(a)
Interpretation:
The product and stereo isomer of product should be identified.
Concept introduction:
Aldopentose: A pentose is a monosaccharide with five carbon atoms. It has an
Stereoisomers: Stereoisomers are molecules that have the same molecular formula and they differ only in arrangement of atom in three-dimensional space.
Enantiomers: A compound which is non-superimposable mirror image is called enantiomers.
Diastereomers: A compound which is non-superimposable and non-mirror image is called diastereomers
Epimer: Epimer is one of a pair of stereoisomers. The two isomers differ in configuration at only one stereogenic center.
To find: Epimeric with D-arabinose at C2
(b)
Interpretation:
The product and stereo isomer of product should be identified.
Concept introduction:
Epimer: Epimer is one of a pair of stereoisomers. The two isomers differ in configuration at only one stereogenic center.
(c)
Interpretation:
The product and stereo isomer of product should be identified.
Concept introduction:
Enantiomers: A compound which is non-superimposable mirror image is called enantiomers.
To find: The enantiomer of D-ribose
(d)
Interpretation:
The product and stereo isomer of product should be identified.
Concept introduction:
Epimer: Epimer is one of a pair of stereoisomers. The two isomers differ in configuration at only one stereogenic center.
To find: The enantiomer of D-arabinose and C2 epimer of L-ribose.
(e)
Interpretation:
The product and stereo isomer of product should be identified.
Concept introduction:
Epimer: Epimer is one of a pair of stereoisomers. The two isomers differ in configuration at only one stereogenic center.
To find: Relationship between the D-ribose and D-lyxose.
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Chapter 24 Solutions
ORGANIC CHEMISTRY (LL) W/ACCESS
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- A mixture of C7H12O2, C9H9OCl, biphenyl and acetone was put together in a gas chromatography tube. Please decide from the GC resutls which correspond to the peak for C7,C9 and biphenyl and explain the reasoning based on GC results. Eliminate unnecessary peaks from Gas Chromatography results.arrow_forwardIs the molecule chiral, meso, or achiral? CI .CH3 H₂C CIarrow_forwardPLEASE HELP ! URGENT!arrow_forward
- Identify priority of the substituents: CH3arrow_forwardHow many chiral carbons are in the molecule? OH F CI Brarrow_forwardA mixture of three compounds Phen-A, Acet-B and Rin-C was analyzed using TLC with 1:9 ethanol: hexane as the mobile phase. The TLC plate showed three spots of R, 0.1 and 0.2 and 0.3. Which of the three compounds (Phen-A; Acet-B or Rin-C) would have the highest (Blank 1), middle (Blank 2) and lowest (Blank 3) spot respectively? 0 CH: 0 CH, 0 H.C OH H.CN OH Acet-B Rin-C phen-A A A <arrow_forward
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