSCh. 24.6 - Prob. 31PTSCh. 24.6 - Prob. 32ATSCh. 24.6 - Prob. 33ATSCh. 24.6 - Prob. 34CCCh. 24.6 - Prob. 35CCCh. 24.6 - Prob. 36CCCh. 24.6 - Prob. 37CCCh. 24.6 - Prob. 38CCCh. 24.7 - Prob. 5LTSCh. 24.7 - Prob. 39PTSCh. 24.7 - Prob. 40ATSCh. 24.7 - Prob. 41CCCh. 24 - Prob. 42PPCh. 24 - Prob. 43PPCh. 24 - Prob. 44PPCh. 24 - Prob. 45PPCh. 24 - Prob. 46PPCh. 24 - Prob. 47PPCh. 24 - Prob. 48PPCh. 24 - Prob. 49PPCh. 24 - Prob. 50PPCh. 24 - Prob. 51PPCh. 24 - Prob. 52PPCh. 24 - Prob. 53PPCh. 24 - Prob. 54PPCh. 24 - Prob. 55PPCh. 24 - Prob. 56PPCh. 24 - Prob. 57PPCh. 24 - Prob. 58PPCh. 24 - Prob. 59PPCh. 24 - Prob. 60PPCh. 24 - Prob. 61PPCh. 24 - Prob. 62PPCh. 24 - Prob. 63PPCh. 24 - Prob. 64PPCh. 24 - Prob. 65PPCh. 24 - Prob. 66PPCh. 24 - Prob. 67PPCh. 24 - Prob. 68PPCh. 24 - Prob. 69PPCh. 24 - Prob. 70PPCh. 24 - Prob. 71PPCh. 24 - Prob. 72PPCh. 24 - Prob. 73PPCh. 24 - Prob. 74PPCh. 24 - Prob. 75PPCh. 24 - Prob. 76PPCh. 24 - Prob. 77PPCh. 24 - Prob. 78PPCh. 24 - Prob. 79PPCh. 24 - Prob. 80PPCh. 24 - Prob. 81IPCh. 24 - Prob. 82IPCh. 24 - Prob. 83IPCh. 24 - Prob. 84IPCh. 24 - Prob. 85IPCh. 24 - Prob. 86IPCh. 24 - Prob. 87CPCh. 24 - Prob. 88CPCh. 24 - Prob. 89CP
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